---
title: "Brayton cycle working principle with P-v and T-s"
subject: "Fundamental of Thermodynamics & Heat Transfer"
chapter: 6
key: "semester_2/fundamental_of_thermodynamics_and_heat_transfer:brayton-cycle-working-principle"
source: https://www.bctengineer.com/q/semester_2/fundamental_of_thermodynamics_and_heat_transfer/brayton-cycle-working-principle
site: BCT Engineering
---

# Brayton cycle working principle with P-v and T-s

Fundamental of Thermodynamics & Heat Transfer · Chapter 6: Thermodynamic Cycles

- Asked in: 2074 Bhadra, 6 marks
- Video: [Brayton Cycle](https://www.youtube.com/watch?v=17-2uYI76k4) — TutorialsPoint
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_2/fundamental_of_thermodynamics_and_heat_transfer/brayton-cycle-working-principle
- Whole chapter: https://www.bctengineer.com/md/semester_2/fundamental_of_thermodynamics_and_heat_transfer/chapter-6

## Question

Explain the working principle of Brayton cycle with corresponding processes on P-v and T-s diagrams.

## Short answer

The Brayton cycle consists of isentropic compression, constant-pressure heat addition, isentropic expansion, and constant-pressure heat rejection. Air is compressed, heated in a combustor, expanded through a turbine, and exhausted. Net work output equals turbine work minus compressor work.

## Answer

The Brayton cycle is the ideal air-standard cycle for gas turbines and jet engines. Air, the working fluid, is compressed, heated at constant pressure and expanded in a turbine. The turbine produces more work than the compressor takes, and the difference is the net output.

```text
                 Fuel (Q_in)
                     |
                     v
          2   +-------------+   3
       +----->|  Combustor  |------+
       |      +-------------+      |
       |                           v
 [Compressor]=======shaft=======[Turbine]---> net work
       ^                           |
       | 1                       4 v
     Air in                     Exhaust
```

#### Processes
1. **1-2: Isentropic compression** in the compressor. Pressure and temperature rise; work is supplied.
2. **2-3: Constant-pressure heat addition** in the combustor (a heat exchanger in the ideal cycle). The temperature rises to the maximum, T₃.
3. **3-4: Isentropic expansion** in the turbine. Work is produced; part of it drives the compressor.
4. **4-1: Constant-pressure heat rejection** to the atmosphere (the hot exhaust cools to the inlet state).

```text
 P-v diagram                      T-s diagram
 P                                T
 |  2 ____________ 3              |               3
 |   \             \              |              /|
 |    \             \             |             / |
 |     '.            '.           |           /   |
 |       '.            '.         |    2 _.-'     |
 |         '-._          '-._     |    |          4
 |             '- 1 _________ 4   |    |       .-'
 |                                |    |   _.-'
 |                                |    1.-'
 +----------------------> v       +--------------------> s
 1-2 isentropic compression       2-3 constant-P heat addition
 3-4 isentropic expansion         4-1 constant-P heat rejection
```

#### Key results
- q_in = cp (T₃ − T₂), q_out = cp (T₄ − T₁)
- w_net = q_in − q_out
- η = 1 − 1/r_p^((γ−1)/γ), where r_p = P₂/P₁

A high pressure ratio gives high efficiency. The back-work ratio (compressor work/turbine work) is large, about 40-80 % for gas turbines.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Why does the Brayton cycle give net work?
   A. Heat rejection is zero
   B. Compressor work exceeds turbine work
   C. Turbine work exceeds compressor work
   D. Pump work is negligible
   Answer: C. Hot gas expands through the turbine giving more work than the compressor uses. (Key point: Net output)

2. Process 2-3 is:
   A. Constant-pressure heat addition
   B. Isothermal compression
   C. Isentropic expansion
   D. Constant-volume heat addition
   Answer: A. Fuel is burned in the combustor at constant pressure, raising T to T3. (Key point: Heat addition)

3. Process 4-1 is:
   A. Throttling
   B. Constant-pressure heat rejection to atmosphere
   C. Constant-volume rejection
   D. Isentropic compression
   Answer: B. Exhaust cools at constant pressure to the inlet state. (Key point: Process 4-1)

4. Efficiency of the ideal Brayton cycle rises with:
   A. Higher pressure ratio
   B. Lower pressure ratio
   C. Lower gamma only
   D. Larger air flow
   Answer: A. eta = 1 - 1/r_p^((g-1)/g). (Key point: Efficiency factor)

## Related in Fundamental of Thermodynamics & Heat Transfer

- [Ideal Brayton cycle: diagrams and efficiency](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Abrayton-cycle-efficiency-derivation) — Fundamental of Thermodynamics & Heat Transfer, chapter 6, asked 2×
- [Ideal diesel cycle working principle](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Adiesel-cycle-working-principle) — Fundamental of Thermodynamics & Heat Transfer, chapter 6
- [Rankine cycle working principle](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Arankine-cycle-working-principle) — Fundamental of Thermodynamics & Heat Transfer, chapter 6
- [Brayton cycle pressure ratio 12: mass flow for 90 MW](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Abrayton-pressure-ratio-12-90mw) — Fundamental of Thermodynamics & Heat Transfer, chapter 6
- [Ideal Brayton cycle with 30 MW heat input](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Abrayton-30mw-efficiency-power) — Fundamental of Thermodynamics & Heat Transfer, chapter 6, asked 2×
- [Ideal Brayton cycle: net work per kg and efficiency](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Abrayton-work-per-kg-efficiency) — Fundamental of Thermodynamics & Heat Transfer, chapter 6

## Related in other subjects

- [Combined cycle advantages and working principle](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Acombined-advantages-working) — Power Plant Equipment, chapter 8, asked 2×
- [Brayton cycle efficiency and optimum pressure ratio](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Abrayton-cycle-efficiency-optimum-pressure-ratio) — Turbo Machines, chapter 3
- [Brayton cycle; Atkinson and Stirling cycles](https://www.bctengineer.com/question.md?key=semester_6%2Finternal_combustion_engines%3Abrayton-cycle-atkinson-stirling-notes) — Internal Combustion Engines, chapter 1
- [Ideal Brayton cycle work and efficiency](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Aideal-brayton-numerical) — Turbo Machines, chapter 3
