---
title: "Range of PI gains Kp, KI for stability"
subject: "Control Systems"
chapter: 4
key: "semester_3/control_systems:pi-kp-ki-range-stable"
source: https://www.bctengineer.com/q/semester_3/control_systems/pi-kp-ki-range-stable
site: BCT Engineering
---

# Range of PI gains Kp, KI for stability

Control Systems · Chapter 4: Stability

- Asked in: 2073 Shrawan, 4 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/control_systems/pi-kp-ki-range-stable
- Whole chapter: https://www.bctengineer.com/md/semester_3/control_systems/chapter-4

## Question

For a closed loop system presented by the block diagram below, determine the range of controller gain (Kp, KI) so that the PI controller provides the stable output. [Figure: R → summing point (+, −) → PI controller (Kp + KI/s) → plant 1/[(s+1)(s+2)] → y; unity negative feedback from y]

## Short answer

The closed-loop characteristic equation is s³ + 3s² + (2+Kp)s + KI = 0. Routh array yields KI > 0 and 3(2+Kp) − KI > 0, giving KI < 3(Kp+2). The stability range is 0 < KI < 3(Kp+2) with Kp > −2.

## Answer

The PI controller $K_p + \frac{K_I}{s}$ adds a pole at the origin. Find the closed-loop characteristic equation and apply Routh's criterion.

#### Characteristic equation

$$
\begin{aligned}
G(s) &= \left(K_p + \frac{K_I}{s}\right)\frac{1}{(s+1)(s+2)} = \frac{K_ps + K_I}{s(s+1)(s+2)} \\
1+G(s) = 0 &\Rightarrow s(s^2+3s+2) + K_ps + K_I = 0 \\
&\Rightarrow s^3 + 3s^2 + (2+K_p)s + K_I = 0
\end{aligned}
$$

#### Routh array

| Row | Col 1 | Col 2 |
|---|---|---|
| $s^3$ | 1 | $2+K_p$ |
| $s^2$ | 3 | $K_I$ |
| $s^1$ | $\frac{3(2+K_p)-K_I}{3}$ | 0 |
| $s^0$ | $K_I$ | |

#### Conditions for stability

- $s^0$ row: $K_I > 0$
- $s^1$ row: $3(2+K_p) - K_I > 0 \Rightarrow K_I < 3(K_p+2)$
- This also requires $K_p > -2$.

$$
0 < K_I < 3(K_p + 2)
$$

**Example:** with $K_p = 1$, the integral gain must satisfy $0 < K_I < 9$; with $K_p = 4$, $0 < K_I < 18$. A larger $K_p$ allows a larger $K_I$.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. The PI controller Kp + KI/s adds
   A. A zero at the origin only
   B. A pole at s = -1
   C. No poles
   D. A pole at the origin
   Answer: D. The 1/s term introduces a pole at the origin, making the loop type 1. (Key point: Effect of PI)

2. The characteristic equation is
   A. s^3+3s^2+(2+Kp)s+KI=0
   B. s^3+3s^2+2s+KpKI=0
   C. s^2+3s+2+Kp+KI=0
   D. s^3+3s^2+(2+KI)s+Kp=0
   Answer: A. s(s+1)(s+2)+Kp s+KI. (Key point: Characteristic equation)

3. The s^1 row condition gives
   A. KI > 3(Kp+2)
   B. KI < 3(Kp+2)
   C. KI < Kp+2
   D. KI < 3Kp
   Answer: B. 3(2+Kp) - KI > 0. (Key point: Upper limit)

4. The stable range is
   A. KI > 3(Kp+2)
   B. 0 < KI < Kp
   C. 0 < KI < 3(Kp+2)
   D. KI < 0
   Answer: C. Combining KI>0 (s^0) and KI<3(Kp+2) (s^1). (Key point: Final range)

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