---
title: "Relative stability using R-H criterion"
subject: "Control Systems"
chapter: 4
key: "semester_3/control_systems:rh-relative-stability"
source: https://www.bctengineer.com/q/semester_3/control_systems/rh-relative-stability
site: BCT Engineering
---

# Relative stability using R-H criterion

Control Systems · Chapter 4: Stability

- Asked in: 2074 Chaitra, 3 marks; 2072 Chaitra, 4 marks (asked 2 times)
- Video: [Relative Stability Analysis](https://www.youtube.com/watch?v=jUX-3XIyH2E) — TutorialsPoint
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/control_systems/rh-relative-stability
- Whole chapter: https://www.bctengineer.com/md/semester_3/control_systems/chapter-4

## Question

Explain how RH (Routh Hurwitz) method is used for determining relative stability.

## Short answer

Relative stability is checked by shifting the imaginary axis: substitute s = z − σ into the characteristic equation. Apply Routh–Hurwitz to the new polynomial in z. If the first column has no sign changes, all closed-loop poles lie to the left of s = −σ, guaranteeing a minimum decay rate.

## Answer

**Relative stability** tells how far the closed-loop poles lie to the left of the imaginary axis, i.e. how stable a stable system is. The basic Routh–Hurwitz test only checks for poles on or to the right of the $j\omega$ axis. To find out whether all roots lie to the left of a line $s=-\sigma$, the axis is shifted.

#### Method (axis shifting)

1. Take the characteristic equation $q(s)=0$.
2. Substitute $s = z - \sigma$, where $\sigma>0$ is the required margin. This moves the vertical line $s=-\sigma$ to the new imaginary axis ($z=0$).
3. Expand to get a polynomial $q(z)$.
4. Form the Routh array of $q(z)$.
   - Number of sign changes = number of roots to the **right** of $s=-\sigma$.
   - No sign change: all roots lie to the left of $s=-\sigma$, so every root has a real part more negative than $-\sigma$. Each mode then decays at least as fast as $e^{-\sigma t}$.
   - A zero row (or a zero constant term): some roots lie exactly on the line $s=-\sigma$.
5. Repeat for other $\sigma$ values, or keep $\sigma$ (or a gain $K$) as a variable to find the limit.

```text
         jw'          jw
          |           |    jw' = new axis (z = 0)
     x    |           |
       x  |           |    Shift: s = z - sigma
   -------+-----------+--------> sigma
     x  -sigma        0
          |           |
```

#### Example

$q(s)=s^3+6s^2+11s+6$ (roots $-1, -2, -3$). Check whether all roots lie to the left of $s=-0.5$. Put $s=z-0.5$:

$$
q(z) = z^3 + 4.5z^2 + 5.75z + 1.875
$$

| Row | Col 1 | Col 2 |
|---|---|---|
| $z^3$ | 1 | 5.75 |
| $z^2$ | 4.5 | 1.875 |
| $z^1$ | 5.333 | |
| $z^0$ | 1.875 | |

No sign change, so all roots lie to the left of $s=-0.5$. With $s=z-1$, $q(z) = z^3+3z^2+2z$; the constant term becomes zero, showing a root exactly at $s=-1$.

#### Uses

- Ensures a minimum decay rate, i.e. a settling time of about $t_s \approx 4/\sigma$ or less.
- Lets the designer find the range of gain $K$ that keeps all poles to the left of a chosen line.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Relative stability measures
   A. How far the closed-loop poles lie to the left of the imaginary axis
   B. Whether the system has zeros
   C. The number of poles
   D. The gain at zero frequency
   Answer: A. It tells how stable a stable system is, i.e. the distance of poles into the LHP. (Key point: Meaning of relative stability)

2. To test whether all roots lie left of s = -sigma, substitute
   A. s = z + sigma
   B. s = z - sigma
   C. s = sigma*z
   D. s = 1/z
   Answer: B. With s = z - sigma the line s = -sigma becomes the new imaginary axis z = 0. (Key point: Axis shift)

3. In the Routh array of q(z), the sign changes equal
   A. Roots on the imaginary axis
   B. Roots left of s = -sigma
   C. Roots to the right of s = -sigma
   D. Number of zeros
   Answer: C. Sign changes count the roots in the right half of the z-plane, i.e. right of s = -sigma. (Key point: Interpreting sign changes)

4. In the shifted array, an all-zero row means
   A. All roots are real
   B. The system is unstable
   C. sigma is too small
   D. Roots lie exactly on the line s = -sigma
   Answer: D. Imaginary-axis roots in z correspond to roots on s = -sigma. (Key point: Zero row meaning)

## Related in Control Systems

- [Relative stability from Bode plot](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Abode-relative-stability) — Control Systems, chapter 6
- [Short note: Nyquist stability criterion](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Ashort-nyquist-criterion) — Control Systems, chapter 6
- [Relative and absolute stability; R-H of s⁵+s⁴+2s³+2s²+3s+5](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Arh-relative-absolute-s5) — Control Systems, chapter 4, asked 2×
- [Relative and absolute stability; R-H of s⁶+2s⁵+8s⁴+12s³+20s²+16s+16](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Arh-relative-absolute-s6) — Control Systems, chapter 4, asked 2×
- [R-H relation between K and T for stability](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Arh-k-t-relation) — Control Systems, chapter 4
- [R-H stability of s⁵+2s⁴+2s³+4s²+s+2](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Arh-s5-2-2-4-1) — Control Systems, chapter 4

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