---
title: "Transfer function from third-order state model"
subject: "Control Systems"
chapter: 8
key: "semester_3/control_systems:ss-tf-3x3-1-2-3"
source: https://www.bctengineer.com/q/semester_3/control_systems/ss-tf-3x3-1-2-3
site: BCT Engineering
---

# Transfer function from third-order state model

Control Systems · Chapter 8: State Space Analysis

- Asked in: 2078 Bhadra, 6+2 marks; 2071 Shrawan, 8 marks (asked 2 times)
- Video: [Transfer Function Derivation from State Model Statement Problem No  4 - Control Systems](https://www.youtube.com/watch?v=n_spUERHzP8) — Ekeeda
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/control_systems/ss-tf-3x3-1-2-3
- Whole chapter: https://www.bctengineer.com/md/semester_3/control_systems/chapter-8

## Question

For given state equation and output equation, find transfer function Y(s)/U(s). Ẋ = [0 1 0; 0 0 1; −1 −2 −3]X + [10; 0; 0]u and y = [1 0 0]X

## Short answer

The transfer function is Y(s)/U(s) = 10(s^2+3s+2)/(s^3+3s^2+2s+1), found from C adj(sI-A)B / det(sI-A).

## Answer

For $\dot{x} = Ax + Bu$, $y = Cx + Du$:

$$
\frac{Y(s)}{U(s)} = C(sI - A)^{-1}B + D = \frac{C\,\operatorname{adj}(sI-A)\,B}{|sI-A|} + D
$$

$$
A = \begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ -1 & -2 & -3 \end{bmatrix},\quad B = \begin{bmatrix} 10 \\ 0 \\ 0 \end{bmatrix},\quad C = \begin{bmatrix} 1 & 0 & 0 \end{bmatrix},\quad D = 0
$$

#### Step 1: $sI - A$ and its determinant

$$
sI - A = \begin{bmatrix} s & -1 & 0 \\ 0 & s & -1 \\ 1 & 2 & s+3 \end{bmatrix}
$$

$$
\begin{aligned}
|sI - A| &= s\left[s(s+3) + 2\right] - (-1)\left[0\cdot(s+3) - (-1)(1)\right] + 0 \\
&= s^3 + 3s^2 + 2s + 1
\end{aligned}
$$

#### Step 2: Required part of the adjoint
Because $B$ has only its first element non-zero and $C$ picks only the first row, only the (1,1) element of the adjoint is needed:

$$
\operatorname{adj}(sI-A)_{11} = \begin{vmatrix} s & -1 \\ 2 & s+3 \end{vmatrix} = s^2 + 3s + 2
$$

Full first column of the adjoint: $\begin{bmatrix} s^2+3s+2 \\ -1 \\ -s \end{bmatrix}$, so

$$
\operatorname{adj}(sI-A)B = 10\begin{bmatrix} s^2+3s+2 \\ -1 \\ -s \end{bmatrix}
$$

#### Step 3: Transfer function

$$
C\,\operatorname{adj}(sI-A)B = 10(s^2 + 3s + 2)
$$

$$
\frac{Y(s)}{U(s)} = \frac{10(s^2+3s+2)}{s^3+3s^2+2s+1} = \frac{10(s+1)(s+2)}{s^3+3s^2+2s+1}
$$

#### Stability check
Routh array for $s^3 + 3s^2 + 2s + 1$:

| Row | | |
|---|---|---|
| $s^3$ | 1 | 2 |
| $s^2$ | 3 | 1 |
| $s^1$ | $\frac{3\times2 - 1}{3} = 1.67$ | 0 |
| $s^0$ | 1 | |

No sign change, so the system is stable. The poles are $-2.325$ and $-0.338 \pm j0.562$; the zeros are $-1$ and $-2$.

**Answer:** $\dfrac{Y(s)}{U(s)} = \dfrac{10(s^2+3s+2)}{s^3+3s^2+2s+1}$.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. In Y/U = C adj(sI - A) B / |sI - A| + D, what does the denominator represent?
   A. The determinant of B
   B. The characteristic polynomial |sI - A|
   C. The product C B
   D. The adjoint of A
   Answer: B. The denominator is |sI - A|, whose roots are the poles. (Key point: Transfer function from a state model)

2. For the companion matrix with last row [-1 -2 -3], what is |sI - A|?
   A. s^3 - 3s^2 - 2s - 1
   B. s^3 + s^2 + 2s + 3
   C. s^3 + 3s^2 + 2s + 1
   D. s^3 + 3s^2 + 2s - 1
   Answer: C. For a companion form the last row gives the coefficients directly: s^3 + 3s^2 + 2s + 1. (Key point: Determinant of 3x3)

3. Why is only adj(sI - A)_11 needed here?
   A. Because the matrix is symmetric
   B. Because D = 0 removes other elements
   C. Because the other elements are always zero
   D. B has only its first element non-zero and C picks only the first row
   Answer: D. C adj B reduces to C1 * adj_11 * B1 when only the first entries of C and B are non-zero. (Key point: Which adjoint element is needed)

4. What is Y(s)/U(s)?
   A. 10(s^2 + 3s + 2)/(s^3 + 3s^2 + 2s + 1)
   B. 10/(s^3 + 3s^2 + 2s + 1)
   C. (s^2 + 3s + 2)/(s^3 + 3s^2 + 2s + 1)
   D. 10 s/(s^3 + 3s^2 + 2s + 1)
   Answer: A. adj_11 = s^2 + 3s + 2 and B1 = 10 give numerator 10(s^2 + 3s + 2). (Key point: Final transfer function)

## Close variants set in other exams

- [Transfer function, poles and zeros from 3×3 state model](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Ass-tf-poles-zeros-3x3) — Control Systems, chapter 8, asked 3×

## Related in Control Systems

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- [Transfer function from state equations, output x2](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Atf-from-de-3x1-x2-y) — Control Systems, chapter 8, asked 2×
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