---
title: "Two-mass system X2/F with F-V and F-I analogy (D3)"
subject: "Control Systems"
chapter: 2
key: "semester_3/control_systems:tf-fv-fi-m1-m2-2"
source: https://www.bctengineer.com/q/semester_3/control_systems/tf-fv-fi-m1-m2-2
site: BCT Engineering
---

# Two-mass system X2/F with F-V and F-I analogy (D3)

Control Systems · Chapter 2: Component Modeling

- Asked in: 2071 Shrawan, 8 marks
- Video: [2.Force Current and Force Voltage Analogy solved problem with system equation](https://www.youtube.com/watch?v=jgCfYudsIFY) — ELECTRICAL HUB
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/control_systems/tf-fv-fi-m1-m2-2
- Whole chapter: https://www.bctengineer.com/md/semester_3/control_systems/chapter-2

## Question

Find the transfer function X2(s)/F(s) for the mechanical system of figure below. Also draw the F-V and F-I analogy circuit of the system. [Figure: wall – spring K1 – mass M1 (force F(t) applied, displacement x1(t), friction D1 with ground); M1 connected to mass M2 (displacement x2(t), friction D2 with ground) through spring K2 in parallel with damper D3; M2 – spring K3 – wall]

## Short answer

X2(s)/F(s) = (D3 s + K2) / Δ, with Δ = [M1s^2+(D1+D3)s+K1+K2][M2s^2+(D2+D3)s+K2+K3] - (D3s+K2)^2. The F-V analogy maps force to voltage, mass to inductance, damper to resistance, spring to 1/capacitance; the F-I analogy maps force to current, mass to capacitance, damper to 1/resistance, spring to 1/inductance.

## Answer

Displacements $x_1$ ($M_1$, force $F$, ground friction $D_1$) and $x_2$ ($M_2$, ground friction $D_2$). $K_1$ ties $M_1$ to the left wall, $K_3$ ties $M_2$ to the right wall, and $K_2 \parallel D_3$ couples them.

#### Equations of motion (Laplace)
$$
\begin{aligned}
\left[M_1s^2 + (D_1 + D_3)s + K_1 + K_2\right]X_1 - (D_3s + K_2)X_2 &= F \\
-(D_3s + K_2)X_1 + \left[M_2s^2 + (D_2 + D_3)s + K_2 + K_3\right]X_2 &= 0
\end{aligned}
$$
(Sum of impedances at each mass on the diagonal; coupling impedance off the diagonal.)

#### Transfer function
$$
\frac{X_2(s)}{F(s)} = \frac{D_3s + K_2}{\Delta}
$$
$$
\Delta = \left[M_1s^2 + (D_1+D_3)s + K_1 + K_2\right]\left[M_2s^2 + (D_2+D_3)s + K_2 + K_3\right] - (D_3s + K_2)^2
$$
Expanded:
$$
\begin{aligned}
\Delta =\; & M_1M_2s^4 + \left[D_1M_2 + D_2M_1 + D_3(M_1 + M_2)\right]s^3 \\
& + \left[D_1D_2 + D_1D_3 + D_2D_3 + M_1(K_2 + K_3) + M_2(K_1 + K_2)\right]s^2 \\
& + \left[D_1(K_2 + K_3) + D_2(K_1 + K_2) + D_3(K_1 + K_3)\right]s \\
& + K_1K_2 + K_1K_3 + K_2K_3
\end{aligned}
$$

#### F-V analogy (mesh)
$F\to e$, $M\to L$, $D\to R$, $K\to 1/C$, velocity $\to$ current.
```text
  L1=M1 R=D1  C=1/K1        L2=M2 R=D2  C=1/K3
 +-LLLL-/\/\--||---+-------+-LLLL-/\/\--||---+
 |                 |                         |
(~) e           R3 = D3                      |
 |                 |                         |
 |    i1        C2 = 1/K2         i2         |
 +-----------------+-------------------------+
```

#### F-I analogy (node)
$F\to i$, $M\to C$, $D\to 1/R$, $K\to 1/L$, velocity $\to$ voltage.
```text
 v1                   L2∥R3      v2
 +----+----+----+---+--LLLL--+---+----+----+
 |    |    |    |   +-/\/\/--+   |    |    |
(i)   C1   R1   L1               C2   R2   L3
 |    |    |    |                |    |    |
 +----+----+----+----------------+----+----+ gnd
```
($C_1 = M_1$, $R_1 = 1/D_1$, $L_1 = 1/K_1$; $L_2 = 1/K_2$ in parallel with $R_3 = 1/D_3$; $C_2 = M_2$, $R_2 = 1/D_2$, $L_3 = 1/K_3$.)
The mesh (F-V) and node (F-I) equations have exactly the same form as the two mechanical equations above.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. In the Laplace equation for M1, what is the coefficient of X1?
   A. M1 s^2 + D1 s + K1
   B. M1 s^2 + (D1 + D3) s + K1 + K2
   C. M1 s^2 + (D1 + D3) s + K1
   D. M1 s^2 + D3 s + K2
   Answer: B. The diagonal term is the sum of all impedances attached to M1: its inertia, D1, K1 and the coupling pair K2 and D3. (Key point: Mass equation diagonal term)

2. What appears as the off-diagonal (coupling) term between the two equations?
   A. M2 s^2 + K3
   B. D3 s + K2
   C. D1 + D2
   D. K1 + K3
   Answer: B. K2 in parallel with D3 joins the masses, so their combined impedance D3 s + K2 is the coupling term, with a negative sign. (Key point: Coupling impedance)

3. Why is the numerator of X2(s)/F(s) equal to D3 s + K2?
   A. Force passes from M1 to M2 only through the K2 || D3 coupling
   B. F acts directly on M2
   C. It is the sum of all spring constants
   D. It equals the determinant of the system
   Answer: A. By Cramer's rule, X2 = (coupling term x F) / determinant, since F acts on M1 and reaches M2 only through the coupling. (Key point: Numerator of X2/F)

4. In the F-V analogy used here, what do mass, spring and damper become?
   A. Capacitance, inductance, conductance
   B. Inductance, 1/C (elastance), resistance
   C. Resistance, inductance, capacitance
   D. Inductance, resistance, 1/L
   Answer: B. F to e, M to L, D to R, K to 1/C, and velocity to current. (Key point: F-V analogy rules)

## Close variants set in other exams

- [Three-mass system X2/F with F-V and F-I analogy](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Atf-fv-fi-three-mass) — Control Systems, chapter 2, asked 3×
- [Two-mass system X2/F with F-V analogy](https://www.bctengineer.com/question.md?key=semester_3%2Fcontrol_systems%3Atf-fv-m1-m2-k1k2-b1b2b3) — Control Systems, chapter 2, asked 3×

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