---
title: "Fermi level with 10¹⁷ Sb then further doping"
subject: "Electrical Engineering Material"
chapter: 6
key: "semester_3/electrical_engineering_material:antimony-1e17-fermi-shift"
source: https://www.bctengineer.com/q/semester_3/electrical_engineering_material/antimony-1e17-fermi-shift
site: BCT Engineering
---

# Fermi level with 10¹⁷ Sb then further doping

Electrical Engineering Material · Chapter 6: Semiconductors

- Asked in: 2080 Baisakh, 8 marks
- Video: [Fermi level and effect of doping on Fermi level  IN JUST 5 MINUTES](https://www.youtube.com/watch?v=gRHzR4X_RWc) — Learning on the way!
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/electrical_engineering_material/antimony-1e17-fermi-shift
- Whole chapter: https://www.bctengineer.com/md/semester_3/electrical_engineering_material/chapter-6

## Question

An n-type silicon wafer is uniformly doped with 10¹⁷ antimony per cm³. Where will the Fermi level compared to its intrinsic Fermi level? Where will the Fermi level be shifted if the sample is further doped with 2×10¹⁶ atoms per cm³?

## Short answer

With 10¹⁷ Sb/cm³, n ≈ Nd, EF – EFi = 0.407 eV above intrinsic level. Further doping with 2×10¹⁶ acceptors compensates, leaving n = 8×10¹⁶ cm⁻³; EF – EFi = 0.401 eV, shifting down by 0.006 eV but still above EFi.

## Answer

Antimony (group V) is a donor, so the wafer is n-type and the Fermi level $E_{Fn}$ lies **above** the intrinsic level $E_{Fi}$. For a non-degenerate semiconductor $n = n_i\,e^{(E_{Fn}-E_{Fi})/kT}$, so

$$
E_{Fn}-E_{Fi} = kT\ln\frac{n}{n_i}
$$

**Data used (Si, 300 K):** $n_i = 1.45\times10^{10}\ \text{cm}^{-3}$, $kT = 8.617\times10^{-5}\times300 = 0.02585\ \text{eV}$, $\mu_e = 1350$, $\mu_h = 450\ \text{cm}^2\text{V}^{-1}\text{s}^{-1}$, $e = 1.6\times10^{-19}\ \text{C}$.

#### Case 1: $N_d = 10^{17}\ \text{cm}^{-3}$ antimony

At room temperature all donors are ionised and $N_d \gg n_i$, so $n \approx N_d = 10^{17}\ \text{cm}^{-3}$.

$$
\begin{aligned}
E_{Fn}-E_{Fi} &= 0.02585\ln\frac{10^{17}}{1.45\times10^{10}} \\
&= 0.02585\times15.75 = 0.407\ \text{eV}
\end{aligned}
$$

**Answer: the Fermi level is 0.407 eV above $E_{Fi}$.**

#### Case 2: further doped with $2\times10^{16}\ \text{cm}^{-3}$ atoms

The type of the second dopant is not printed; the usual reading is that it is an **acceptor (e.g. boron)**, $N_a = 2\times10^{16}\ \text{cm}^{-3}$. The acceptors capture an equal number of the donated electrons (compensation):

$$
n = N_d - N_a = 10^{17} - 2\times10^{16} = 8\times10^{16}\ \text{cm}^{-3}
$$

$$
\begin{aligned}
E_{Fn}-E_{Fi} &= 0.02585\ln\frac{8\times10^{16}}{1.45\times10^{10}} \\
&= 0.401\ \text{eV}
\end{aligned}
$$

**Answer: the Fermi level is still above $E_{Fi}$, now 0.401 eV above it, i.e. it moves down by about 0.006 eV towards $E_{Fi}$.** The sample stays n-type because $N_d > N_a$.

(If the extra $2\times10^{16}$ atoms were more antimony, $n = 1.2\times10^{17}$ and $E_F - E_{Fi} = 0.412$ eV, a shift of 0.005 eV upward.)

```text
 Ec ---------------------------
 EFn ......... (0.407 eV) 1st
 EFn ......... (0.401 eV) 2nd
 EFi - - - - - - - - - - - - -
 Ev ---------------------------
```

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Why does antimony put E_F above E_Fi?
   A. It is a group V donor, so electrons are the majority carriers
   B. It is a group III acceptor
   C. It reduces the band gap
   D. It adds holes
   Answer: A. Donors raise n above ni and so raise E_F. (Key point: Dopant type)

2. What is E_F - E_Fi for Nd = 10^17 cm^-3?
   A. About 0.407 eV below E_Fi
   B. About 0.407 eV above E_Fi
   C. About 0.348 eV above E_Fi
   D. About 0.55 eV above E_Fi
   Answer: B. 0.02585 x ln(10^17/1.45x10^10) = 0.02585 x 15.75 = 0.407 eV. (Key point: Case 1 value)

3. If the added 2x10^16 atoms are acceptors, what is n?
   A. n = 1.2x10^17 cm^-3
   B. n = 2x10^16 cm^-3
   C. n = Nd - Na = 8x10^16 cm^-3
   D. n = 10^17 cm^-3 unchanged
   Answer: C. Acceptors capture an equal number of donor electrons. (Key point: Compensation)

4. What happens to the Fermi level after the acceptor doping?
   A. It crosses below E_Fi, making the sample p-type
   B. It moves up by 0.1 eV
   C. It moves to mid-gap exactly
   D. It stays above E_Fi at 0.401 eV, moving down about 0.006 eV, still n-type
   Answer: D. Nd > Na so the sample is still n-type, only slightly less so. (Key point: Shift)

## Close variants set in other exams

- [Fermi level with 10¹⁶ Sb then 2×10¹⁷ B](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aantimony-1e16-boron-2e17) — Electrical Engineering Material, chapter 6, asked 6×
- [Fermi level with 10¹⁰ Sb then 2×10¹⁵ B](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aantimony-1e10-boron-2e15) — Electrical Engineering Material, chapter 6, asked 6×
- [Fermi level with 10¹⁶ B then 10¹⁷ Sb](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aboron-1e16-antimony-1e17) — Electrical Engineering Material, chapter 6, asked 5×
- [Fermi level of Si with 10¹⁶ Sb](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aantimony-1e16-fermi) — Electrical Engineering Material, chapter 6, asked 5×

## Related in Electrical Engineering Material

- [Si with 10¹⁵ Sb: carriers, resistance, Fermi level](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aantimony-1e15-resistance-fermi) — Electrical Engineering Material, chapter 6
- [Fermi level shift with As then B](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Aarsenic-1e15-fermi-shift) — Electrical Engineering Material, chapter 6, asked 2×
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- [Si crystal resistance with As then B doping](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Asi-arsenic-boron-resistance) — Electrical Engineering Material, chapter 6
- [Doping to raise Fermi level by 0.7 eV](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Araise-fermi-0-7ev) — Electrical Engineering Material, chapter 6, asked 2×
- [Resistance of Si cube doped with Sb](https://www.bctengineer.com/question.md?key=semester_3%2Felectrical_engineering_material%3Asi-cube-antimony) — Electrical Engineering Material, chapter 6
