---
title: "Applications of LC oscillators; Colpitts oscillator"
subject: "Electronics Devices and Circuit"
chapter: 5
key: "semester_3/electronics_devices_and_circuit:colpitts-oscillator-applications"
source: https://www.bctengineer.com/q/semester_3/electronics_devices_and_circuit/colpitts-oscillator-applications
site: BCT Engineering
---

# Applications of LC oscillators; Colpitts oscillator

Electronics Devices and Circuit · Chapter 5: Signal Generator and Waveform-Shaping Circuits

- Asked in: 2070 Chaitra, 6 marks
- Video: [Colpitts Oscillator Explained](https://www.youtube.com/watch?v=1fgw-ONlAcc) — ALL ABOUT ELECTRONICS
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/electronics_devices_and_circuit/colpitts-oscillator-applications
- Whole chapter: https://www.bctengineer.com/md/semester_3/electronics_devices_and_circuit/chapter-5

## Question

Write the applications of tuned LC oscillators. Draw the Colpitt's oscillator circuit and derive the expression for frequency of oscillation.

## Short answer

Tuned LC oscillators are used as local oscillators in receivers, carrier sources in transmitters, in RF signal generators, frequency synthesizers, and induction heating. The Colpitts oscillator uses a capacitive divider (C1, C2) across an inductor; frequency f = 1/(2pi sqrt(L C1C2/(C1+C2))).

## Answer

#### Applications of tuned LC oscillators
- Generating the local oscillator signal in radio, TV and communication receivers (superheterodyne).
- Carrier generation in transmitters (AM and FM), with a varactor for frequency modulation.
- RF signal generators and test equipment.
- Frequency synthesizers and phase-locked loops (VCO stage).
- Mixers and frequency converters in cell phones, wireless devices and radar.
- Induction heating and metal detectors.

LC oscillators are used at radio frequencies (from about 100 kHz to a few hundred MHz). RC oscillators are used at audio frequencies, because the L and C values would be too large at low frequencies.

#### Colpitts oscillator circuit (BJT, common emitter)
```text
                 +VCC
                  |
        +---------+
        |         |
      [R1]      [RFC]
        |         |
        |         +----||---+---------+
        |         |    Cc2  |         |
        |         C        [C1]       |
  +-----+------B--|  Q1     |        [L]
  |     |         E        GND        |
  |   [R2]        |         |         |
  |     |       [RE]||[CE] [C2]       |
  |    GND        |         |         |
  |              GND        |         |
  |                         |         |
  +---------||--------------+---------+
            Cc1
```

The collector is coupled through Cc2 to the top of the tank. C1 runs from the top of the tank to ground, C2 from ground to the bottom of the tank, and L is across the whole C1-C2 series combination. The bottom of the tank is coupled back to the base through Cc1. The output is taken from the collector (or the tank).

Tank connections in a simple form:

```text
 Collector o----+------+
                |      |
               [C1]    |
                |     [L]
 Emitter/GND o--+      |
                |      |
               [C2]    |
                |      |
 Base        o--+------+
```

C1 is between collector and ground, C2 between base and ground (emitter), and L is across the series combination. Bias: voltage divider R1, R2; emitter resistor RE with bypass capacitor CE; RF choke in the collector supply.

#### Derivation of frequency
Neglecting loading by the transistor (hie, hoe), the tank is L in parallel with the series combination of C1 and C2:

Ceq = C1 C2 / (C1 + C2)

At resonance the inductive and capacitive reactances are equal: ωL = 1/(ω Ceq)

**f = 1 / (2π √(L Ceq)) = 1 / (2π √( L C1 C2 / (C1 + C2) ))**

(A more exact derivation using the h-parameter model gives the same frequency when the transistor loading is negligible.)

**Condition for oscillation:** with Aβ ≥ 1 and β = C1/C2, the transistor gain must satisfy

hfe ≥ C2/C1

**Example:** L = 100 µH, C1 = 1 nF, C2 = 1 nF: Ceq = 0.5 nF; f = 1/(2π√(100×10⁻⁶ × 0.5×10⁻⁹)) = 712 kHz.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Which is a typical application of tuned LC oscillators?
   A. Local oscillator in superheterodyne receivers
   B. Audio frequency generation at 50 Hz
   C. DC power supply regulation
   D. Digital counting
   Answer: A. LC oscillators are used at RF, e.g. as receiver local oscillators and transmitter carriers. (Key point: Applications)

2. Why are RC oscillators used at audio frequencies rather than LC?
   A. An LC would be too large at low frequency
   B. RC is more stable at RF
   C. LC cannot oscillate
   D. RC has higher Q
   Answer: A. Low frequencies need very large L and C. (Key point: LC vs RC range)

3. What is the Colpitts frequency?
   A. 1/(2π√(L(C1 + C2)))
   B. 1/(2π√(L C1C2/(C1 + C2)))
   C. 1/(2π√6 RC)
   D. 1/(2π√((L1 + L2)C))
   Answer: B. C1 and C2 act in series across L. (Key point: Colpitts frequency)

4. L = 100 µH, C1 = C2 = 1 nF. What is f approximately?
   A. 712 kHz
   B. 503 kHz
   C. 159 kHz
   D. 7.12 MHz
   Answer: A. Ceq = 0.5 nF, f = 1/(2π√(5x10^-14)) = 712 kHz. (Key point: Numerical)

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