---
title: "Depletion MOSFET Q-points (IDSS 10 mA, VP -4 V)"
subject: "Electronics Devices and Circuit"
chapter: 3
key: "semester_3/electronics_devices_and_circuit:depletion-mosfet-qpoints"
source: https://www.bctengineer.com/q/semester_3/electronics_devices_and_circuit/depletion-mosfet-qpoints
site: BCT Engineering
---

# Depletion MOSFET Q-points (IDSS 10 mA, VP -4 V)

Electronics Devices and Circuit · Chapter 3: Field-Effect Transistor

- Asked in: 2082 Baisakh, 8 marks
- Video: [Electronics Basics #26 | Depletion MOSFET DC Analysis: Voltage-Divider Bias](https://www.youtube.com/watch?v=IJ1OX3K92MA) — AcEdumy EN | EngineeringENG
- Page: https://www.bctengineer.com/q/semester_3/electronics_devices_and_circuit/depletion-mosfet-qpoints
- Whole chapter: https://www.bctengineer.com/md/semester_3/electronics_devices_and_circuit/chapter-3

## Question

The depletion type N channel MOSFET has IDSS= 10 mA and Vp= -4V. [Figure: n-channel depletion MOSFET with drain resistor RD from +VDD to drain, gate resistor RG from gate to -VGG, source grounded, signal Vin through coupling capacitor C to the gate, output Vout at the drain]
a) Find the quiescent values of ID and VDS when VGS = -1V
b) Repeat when VGS = +2V
c) Which, if either, of these Q-points is in pinch off region?
d) At which, if either, of these Q-points is the device operating in enhancement mode

## Short answer

Assuming VDD = 20 V, RD = 500 Ω. For VGS = –1 V: ID = 5.625 mA, VDS = 17.19 V. For VGS = +2 V: ID = 22.5 mA, VDS = 8.75 V. Both Q-points have VDS > VGS – VP, so both are in pinch-off. Only VGS = +2 V (ID > IDSS) is enhancement mode.

## Answer

The n-channel depletion MOSFET is biased by a negative gate supply -VGG (through RG, with no gate current, so VGS is set directly by the supply). The drain current follows the same equation as a JFET, but VGS may also be positive.

```text
ID = IDSS (1 - VGS/VP)² ,     VDS = VDD - ID RD
```
IDSS = 10 mA, VP = -4 V. VDD and RD are not given in the question, so VDS is shown as a formula and then evaluated for an assumed VDD = 20 V and RD = 500 Ω (assumption).

#### a) VGS = -1 V
```text
ID = 10 (1 - (-1)/(-4))² = 10 (1 - 0.25)² = 10 × 0.5625 = 5.625 mA
VDS = VDD - ID RD = 20 - 5.625 mA × 0.5 kΩ = 17.19 V
```

#### b) VGS = +2 V
```text
ID = 10 (1 - 2/(-4))² = 10 (1 + 0.5)² = 10 × 2.25 = 22.5 mA
VDS = 20 - 22.5 mA × 0.5 kΩ = 8.75 V
```

#### c) Pinch-off (saturation) region
The condition for pinch-off operation is VDS ≥ VGS - VP (= VGS + 4 V).
- (a) VGS - VP = -1 + 4 = 3 V; VDS = 17.19 V > 3 V, so **Q-point (a) is in the pinch-off region**.
- (b) VGS - VP = 2 + 4 = 6 V; VDS = 8.75 V > 6 V, so **Q-point (b) is also in the pinch-off region** (for the assumed VDD and RD). In general the check is VDD - ID RD > VGS - VP.

#### d) Enhancement mode
A depletion MOSFET works in the depletion mode for VGS < 0 (channel width reduced, ID < IDSS) and in the **enhancement mode for VGS > 0** (channel gets more carriers, ID > IDSS). Hence Q-point (b), VGS = +2 V with ID = 22.5 mA > IDSS, is in the enhancement mode; Q-point (a) (VGS = -1 V, ID = 5.6 mA < IDSS) is in the depletion mode.

**Answer:** (a) ID = 5.625 mA, VDS = VDD - 5.625 RD; (b) ID = 22.5 mA, VDS = VDD - 22.5 RD; (c) both are in pinch-off if VDS exceeds 3 V and 6 V respectively; (d) only (b).

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is ID at VGS = -1 V for IDSS = 10 mA and VP = -4 V?
   A. 5.625 mA
   B. 7.5 mA
   C. 2.5 mA
   D. 10 mA
   Answer: A. ID = 10(1 - 0.25)^2 = 5.625 mA. (Key point: Drain current at VGS=-1)

2. What is ID at VGS = +2 V?
   A. 22.5 mA
   B. 15 mA
   C. 10 mA
   D. 12.5 mA
   Answer: A. ID = 10(1 + 0.5)^2 = 22.5 mA. (Key point: Drain current at VGS=+2)

3. What is the pinch-off (saturation) condition?
   A. VDS ≥ VGS - VP
   B. VDS ≤ VGS - VP
   C. VGS ≥ 0
   D. VDS = VDD
   Answer: A. The device is in pinch-off when VDS is at least VGS - VP. (Key point: Pinch-off condition)

4. Which Q-point is in enhancement mode?
   A. VGS = +2 V, since ID exceeds IDSS
   B. VGS = -1 V
   C. Both
   D. Neither
   Answer: A. Positive VGS in a depletion MOSFET gives enhancement, with ID > IDSS. (Key point: Enhancement mode)

## Related in Electronics Devices and Circuit

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