---
title: "Area of traverse by DMD and coordinates (N/S/E/W)"
subject: "Surveying I"
chapter: 9
key: "semester_3/surveying_i:area-closed-traverse-nswe-108"
source: https://www.bctengineer.com/q/semester_3/surveying_i/area-closed-traverse-nswe-108
site: BCT Engineering
---

# Area of traverse by DMD and coordinates (N/S/E/W)

Surveying I · Chapter 9: Computation of Area and Volume

- Asked in: 2080 Bhadra, 3+3 marks
- Video: [AREA OF CLOSED TRAVERSE: LATITUDE & DEPARTURE/ ERROR OF CLOSURE](https://www.youtube.com/watch?v=TFfu4_ilVyU) — Engineereya's Vlog
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/surveying_i/area-closed-traverse-nswe-108
- Whole chapter: https://www.bctengineer.com/md/semester_3/surveying_i/chapter-9

## Question

A closed traverse ABCDA is run along the boundaries with the following results.

| Side | Latitude N | Latitude S | Departure E | Departure W |
|---|---|---|---|---|
| AB | 108 | | 4 | |
| BC | 15 | | 249 | |
| CD | | 123 | 4 | |
| DA | 0 | | | 257 |

Calculate the area of the traverse by Double Meridian method and coordinate method.

## Short answer

DMD method: DMDs derived from departures, area = ½|Σ(L × DMD)| = 29221.50 m² (2.922 ha). Coordinate method confirms.

## Answer

Convert the table to signed values (N and E positive, S and W negative): ΣN = 123 = ΣS and ΣE = 257 = ΣW, so the traverse closes.

| Side | Latitude (m) | Departure (m) |
|---|---|---|
| AB | +108 | +4 |
| BC | +15 | +249 |
| CD | −123 | +4 |
| DA | 0 | −257 |

#### DMD method

**DMD rule (taking the meridian through the starting station):**
- DMD of the first line = departure of the first line.
- DMD of any line = DMD of the previous line + departure of the previous line + departure of the line itself.
- DMD of the last line = departure of the last line with opposite sign (a check).
- Double area = Σ (latitude × DMD), and area = ½ |Σ L × DMD|.

- DMD(AB) = D(AB) = 4
- DMD(BC) = 4 + (4) + (249) = 257
- DMD(CD) = 257 + (249) + (4) = 510
- DMD(DA) = 510 + (4) + (-257) = 257
- Check: DMD(DA) = 257 = −D(DA) = 257, so the DMDs are correct.

| Line | Latitude L (m) | Departure D (m) | DMD (m) | L × DMD (m²) |
|---|---|---|---|---|
| AB | 108 | 4 | 4 | 432 |
| BC | 15 | 249 | 257 | 3855 |
| CD | -123 | 4 | 510 | -62730 |
| DA | 0 | -257 | 257 | 0 |
| **Sum** | 0 | 0 | | **-58443** |

$$
\text{Area} = \frac{|-58443|}{2} = 29221.5\ \text{m}^2
$$

#### Coordinate method

Taking the first station as the origin (N = 0, E = 0) and adding the latitudes and departures successively gives the total coordinates. The area is

$$
2A = \sum N_i\,(E_{i+1} - E_{i-1})
$$

| Station | N (m) | E (m) | E(next) − E(previous) | N × (E(next) − E(previous)) |
|---|---|---|---|---|
| A | 0 | 0 | -253 | 0 |
| B | 108 | 4 | 253 | 27324 |
| C | 123 | 253 | 253 | 31119 |
| D | 0 | 257 | -253 | 0 |
| **Sum** | | | | **58443** |

$$
\text{Area} = \frac{|58443|}{2} = 29221.5\ \text{m}^2
$$

Both methods agree.

**Answer: Area = 29221.50 m² (2.922 ha).**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. How is the N/S/E/W table converted before computing?
   A. All values positive
   B. N and E positive, S and W negative
   C. N and W positive, S and E negative
   D. S and E positive, N and W negative
   Answer: B. Latitudes: N +, S -. Departures: E +, W -. (Key point: Signs)

2. How does the answer show the traverse closes?
   A. Sum N = sum S = 123 and sum E = sum W = 257
   B. Because all sides are equal
   C. Because DA has zero latitude
   D. Because there are four sides
   Answer: A. Closure needs net latitude and net departure to be zero. (Key point: Closure check)

3. How is the DMD of a line (other than the first) found?
   A. DMD of previous line - departure of the line itself
   B. Latitude of previous line + latitude of the line
   C. Sum of all departures
   D. DMD of previous line + departure of previous line + departure of the line itself
   Answer: D. Each DMD = previous DMD + previous departure + own departure. (Key point: DMD rule)

4. With DMD(AB) = 4 and departures AB = 4, BC = 249, what is DMD(BC)?
   A. 253
   B. 249
   C. 257
   D. 4
   Answer: C. 4 + 4 + 249 = 257. (Key point: DMD of BC)

## Related in Surveying I

- [Area by total coordinates and DMD (AB 90.29)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Admd-and-coordinates-ab-90-29) — Surveying I, chapter 9
- [Area by DMD, departure AB 405.85](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Admd-traverse-ab-405-85) — Surveying I, chapter 9, asked 2×
- [Area by coordinates and DMD (AB -370)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Aarea-coordinate-and-dmd-minus-370) — Surveying I, chapter 9, asked 4×
- [Area by DMD, traverse ABCD (225.28)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Admd-traverse-ab-225-28) — Surveying I, chapter 9, asked 2×
- [Area by DMD, traverse ABCDEA (-5.693)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Admd-five-sides-lat-minus-5-693) — Surveying I, chapter 9, asked 4×
- [Area by DMD, traverse ABCDE (+218)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Admd-traverse-ab-218) — Surveying I, chapter 9, asked 4×

## Related in other subjects

- [Closed traverse ABCDA missing figures (C=2500)](https://www.bctengineer.com/question.md?key=semester_4%2Fsurveying_ii%3Aclosed-traverse-abcda-missing-2072m) — Surveying II, chapter 1
- [Closed traverse ABCDA, B at 26500 N 22400 E](https://www.bctengineer.com/question.md?key=semester_4%2Fsurveying_ii%3Aclosed-traverse-abcda-missing-2066m) — Surveying II, chapter 1
- [Closed traverse ABCDA missing data, C(1200, 2000)](https://www.bctengineer.com/question.md?key=semester_4%2Fsurveying_ii%3Aclosed-traverse-abcda-c-1200-2000) — Surveying II, chapter 1
- [Closed traverse ABCDA, missing data](https://www.bctengineer.com/question.md?key=semester_4%2Fsurveying_ii%3Aclosed-traverse-abcda-missing-2069b) — Surveying II, chapter 1
