---
title: "Level book, RL of A 380.500, 3.945 on B"
subject: "Surveying I"
chapter: 5
key: "semester_3/surveying_i:level-book-4m-staff-30m-380-500-minus"
source: https://www.bctengineer.com/q/semester_3/surveying_i/level-book-4m-staff-30m-380-500-minus
site: BCT Engineering
---

# Level book, RL of A 380.500, 3.945 on B

Surveying I · Chapter 5: Leveling

- Asked in: 2081 Baisakh, 6 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_3/surveying_i/level-book-4m-staff-30m-380-500-minus
- Whole chapter: https://www.bctengineer.com/md/semester_3/surveying_i/chapter-5

## Question

The following consecutive readings were taken with a level and a 4 meter levelling staff on a continuously sloping ground at a common interval of 30 meters.

-0.855 (on A), 1.545, 2.353, 3.115, 3.825, 0.455, 1.380, 2.055, 2.855, 3.455, 0.585, 1.015, 1.850, 2.755, 3.945 (on B).

The R.L. of A was 380.500. Make a level book and apply usual checks. Determine the gradient of the line AB.

## Short answer

With rise and fall method, RL of B is 369.460 m. The fall from A (380.500 m) to B is 11.040 m over 360 m (12 intervals of 30 m), giving a falling gradient of 1 in 32.6.

## Answer

**Arranging the readings.** The staff is 4 m long, so the instrument must be shifted when the reading nears 4 m: after 3.825 and after 3.455. The first reading ($-0.855$ m) is negative: the staff was held inverted (for example under a beam), so the point A is above the line of sight. The set-ups are:

- Set-up 1: BS $-0.855$ on A; IS 1.545, 2.353, 3.115; FS 3.825 on CP1.
- Set-up 2: BS 0.455 on CP1; IS 1.380, 2.055, 2.855; FS 3.455 on CP2.
- Set-up 3: BS 0.585 on CP2; IS 1.015, 1.850, 2.755; FS 3.945 on B.

RL of A $= 380.500$ m. The 15 readings are on 13 points (the FS and BS at a change point are on one point), 30 m apart.

#### Level field book (rise and fall method)

| Station | BS | IS | FS | Rise | Fall | RL (m) |
|---|---|---|---|---|---|---|
| A | -0.855 |  |  |  |  | 380.500 |
| 2 |  | 1.545 |  |  | 2.400 | 378.100 |
| 3 |  | 2.353 |  |  | 0.808 | 377.292 |
| 4 |  | 3.115 |  |  | 0.762 | 376.530 |
| 5 (CP1) | 0.455 |  | 3.825 |  | 0.710 | 375.820 |
| 6 |  | 1.380 |  |  | 0.925 | 374.895 |
| 7 |  | 2.055 |  |  | 0.675 | 374.220 |
| 8 |  | 2.855 |  |  | 0.800 | 373.420 |
| 9 (CP2) | 0.585 |  | 3.455 |  | 0.600 | 372.820 |
| 10 |  | 1.015 |  |  | 0.430 | 372.390 |
| 11 |  | 1.850 |  |  | 0.835 | 371.555 |
| 12 |  | 2.755 |  |  | 0.905 | 370.650 |
| B |  |  | 3.945 |  | 1.190 | 369.460 |

#### Arithmetic check

$\Sigma BS - \Sigma FS = 0.185 - (11.225) = -11.040$ ; $\Sigma \text{Rise} - \Sigma \text{Fall} = 0.000 - 11.040 = -11.040$ ; last RL $-$ first RL $= 369.460 - 380.500 = -11.040$

All three are equal, so the reduction is correct.


#### Gradient of the line AB

There are 13 points, so 12 intervals of 30 m: $AB = 12 \times 30 = 360$ m.

$$
\text{Fall from A to B} = 380.500 - 369.460 = 11.040\ \text{m}
$$

$$
\text{Gradient} = \frac{11.040}{360} = \frac{1}{32.6}\ (\text{falling from A to B})
$$

**Answer:** RL of B = 369.460 m; the line AB falls at a gradient of 1 in 32.6 (about 1 in 33).

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. With a 4 m staff, why is the instrument shifted after 3.825 and 3.455?
   A. The reading nears the staff length, so the next point could not be read from the same set-up
   B. Those readings contain errors
   C. Every fourth reading must be a change point
   D. The staff is inverted there
   Answer: A. The staff reads only up to 4 m, so a change point is taken when readings approach that. (Key point: Where to shift)

2. What does the first reading of -0.855 m on A mean?
   A. A is 0.855 m below the instrument
   B. The staff was held inverted and A is above the line of sight
   C. It is a booking error
   D. It is a foresight reading
   Answer: B. A negative reading means the staff was inverted under an overhead object, so the point is above the line of sight. (Key point: Negative reading)

3. Which three equal quantities verify the rise and fall level book?
   A. SumBS - SumIS, SumFall, and first RL
   B. SumFS + SumBS, SumRise + SumFall, and last RL
   C. SumBS - SumFS, SumRise - SumFall, and last RL - first RL
   D. SumIS - SumFS only
   Answer: C. All three equal -11.040 m here, which checks the arithmetic of the reductions. (Key point: Checks)

4. RL of A = 380.500, RL of B = 369.460, 13 points at 30 m. What is the gradient?
   A. Falling 11.040 m in 390 m, 1 in 35.3
   B. Rising 11.040 m in 360 m, 1 in 32.6
   C. Falling 11.040 m in 30 m, 1 in 2.7
   D. Falling 11.040 m in 360 m, about 1 in 32.6
   Answer: D. 13 points give 12 intervals x 30 m = 360 m; 360/11.040 = 32.6. (Key point: Gradient)

## Close variants set in other exams

- [Level book, RL of B 1380.500](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Alevel-book-4m-staff-b-1380-500) — Surveying I, chapter 5, asked 3×
- [Level book, RL of A 380.500, 3.845 on B](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Alevel-book-4m-staff-a-380-500-3-845) — Surveying I, chapter 5, asked 3×

## Related in Surveying I

- [Level book, staff readings at B and C (1251.250)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Alevel-book-15m-b-c-rl-1250-800-1251-250) — Surveying I, chapter 5, asked 3×
- [Level book, staff readings at B and C (1251.000)](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Alevel-book-15m-b-c-rl-1250-800-1251-000) — Surveying I, chapter 5, asked 3×
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- [Level book, B and C, RL 50.250 base](https://www.bctengineer.com/question.md?key=semester_3%2Fsurveying_i%3Alevel-book-15m-b-c-rl-50-800-51-000) — Surveying I, chapter 5, asked 3×
