---
title: "Booth multiplication of -6 × -11"
subject: "Computer Organization and Architecture"
chapter: 5
key: "semester_5/computer_organization_and_architecture:booth-6x-11"
source: https://www.bctengineer.com/q/semester_5/computer_organization_and_architecture/booth-6x-11
site: BCT Engineering
---

# Booth multiplication of -6 × -11

Computer Organization and Architecture · Chapter 5: Computer Arithmetic

- Asked in: 2075 Chaitra, 6 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_5/computer_organization_and_architecture/booth-6x-11
- Whole chapter: https://www.bctengineer.com/md/semester_5/computer_organization_and_architecture/chapter-5

## Question

Multiply -6 × -11 using Booth's multiplication algorithm.

## Short answer

Booth's algorithm with 5-bit registers: -6 (11010) × -11 (10101), -M=00110. After five add/subtract and arithmetic right shifts, result in A,Q is 00010 00010 = 66.

## Answer

Booth's algorithm with 5-bit registers (−6 = 11010, −11 = 10101).

Multiplicand M = -6 = 11010, multiplier Q = -11 = 10101, -M = 00110, n = 5 bits.

```text
Step  Action               A      Q      Q-1
-     Initial              00000  10101  0
1     Q0Q-1=10: A = A - M  00110  10101  0
      ASR                  00011  01010  1
2     Q0Q-1=01: A = A + M  11101  01010  1
      ASR                  11110  10101  0
3     Q0Q-1=10: A = A - M  00100  10101  0
      ASR                  00010  01010  1
4     Q0Q-1=01: A = A + M  11100  01010  1
      ASR                  11110  00101  0
5     Q0Q-1=10: A = A - M  00100  00101  0
      ASR                  00010  00010  1
```

Result in A,Q = 00010 00010 = 66.

**Answer: -6 × -11 = 66**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. For M = -6 = 11010, -M is
   A. 00101
   B. 00110
   C. 11010
   D. 11001
   Answer: B. 2's complement of 11010 is 00110. (Key point: -M value)

2. Multiplier -11 = 10101 alternates bits. What does Booth do?
   A. Skip all steps
   B. Only shift
   C. Subtract or add at almost every step
   D. Add only
   Answer: C. Alternating 1s and 0s give 10 and 01 pairs often, so arithmetic is done in most steps. (Key point: Alternating multiplier)

3. What is -6 x -11?
   A. 66 = 00010 00010
   B. -66 = 11101 11110
   C. 66 = 00100 00100
   D. 6 = 00000 00110
   Answer: A. Both negative, product positive: A:Q = 00010 00010 = 66. (Key point: Result)

## Close variants set in other exams

- [Booth multiplication of -5 × -9](https://www.bctengineer.com/question.md?key=semester_5%2Fcomputer_organization_and_architecture%3Abooth-5x-9) — Computer Organization and Architecture, chapter 5, asked 5×
- [Booth multiplication of 5 × -6](https://www.bctengineer.com/question.md?key=semester_5%2Fcomputer_organization_and_architecture%3Abooth-5x-6) — Computer Organization and Architecture, chapter 5, asked 5×
- [Booth multiplication of -7 × -10](https://www.bctengineer.com/question.md?key=semester_5%2Fcomputer_organization_and_architecture%3Abooth-7x-10) — Computer Organization and Architecture, chapter 5, asked 5×
- [Booth multiplication of 10 × (-5)](https://www.bctengineer.com/question.md?key=semester_5%2Fcomputer_organization_and_architecture%3Abooth-10x-5) — Computer Organization and Architecture, chapter 5, asked 5×

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