---
title: "Double field revolving theory and a starting method"
subject: "Electric Machines II"
chapter: 3
key: "semester_5/electric_machines_ii:dfrt-one-starting-method"
source: https://www.bctengineer.com/q/semester_5/electric_machines_ii/dfrt-one-starting-method
site: BCT Engineering
---

# Double field revolving theory and a starting method

Electric Machines II · Chapter 3: Fractional Kilowatt Motors

- Asked in: 2081 Bhadra, 8 marks
- Video: [Double Field Revolving Theory - Single Phase Induction Motor -  Electrical Machines 3](https://www.youtube.com/watch?v=z0x1DM4RZRo) — Ekeeda
- Answer checked by Claude Sonnet 5.5 on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_5/electric_machines_ii/dfrt-one-starting-method
- Whole chapter: https://www.bctengineer.com/md/semester_5/electric_machines_ii/chapter-3

## Question

State and explain double field revolving theory of single phase induction motor with detailed diagram and explain any one starting method.

## Short answer

The double field revolving theory resolves a pulsating field into two equal counter-rotating fields at synchronous speed, yielding zero net torque at standstill. Once started, forward torque dominates. A capacitor-start method uses an auxiliary winding with a series capacitor and centrifugal switch to create phase shift and produce starting torque.

## Answer

**Double field revolving theory** states that a pulsating (alternating) magnetic field of maximum value $\phi_m$ can be replaced by **two fields, each of constant magnitude $\phi_m/2$, rotating in opposite directions at synchronous speed** $N_s = 120f/P$.

#### Pulsating field resolved

The single-phase stator winding produces a flux that only alternates along its axis:

$$
\phi = \phi_m \cos\omega t
$$

This is equal to the sum of two rotating phasors $\phi_f$ (forward) and $\phi_b$ (backward), each $\phi_m/2$, turning at $\omega$ in opposite directions:

$$
\phi = \frac{\phi_m}{2}e^{j\omega t} + \frac{\phi_m}{2}e^{-j\omega t} = \phi_m\cos\omega t
$$

```text
 wt = 0      wt = 90 deg     wt = 180 deg
  ^ ^          <-- -->          v v
  | |  phi_f  phi_b               | |
  sum = phi_m  sum = 0       sum = -phi_m
 (both along  (cancel)       (both reversed)
  the axis)
 phi_f turns anticlockwise, phi_b clockwise
```

At every instant the vertical components add and the horizontal components cancel, so the resultant is the pulsating field.

#### Torque at standstill - not self-starting

- At standstill each rotating field induces equal rotor currents (slip = 1 for both), so the forward torque $T_f$ and backward torque $T_b$ are equal and opposite.
- Net starting torque $T = T_f - T_b = 0$. Hence a single-phase induction motor is **not self-starting**.

#### Torque when running

If the rotor turns at speed $N$ in the forward direction:

$$
s_f = \frac{N_s - N}{N_s} = s, \qquad s_b = \frac{N_s + N}{N_s} = 2 - s
$$

Using the induction motor torque expression for each field:

$$
T_f = \frac{K s R_2}{R_2^2 + (sX_2)^2}, \qquad T_b = -\frac{K (2-s) R_2}{R_2^2 + \left((2-s)X_2\right)^2}
$$

$$
T = T_f + T_b
$$

- Near normal speed $s$ is small, $2 - s \approx 2$: the backward rotor current sees a large frequency $(2-s)f$ and high reactance, so $T_b$ is small and $T_f \gg |T_b|$. The motor keeps running in whichever direction it was started.

```text
        T
        |            _
        |         .-' \   forward run
        |      .-'     |  (Tf > Tb)
 -Ns ---+----.'--------+---> speed
     |  |  .' 0        Ns
      \_|.'
 reverse run      net T = 0 at N = 0
 (mirror image)
```

The resultant torque-speed curve passes through **zero at standstill** and is symmetrical: positive in the forward direction, negative in the reverse direction.

#### Equivalent circuit (based on DFRT)

The rotor is split into two halves, one for each field: forward half with $0.5R_2'/s$ and $0.5X_2'$, backward half with $0.5R_2'/(2-s)$ and $0.5X_2'$, each with $0.5X_m$ in parallel, in series with the stator $R_1 + jX_1$.

```text
 o--R1--X1--+--0.5X2'--0.5R2'/s ------+
 V          |  (0.5Xm parallel)  forward
            +--0.5X2'--0.5R2'/(2-s)---+
            |  (0.5Xm parallel)  backward
 o----------+-------------------------+
```

Hence, an auxiliary means (split phase, capacitor, shaded pole) is needed only to start the motor; once running, the forward field dominates.

#### One starting method: capacitor-start motor

Since net starting torque is zero, a second (auxiliary) winding is placed $90^\circ$ (electrical) from the main winding, with a capacitor $C$ in series and a **centrifugal switch** S.

```text
 1-ph AC o----+-----------+
              |           |
          Main wdg     Aux wdg
           (Im)           |
              |           C
              |           |
              |        S (opens at ~75% Ns)
 o------------+-----------+
```

1. The capacitor makes the auxiliary current $I_a$ **lead** $V$, while the main current $I_m$ lags $V$; the phase difference $\alpha$ approaches $90^\circ$.
2. Two space-displaced windings carrying time-displaced currents produce a **rotating field**, giving starting torque $T_{st} = K I_m I_a \sin\alpha$, which is high (about 3-4.5 times full-load torque).
3. At about 70-80 % of synchronous speed the centrifugal switch disconnects the auxiliary winding; the motor then runs on the main winding alone, as explained by DFRT.

It is used for compressors, pumps, refrigerators and air-conditioners.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. DFRT replaces a pulsating field phi_m with:
   A. Two fields phi_m/2 rotating in opposite directions at Ns
   B. One field phi_m at Ns
   C. Two fields phi_m rotating the same way
   D. Two fields of phi_m/2 at Ns/2
   Answer: A. The sum of forward and backward phasors reproduces phi_m cos(wt). (Key point: Statement of DFRT)

2. At standstill the net torque is zero because:
   A. Tf and Tb are equal and opposite with slip 1 for both fields
   B. Rotor current is zero
   C. The forward field vanishes
   D. The motor has a capacitor
   Answer: A. Each field gives equal rotor current and torque in opposite directions. (Key point: Zero starting torque)

3. In the capacitor-start method, the auxiliary current Ia relative to V is:
   A. Leading V, while Im lags V, so alpha approaches 90 degrees
   B. Lagging V more than Im
   C. In phase with Im
   D. Zero
   Answer: A. The capacitor makes Ia lead V. (Key point: Capacitor-start phase relation)

4. After the centrifugal switch opens at 70-80 % Ns, the motor:
   A. Runs on the main winding alone with the forward field dominating
   B. Stops
   C. Runs at double speed
   D. Runs on the capacitor alone
   Answer: A. Starting needs the auxiliary winding; running does not. (Key point: Switch and running)

## Close variants set in other exams

- [Double field revolving theory](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Adouble-field-revolving-theory) — Electric Machines II, chapter 3, asked 5×

## Related in Electric Machines II

- [DFRT, starting methods and capacitor start-run motor](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Adfrt-starting-methods-csr) — Electric Machines II, chapter 3
- [Single phase IM principle, torque-slip and starting](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Asingle-phase-principle-torque-slip) — Electric Machines II, chapter 3
- [Why single-phase IM is not self starting; methods](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Asingle-phase-not-self-starting-methods) — Electric Machines II, chapter 3, asked 2×
- [DFRT and equivalent circuit of single phase IM](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Adfrt-equivalent-circuit) — Electric Machines II, chapter 3
- [Split-phase motor winding currents at starting](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Asplit-phase-starting-currents) — Electric Machines II, chapter 3
- [DFRT explanation of no starting torque](https://www.bctengineer.com/question.md?key=semester_5%2Felectric_machines_ii%3Adfrt-not-self-starting) — Electric Machines II, chapter 3

## Related in other subjects

- [Double revolving field theory](https://www.bctengineer.com/question.md?key=semester_4%2Felectrical_machine%3Adouble-field-revolving-theory) — Electrical Machine, chapter 7, asked 3×
- [Double field theory; not self-starting](https://www.bctengineer.com/question.md?key=semester_4%2Felectrical_machine%3Adfrt-not-self-starting-proof) — Electrical Machine, chapter 7, asked 2×
- [Double field theory; starting methods](https://www.bctengineer.com/question.md?key=semester_4%2Felectrical_machine%3Adfrt-two-starting-methods) — Electrical Machine, chapter 7
- [DFRT and making single phase motor self-starting](https://www.bctengineer.com/question.md?key=semester_4%2Felectrical_machines%3Adfrt-self-starting-explain) — Electrical Machines, chapter 7, asked 3×
