---
title: "Estimation vs testing; CI for hardness"
subject: "Probability and Statistics"
chapter: 6
key: "semester_5/probability_and_statistics:estimation-vs-hypothesis-ci-magnesium"
source: https://www.bctengineer.com/q/semester_5/probability_and_statistics/estimation-vs-hypothesis-ci-magnesium
site: BCT Engineering
---

# Estimation vs testing; CI for hardness

Probability and Statistics · Chapter 6: Inference concerning mean

- Asked in: 2074 Asoj, 5 marks
- Answer checked by Claude Sonnet 5.5 on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_5/probability_and_statistics/estimation-vs-hypothesis-ci-magnesium
- Whole chapter: https://www.bctengineer.com/md/semester_5/probability_and_statistics/chapter-6

## Question

Discuss difference between estimation and hypothesis test of significance of population. The following hardness readings were obtained: 66.3, 63.5, 64.9, 61.9, 64.3, 64.7, 65.1, 64.5, 68.4, 63.2. Find 99% confidence interval for true hardness of magnesium alloy.

## Short answer

Estimation gives a parameter value or interval from a sample; hypothesis testing decides if a claim is supported. For hardness: mean = 64.68, t(0.005,9)=3.250, 99% confidence interval is (62.86, 66.50).

## Answer

#### Estimation versus testing of hypothesis

**Estimation** finds a value, or an interval of values, for an unknown population parameter from a sample. **Testing of hypothesis** decides, using sample evidence, whether a stated claim about the parameter should be accepted or rejected.

| Basis | Estimation | Hypothesis testing |
|---|---|---|
| Purpose | To find the value of the parameter | To check a claim about the parameter |
| Starting point | No prior claim about the parameter | A definite claim (H0) is made first |
| Result | Point value or confidence interval | Decision: reject or fail to reject H0 |
| Question answered | "What is the value of θ?" | "Is θ equal to (or greater/less than) θ₀?" |
| Error control | Confidence level (1 − α) | Level of significance α and power |
| Example | 99% interval for mean hardness | Test whether mean hardness = 65 |

Both use the sampling distribution of the statistic and are closely linked: a two-tailed test at level α rejects H0: μ = μ₀ exactly when μ₀ lies outside the (1 − α) confidence interval.

#### 99% confidence interval for mean hardness

Population SD is unknown and n is small (10), so the t-distribution is used.

```text
Σx = 646.8, n = 10
x̄ = 64.680
s² = Σ(x−x̄)²/(n−1) = 28.1760/9 = 3.1307
s  = 1.7694
SE = s/√n = 1.7694/√10 = 0.5595
t(0.005, 9) = 3.250
margin = 3.250 × 0.5595 = 1.818
limits = 64.680 ± 1.818
```

**Answer: the 99% confidence interval for the true hardness is (62.86, 66.50)**, i.e. about 62.9 to 66.5.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Which describes estimation as opposed to hypothesis testing?
   A. It finds the value or interval for a parameter with no prior claim
   B. It uses only alpha and power
   C. It starts with a claim H0
   D. It decides reject or fail to reject
   Answer: A. Estimation gives a value or confidence interval; testing checks a definite claim. (Key point: Estimation vs testing)

2. Why is the t-distribution used for the hardness CI?
   A. n is large
   B. The data are binomial
   C. Sigma is unknown and n = 10 is small
   D. Sigma is known
   Answer: C. With unknown population SD and a small sample, the t-distribution with n-1 d.f. is used. (Key point: Distribution used)

3. Which critical value is used for the 99% CI?
   A. t(0.01, 10) = 2.764
   B. z = 2.576
   C. t(0.025, 9) = 2.262
   D. t(0.005, 9) = 3.250
   Answer: D. 99% two-sided leaves 0.005 in each tail, with df = 9, giving 3.250. (Key point: Critical value)

4. What is the 99% confidence interval?
   A. (63.1, 66.3)
   B. (60.0, 69.4)
   C. (62.86, 66.50)
   D. (64.68, 68.00)
   Answer: C. 64.680 +- 3.250 x 0.5595 = 64.680 +- 1.818. (Key point: Result)

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