---
title: "Materials for 10 m³ brickwork (1:6) numerical"
subject: "Building Technology"
chapter: 3
key: "semester_6/building_technology:mortar-10m3-1to6"
source: https://www.bctengineer.com/q/semester_6/building_technology/mortar-10m3-1to6
site: BCT Engineering
---

# Materials for 10 m³ brickwork (1:6) numerical

Building Technology · Chapter 3: Mortars & Masonry works

- Asked in: 2075 Bhadra, 5 marks
- Video: [Calculation of Material required per 10 m3 volume of brickwork](https://www.youtube.com/watch?v=swUTyaJk2J4) — Amazing Engineering | ACES
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/building_technology/mortar-10m3-1to6
- Whole chapter: https://www.bctengineer.com/md/semester_6/building_technology/chapter-3

## Question

Estimate the quantities of materials for 10 m³ brick work where size of brick is 57mm × 115mm × 240mm, thickness of mortar is 10 mm and mortar of cement sand ratio is 1:6.

## Short answer

For 10 m³ brickwork, wet mortar volume is 2.485 m³, dry volume 3.156 m³ (×1.27). Using 1:6 mix, cement = (1/7)×3.156 = 0.451 m³ (13 bags of 50 kg) and sand = (6/7)×3.156 = 2.705 m³. Bricks: 4777 nos.

## Answer

**Given:** brickwork volume $= 10\ \text{m}^3$; brick size 57 mm x 115 mm x 240 mm (actual size, without mortar); mortar joint $= 10$ mm; mortar 1:6 (cement : sand).

**Step 1: Size of brick with mortar**

$$
(0.25 \times 0.125 \times 0.067) = 0.002094\ \text{m}^3
$$

**Step 2: Number of bricks**

$$
N = \frac{10}{0.002094} = 4776.1 \approx 4777\ \text{bricks}
$$

**Step 3: Volume of bricks without mortar**

$$
4777 \times 0.24 \times 0.115 \times 0.057 = 7.515\ \text{m}^3
$$

**Step 4: Wet volume of mortar**

$$
10 - 7.515 = 2.485\ \text{m}^3
$$

**Step 5: Dry volume of mortar** (add 27% for dry bulk, voids in sand, wastage and shrinkage)

$$
2.485 \times 1.27 = 3.156\ \text{m}^3
$$

**Step 6: Cement and sand** for 1:6 (sum of ratio $= 7$)

$$
\text{Cement} = \frac{1}{7} \times 3.156 = 0.451\ \text{m}^3 = 649\ \text{kg} \approx 13\ \text{bags (50 kg, 0.0347 m}^3\text{ each)}
$$

$$
\text{Sand} = \frac{6}{7} \times 3.156 = 2.705\ \text{m}^3
$$

**Answer: Bricks = 4777 nos.; cement = 0.451 m³ (about 13 bags); sand = 2.7 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Number of bricks in 10 m^3 is about:
   A. 4777
   B. 2000
   C. 10000
   D. 7515
   Answer: A. 10 / 0.002094 = 4776.1, rounded up to 4777. (Key point: Number of bricks)

2. Dry volume of mortar here is:
   A. 3.156 m^3
   B. 2.485 m^3
   C. 7.515 m^3
   D. 10 m^3
   Answer: A. 2.485 x 1.27 = 3.156 m^3. (Key point: Wet to dry)

3. Cement fraction in 1:6 mortar is:
   A. 1/7
   B. 1/6
   C. 1/5
   D. 6/7
   Answer: A. Sum of ratio is 7, so cement = 3.156/7 = 0.451 m^3. (Key point: Cement for 1:6)

4. Sand volume for 1:6 is about:
   A. 2.7 m^3
   B. 0.45 m^3
   C. 3.156 m^3
   D. 1.5 m^3
   Answer: A. Sand = 6/7 x 3.156 = 2.705 m^3. (Key point: Sand volume)

## Related in Building Technology

- [Mortar for 10 m³ brickwork (1:4) numerical](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Amortar-10m3-1to4) — Building Technology, chapter 3
- [Mortar properties; cement and sand for 10 cum](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Amortar-quantity-10cum) — Building Technology, chapter 3
- [First class brickwork in 1:6 mortar numerical](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Amortar-first-class-1to6) — Building Technology, chapter 3
- [Masonry work, materials for 20 cum brickwork](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Abrickwork-20cum-1to6) — Building Technology, chapter 3
- [Cement and sand for 100 m² plastering numerical](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Aplaster-100m2-1to6) — Building Technology, chapter 3, asked 2×
- [Cement and sand for 200 m² plastering numerical](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Aplaster-200m2-1to5) — Building Technology, chapter 3, asked 2×

## Related in other subjects

- [Materials for brick wall 10 m (1:5)](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-wall-10m-1-5) — Estimating and Costing, chapter 4, asked 2×
- [Materials for brick wall, two windows 1.5 m](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-wall-windows-1-5) — Estimating and Costing, chapter 4
- [Brick (1:6) materials; PCC (1:2:4) rate](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-1-6-and-pcc-rate) — Estimating and Costing, chapter 4
- [Materials for 10 m³ brick masonry 1:3](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-10m3-1-3-old-size) — Estimating and Costing, chapter 4