---
title: "Cement and sand for 200 m² plastering numerical"
subject: "Building Technology"
chapter: 3
key: "semester_6/building_technology:plaster-200m2-1to5"
source: https://www.bctengineer.com/q/semester_6/building_technology/plaster-200m2-1to5
site: BCT Engineering
---

# Cement and sand for 200 m² plastering numerical

Building Technology · Chapter 3: Mortars & Masonry works

- Asked in: 2077 Chaitra, 4 marks
- Video: [How to Calculate Quantity of Cement & Sand For Plaster](https://www.youtube.com/watch?v=pk8pAG5VxDg) — YAHYA SIR - PRODUCTIVE TALK
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/building_technology/plaster-200m2-1to5
- Whole chapter: https://www.bctengineer.com/md/semester_6/building_technology/chapter-3

## Question

Find out the quantities of cement and sand of 200 m² plastering area in 1:5 ratio if the thickness of plaster is 10mm.

## Short answer

For 200 m² plaster 10 mm thick in 1:5 mix: wet volume 2 m³, dry volume 2.54 m³. Cement = 0.423 m³ (approx. 12.2 bags), sand = 2.117 m³.

## Answer

**Given:** plastering area $= 200\ \text{m}^2$; thickness $= 10$ mm; mix 1:5 (cement : sand).

**Step 1: Wet volume of mortar**

$$
200 \times 0.01 = 2\ \text{m}^3
$$

**Step 2: Dry volume** (add 27% for dry bulk, voids in sand and wastage)

$$
2 \times 1.27 = 2.54\ \text{m}^3
$$

**Step 3: Cement and sand** (sum of ratio $= 6$)

$$
\text{Cement} = \frac{2.54}{6} = 0.423\ \text{m}^3 \approx 12.2\ \text{bags (0.0347 m}^3\text{ per bag)}
$$

$$
\text{Sand} = \frac{5}{6} \times 2.54 = 2.117\ \text{m}^3
$$

**Answer: Cement = 0.423 m³ (about 12.2 bags of 50 kg = 610 kg); sand = 2.117 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Wet mortar for 200 m^2 at 10 mm thickness is?
   A. 20 m^3
   B. 2 m^3
   C. 0.2 m^3
   D. 2.54 m^3
   Answer: B. 200 x 0.01 = 2 m^3. (Key point: Wet volume)

2. Dry volume after the 27% allowance is?
   A. 3 m^3
   B. 2.54 m^3
   C. 1.57 m^3
   D. 2.27 m^3
   Answer: B. 2 x 1.27 = 2.54 m^3. (Key point: Dry volume)

3. Cement for dry volume 2.54 m^3 in 1:5 mix?
   A. 2.54/5 = 0.508 m^3
   B. 2.54/6 = 0.423 m^3
   C. 2.54/4 = 0.635 m^3
   D. 2/6 = 0.333 m^3
   Answer: B. Sum of ratio is 6, cement = 0.423 m^3 (about 12.2 bags). (Key point: Cement in 1:5)

4. Sand quantity is?
   A. 0.423 m^3
   B. 2.117 m^3
   C. 2.54 m^3
   D. 1.693 m^3
   Answer: B. Sand = 5/6 x 2.54 = 2.117 m^3. (Key point: Sand in 1:5)

## Close variants set in other exams

- [Cement and sand for 100 m² plastering numerical](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Aplaster-100m2-1to6) — Building Technology, chapter 3, asked 2×

## Related in Building Technology

- [Cement-sand plastering and its types](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Aplastering-process) — Building Technology, chapter 9, asked 3×
- [Mortar properties; cement and sand for 10 cum](https://www.bctengineer.com/question.md?key=semester_6%2Fbuilding_technology%3Amortar-quantity-10cum) — Building Technology, chapter 3

## Related in other subjects

- [Methods of taking out quantities](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amethods-taking-out-quantities) — Estimating and Costing, chapter 2, asked 6×
- [Detailed specification of cement plaster 1:4](https://www.bctengineer.com/question.md?key=semester_8%2Fconstruction_management%3Adetailed-spec-plaster-1-4) — Construction Management, chapter 12
- [Underground water tank: excavation, brick, plaster](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Aug-tank-g-brick-plaster) — Estimating and Costing, chapter 6