---
title: "Square deodar column 4 m, 250 kN, open shed"
subject: "Design of Steel and Timber Structure"
chapter: 11
key: "semester_6/design_of_steel_and_timber_structure:timber-column-deodar-4m-250kn"
source: https://www.bctengineer.com/q/semester_6/design_of_steel_and_timber_structure/timber-column-deodar-4m-250kn
site: BCT Engineering
---

# Square deodar column 4 m, 250 kN, open shed

Design of Steel and Timber Structure · Chapter 11: Design of Compression Members

- Asked in: 2076 Baisakh, 6 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/design_of_steel_and_timber_structure/timber-column-deodar-4m-250kn
- Whole chapter: https://www.bctengineer.com/md/semester_6/design_of_steel_and_timber_structure/chapter-11

## Question

Design a square Deoder wood column of length 4m to be used in an open shed, to carry an axial load of 250kN.

## Short answer

Solid square Deodar column per IS 883:1994. Trial 225×225mm (A=50,625mm²). S/d=17.8, K8=21.65, intermediate column; fc=fcp[1-⅓(S/d/K8)⁴]=5.85 N/mm². Capacity P=fc·A=296 kN > 250 kN. Safe. Grade I, outside location, pin-ended, S/d<50 satisfied.

## Answer

**Approach.** Working stress design to IS 883:1994 (cl. 7.6 for columns, cl. 7.7 for combined axial compression and bending). Ends are taken as pin-ended, so the effective length equals the unsupported length $S$ (cl. 7.6.1.5).

#### Data and permissible stresses

Length $S = 4.00$ m = 4000 mm. Axial load $N = 250$ kN.

**Species:** Deodar (Cedrus deodara), Group C. **Location:** outside. **Grade:** Grade I (standard) (Table 1 values are for Grade I).

Permissible stresses (IS 883:1994 Table 1, outside location):

| Property | Table 1 value (N/mm²) | Used (N/mm²) |
|---|---|---|
| Bending / tension along grain $f_b$ | 8.7 | 8.70 |
| Compression parallel to grain $f_{cp}$ | 6.9 | 6.90 |
| Compression perpendicular to grain $f_{cn}$ | 2.1 | 2.10 |
| Horizontal shear $H$ | 0.7 | 0.70 |
| Modulus of elasticity $E$ | 9480 | 9480 |

An open shed is an **outside** location. The grade is not stated, so Grade I (standard) is taken.

#### Trial section

Try **225 mm × 225 mm** (square). Area $A = 50,625$ mm²; least dimension $d = 225$ mm.

#### Slenderness and permissible axial stress (cl. 7.6.1)

$$
\begin{aligned} S/d &= \frac{4000}{225} = 17.8 \\ K_8 &= 0.584\sqrt{\frac{E}{f_{cp}}} = 0.584\sqrt{\frac{9480}{6.90}} = 21.65 \end{aligned}
$$

$11 < S/d = 17.8 < K_8 = 21.6$, so it is an **intermediate column**:

$$
f_c = f_{cp}\left[1 - \frac{1}{3}\left(\frac{S/d}{K_8}\right)^4\right] = 6.90\left[1 - \frac{1}{3}\left(\frac{17.8}{21.6}\right)^4\right] = 5.85\ \text{N/mm}^2
$$

$S/d = 17.8 < 50$ (cl. 7.6.1.4). OK.

#### Check

$$
P = f_cA = 5.85\times50,625/10^3 = 296.3\ \text{kN} \ge N = 250\ \text{kN}
$$

Safe.

#### Answer

Provide a solid Deodar column of **225 mm × 225 mm** cross-section (Grade I (standard), outside location). Capacity $296$ kN $> 250$ kN.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Why are the 'outside' Table 1 stresses used for the column in an open shed?
   A. Because the column is Group C timber
   B. Because an open shed is exposed to weather, so it is an outside location
   C. Because the grade is Select
   D. Because the length is over 3 m
   Answer: B. An open shed is not enclosed, so IS 883 outside-location stresses (lower than inside) apply. (Key point: Location and stress values)

2. S/d = 17.8 and K8 = 21.65. How is the column classified and which fc formula is used?
   A. Short; fc = fcp
   B. Intermediate (11 < S/d < K8); fc = fcp[1 - (1/3)(S/d / K8)^4]
   C. Long; fc = 0.329E/(S/d)^2
   D. Intermediate; fc = 0.329E/(S/d)^2
   Answer: B. S/d lies between 11 and K8, so the intermediate-column formula with the fourth power applies. (Key point: Column classification)

3. With 225 x 225 mm and fc = 5.85 N/mm^2, what is the conclusion?
   A. P = 296 kN > 250 kN, safe
   B. P = 296 kN > 250 kN, but S/d exceeds 50 so it fails
   C. P = 350 kN, over-designed and rejected
   D. P = 250 kN exactly
   Answer: A. P = fc x A = 5.85 x 50,625 = 296 kN, greater than 250 kN; S/d = 17.8 is also below the 50 limit. (Key point: Capacity check)

## Related in Design of Steel and Timber Structure

- [Circular Sal column, open shed, 200 kN](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-circular-sal-3-5m-200kn) — Design of Steel and Timber Structure, chapter 11
- [Square deodar column 4 m, 350 kN, outside](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-column-deodar-square-4m-350kn) — Design of Steel and Timber Structure, chapter 11
- [Box deodar column, 60 mm planks, 350 kN](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-box-column-deodar-5m-350kn) — Design of Steel and Timber Structure, chapter 11
- [Deodar column 4 m, 300 kN](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-column-deodar-4m-300kn) — Design of Steel and Timber Structure, chapter 11
- [Check 25 cm x 25 cm Sal column, 200 kN + 20 kNm](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-column-sal-25x25-200kn-20knm) — Design of Steel and Timber Structure, chapter 11
- [Check 200x200 Debdar column, 30 kN + 1.5 kNm](https://www.bctengineer.com/question.md?key=semester_6%2Fdesign_of_steel_and_timber_structure%3Atimber-column-check-debdar-200x200) — Design of Steel and Timber Structure, chapter 11

## Related in other subjects

- [Brick column design for 80 kN axial load](https://www.bctengineer.com/question.md?key=semester_5%2Fconcrete_technology_and_masonry_structure%3Abrick-column-80kn-roof) — Concrete Technology and Masonry Structure, chapter 8
- [Design of a square timber column](https://www.bctengineer.com/question.md?key=semester_5%2Fdesign_of_timber_and_masonry_structures%3Adesign-axially-loaded-timber-column) — Design of Timber and Masonry Structures, chapter 3
- [Biaxial short square column, 800 kN](https://www.bctengineer.com/question.md?key=semester_7%2Fdesign_of_rcc_structure%3Abiaxial-short-square-column-800-kn) — Design of RCC Structure, chapter 10
- [Timber column under axial load and bending](https://www.bctengineer.com/question.md?key=semester_5%2Fdesign_of_timber_and_masonry_structures%3Atimber-column-combined-bending-axial) — Design of Timber and Masonry Structures, chapter 3
