---
title: "Transfer function of zero order hold"
subject: "Digital Control System"
chapter: 1
key: "semester_6/digital_control_system:zoh-transfer-function"
source: https://www.bctengineer.com/q/semester_6/digital_control_system/zoh-transfer-function
site: BCT Engineering
---

# Transfer function of zero order hold

Digital Control System · Chapter 1: Introduction to Discrete Time Control System

- Asked in: 2081 Chaitra, 4 marks; 2080 Chaitra, 6 marks; 2070 Magh, 8 marks; 2067 Mangsir, 6 marks (asked 4 times)
- Video: [Zero Order Hold Transfer Function Proof. Based on IOE Syllabus . Digital Control System.....](https://www.youtube.com/watch?v=zAsuE-esMDU) — Aman Grid
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/digital_control_system/zoh-transfer-function
- Whole chapter: https://www.bctengineer.com/md/semester_6/digital_control_system/chapter-1

## Question

Show that the transfer function of zero order hold circuit is given by Gₕ₀(s)=(1-e⁻ᵀˢ)/s.

## Short answer

The ZOH holds each sample for one period T, giving impulse response g(t)=u(t)-u(t-T). Taking the Laplace transform of this rectangular pulse gives G_h0(s) = (1 - e^{-Ts})/s, the required transfer function.

## Answer

A **zero order hold (ZOH)** holds each sample value constant until the next sample arrives. Its output is a staircase signal. Its transfer function is found from its impulse response.

#### Impulse response

Apply a unit impulse $\delta(t)$ (sample of strength 1 at $t=0$). The ZOH holds this value for one sampling period $T$ and then drops to zero:

$$
g_{h0}(t) = \begin{cases} 1, & 0 \le t < T \\ 0, & \text{otherwise} \end{cases}
$$

```text
 g(t)
  1 |------+
    |      |
    |      |
  0 +------+---------> t
    0      T
```

This rectangular pulse is the difference of two unit steps:

$$
g_{h0}(t) = u(t) - u(t-T)
$$

#### Laplace transform

Using $\mathcal{L}[u(t)] = \frac{1}{s}$ and the time-shift theorem $\mathcal{L}[f(t-T)u(t-T)] = e^{-Ts}F(s)$:

$$
\begin{aligned}
G_{h0}(s) &= \mathcal{L}[u(t)] - \mathcal{L}[u(t-T)] \\
&= \frac{1}{s} - \frac{e^{-Ts}}{s} \\
&= \frac{1-e^{-Ts}}{s}
\end{aligned}
$$

which is the required result.

#### General input

For an impulse-sampled input $x^*(t) = \sum x(kT)\delta(t-kT)$, the output is
$h(t) = \sum_k x(kT)[u(t-kT) - u(t-(k+1)T)]$, whose Laplace transform is $X^*(s)\,\frac{1-e^{-Ts}}{s}$, confirming the same transfer function.

#### Frequency response (for reference)

Putting $s = j\omega$:
$G_{h0}(j\omega) = T\,\frac{\sin(\omega T/2)}{\omega T/2}\,e^{-j\omega T/2}$, so the ZOH is a low-pass filter with a phase lag of $\omega T/2$ (a delay of half a sampling period).

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is the response of a zero order hold to a unit impulse?
   A. A unit pulse of height 1 lasting for 0 <= t < T, then zero
   B. A ramp rising from 1 to 2 over T
   C. An impulse of strength T
   D. A constant 1 for all t >= 0
   Answer: A. The ZOH holds the sample value for one period T and then drops to zero, giving a rectangular pulse. (Key point: ZOH impulse response)

2. How is the rectangular pulse g(t) written using unit steps?
   A. u(t) + u(t-T)
   B. u(t) - u(t-T)
   C. u(t) * u(t-T)
   D. u(t-T) - u(t-2T)
   Answer: B. A step starting at 0 minus a delayed step starting at T leaves a pulse of height 1 between 0 and T. (Key point: Pulse as step difference)

3. Which property turns the delayed step u(t-T) into e^(-Ts)/s?
   A. Initial value theorem
   B. Convolution theorem
   C. Time-shift theorem of the Laplace transform
   D. Final value theorem
   Answer: C. L[f(t-T)u(t-T)] = e^(-Ts)F(s), and with F(s) = 1/s this gives e^(-Ts)/s. (Key point: Time-shift theorem)

4. What does putting s = jω show about the ZOH?
   A. It is a low-pass filter with phase lag ωT/2 (a delay of half a sampling period)
   B. It is a high-pass filter with phase lead
   C. It has unity gain and zero phase at all frequencies
   D. It amplifies high frequencies
   Answer: A. G(jω) = T sin(ωT/2)/(ωT/2) e^(-jωT/2): a sinc magnitude (low-pass) and phase lag ωT/2. (Key point: Frequency response of ZOH)

## Close variants set in other exams

- [Transfer function of first order hold](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Afoh-transfer-function) — Digital Control System, chapter 1, asked 7×

## Related in Digital Control System

- [Pulse transfer function with first order hold](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Afoh-system-pulse-tf) — Digital Control System, chapter 3
- [Data hold circuit and ZOH derivation](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Adata-hold-zoh-derivation) — Digital Control System, chapter 1
- [ZOH and FOH defined; ZOH transfer function](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Azoh-foh-definition) — Digital Control System, chapter 1
- [Series programming of a third-order transfer function](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Aseries-programming-z-plus-1) — Digital Control System, chapter 4, asked 2×
- [Ladder programming of a third-order transfer function](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Aladder-z3-4z2) — Digital Control System, chapter 4, asked 2×
- [Short note: Sample and hold circuit](https://www.bctengineer.com/question.md?key=semester_6%2Fdigital_control_system%3Ashort-note-sample-hold) — Digital Control System, chapter 1

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- [3rd order Butterworth HPF from LPF transfer function](https://www.bctengineer.com/question.md?key=semester_5%2Ffilter_design%3Athird-order-hpf-from-lpf-tf) — Filter Design, chapter 5
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