---
title: "ERR to recommend best of A, B, C"
subject: "Engineering Economics"
chapter: 4
key: "semester_6/engineering_economics:err-recommend-best-abc-e20"
source: https://www.bctengineer.com/q/semester_6/engineering_economics/err-recommend-best-abc-e20
site: BCT Engineering
---

# ERR to recommend best of A, B, C

Engineering Economics · Chapter 4: Comparative Analysis of Alternatives

- Asked in: 2065 Kartik, 12 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/engineering_economics/err-recommend-best-abc-e20
- Whole chapter: https://www.bctengineer.com/md/semester_6/engineering_economics/chapter-4

## Question

Recommend the best using ERR method, E = 20%. (End of year cash flows in Rs. '000.)
| ERR | Project | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|---|
| 28.3% | A | -640 | 262 | 290 | 302 | 310 | 310 | 260 |
| 26.4% | B | -680 | -40 | 392 | 380 | 380 | 380 | 380 |
| 28.5% | C | -755 | 205 | 406 | 400 | 390 | 390 | 324 |

## Short answer

Individual ERR: A28.3%, B26.4%, C28.5% all >20%. Incremental ERR: B over A =14.32% (reject), C over A =27.10% (accept). Recommend project C.

## Answer

**ERR method.** Compound all positive cash flows to year 6 at the reinvestment rate ε = 20% and discount all negative cash flows to year 0 at ε. ERR is the rate i' that satisfies PW(outflows)(1 + i')⁶ = FW(inflows). The **MARR is not stated; assume MARR = ε = 20%.** (Figures in Rs '000.)

#### Step 1: ERR of each project
```text
A: FW = 262(1.2)⁵ + 290(1.2)⁴ + 302(1.2)³ + 310(1.2)² + 310(1.2) + 260 = 2853.5
   PW(out) = 640
   ERR = (2853.5/640)^(1/6) − 1 = 28.29%
B: FW = 392(1.2)⁴ + 380(1.2)³ + 380(1.2)² + 380(1.2) + 380 = 2852.7
   PW(out) = 680 + 40/1.2 = 713.3
   ERR = (2852.7/713.3)^(1/6) − 1 = 25.99%
C: FW = 205(1.2)⁵ + 406(1.2)⁴ + 400(1.2)³ + 390(1.2)² + 390(1.2) + 324 = 3396.8
   PW(out) = 755
   ERR = (3396.8/755)^(1/6) − 1 = 28.49%
```
(The values printed with the question are 28.3%, 26.4% and 28.5%; recomputation gives B slightly lower, which does not change the ranking.) All three exceed 20%, so all are acceptable. ERR of the individual projects cannot be used to rank mutually exclusive projects of different size, so use incremental analysis, starting with the cheapest project A.

#### Step 2: Incremental ERR
```text
Year     0     1     2    3    4    5    6
B − A  −40  −302   102   78   70   70  120
C − A −115   −57   116   98   80   80   64
```
- **B − A:** FW of inflows at year 6 = 651.1; PW of outflows = 40 + 302/1.2 = 291.7; ERR = 14.32% < 20%. The extra investment in B is not justified, so A stays the defender.
- **C − A:** FW = 685.1; PW of outflows = 115 + 57/1.2 = 162.5; ERR = 27.10% > 20%. The extra investment in C is justified, so C replaces A.

| Comparison | Incremental ERR | Decision |
|---|---|---|
| B vs A | 14.32% | Keep A |
| C vs A | 27.10% | Choose C |

**Answer: Recommend project C.** Its extra investment of Rs 1,15,000 over A earns 27.10%, above the required 20%, and C also has the highest individual ERR (28.49%).

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What equation defines ERR for these projects (E = 20%)?
   A. PW(inflows)(1+i')^6 = FW(outflows)
   B. PW(outflows)(1+i')^6 = FW(inflows at year 6)
   C. FW(outflows) = PW(inflows)
   D. Sum of flows = 0 at i'
   Answer: B. Negatives are discounted to year 0 and positives compounded to year 6 at E, then PW(out)(1+i')^6 = FW(in). (Key point: ERR equation)

2. Why is incremental ERR used even though all three ERRs exceed 20%?
   A. Because ERR is invalid
   B. Because MARR is unknown
   C. Because individual ERRs cannot reliably rank mutually exclusive projects of different size
   D. Because B has negative flows
   Answer: C. Different investment sizes require checking whether each extra investment earns at least MARR. (Key point: Why incremental analysis)

3. The incremental ERR of B over A is 14.32%. What follows?
   A. B replaces A
   B. A stays as defender because the extra investment in B is below 20%
   C. C is rejected
   D. A is rejected
   Answer: B. 14.32% < 20%, so the additional investment in B is not justified. (Key point: B vs A)

4. Which project is recommended and why?
   A. A, the cheapest
   B. B, the most inflows
   C. A, highest incremental ERR
   D. C, because its extra investment over A earns 27.10% > 20%
   Answer: D. C vs A increment earns 27.10%, above the required 20%, so C replaces A. (Key point: Final recommendation)

## Related in Engineering Economics

- [Payback period to recommend best of A, B, C](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Apayback-recommend-abc-2a) — Engineering Economics, chapter 4
- [ERR method to select best of three projects](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Aerr-select-best-abc) — Engineering Economics, chapter 4
- [Best project for 4-year and 8-year service periods](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Aselect-best-project-fw-4yr-irr) — Engineering Economics, chapter 4

## Related in other subjects

- [Best financing option; EBIT Rs 350,000](https://www.bctengineer.com/question.md?key=semester_7%2Fproject_engineering%3Abest-option-two-options-ebit-350000) — Project Engineering, chapter 6
- [EPS and book value; ABC project Rs 6,00,000](https://www.bctengineer.com/question.md?key=semester_7%2Fproject_engineering%3Aeps-bv-abc-project-600000-b79) — Project Engineering, chapter 6
