---
title: "Nominal vs effective; FW with monthly compounding"
subject: "Engineering Economics"
chapter: 2
key: "semester_6/engineering_economics:fw-monthly-compounding-annual-begin"
source: https://www.bctengineer.com/q/semester_6/engineering_economics/fw-monthly-compounding-annual-begin
site: BCT Engineering
---

# Nominal vs effective; FW with monthly compounding

Engineering Economics · Chapter 2: Interest and Time Value of Money

- Asked in: 2071 Bhadra, 3+5 marks
- Video: [Compounding More Frequent than Payments - Engineering Economics Lightboard](https://www.youtube.com/watch?v=kEcGEXlK5oY) — Engineering Economics Guy
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/engineering_economics/fw-monthly-compounding-annual-begin
- Whole chapter: https://www.bctengineer.com/md/semester_6/engineering_economics/chapter-2

## Question

What is nominal and effective interest rate? Evaluate FW at the end of 15 years with 10% interest compounded monthly of a cash flow of Rs. 50,000 at the beginning of each year for first 10 years.

## Short answer

Effective annual rate = (1+0.10/12)^12 -1 = 10.4713%. Annuity-due of 10 payments gives FV at year 9, then compound 6 years: FW = 50,000 × 16.302 × 1.8175 = Rs 14,81,529.

## Answer

#### Nominal and effective interest rate
The nominal rate is the stated yearly rate, ignoring the effect of compounding within the year (here 10% per year). The effective rate is the actual yearly rate after compounding m times a year: i = (1 + r/m)ᵐ − 1.

#### Effective annual rate
i = (1 + 0.10/12)¹² − 1 = **10.4713% per year**

#### Cash flow diagram
```text
 Rs 50,000 at t = 0, 1, ..., 9 (beginning of years 1-10)
 ^  ^  ^  ^  ^  ^  ^  ^  ^  ^
 |  |  |  |  |  |  |  |  |  |
 +--+--+--+--+--+--+--+--+--+--+--+--+--+--+--+--> year
 0  1  2  3  4  5  6  7  8  9  10 11 12 13 14 15
                                              FW = ?
```

#### FW at the end of year 15
The payments at t = 0 to 9 form an annuity-due. The (F/A, i, 10) factor gives their value at t = 9, so this is then moved to t = 15 (6 years):

FW = 50,000 (F/A, 10.4713%, 10) (F/P, 10.4713%, 6)

- (F/A, 10.4713%, 10) = [(1.104713)¹⁰ − 1] / 0.104713 = 16.302
- (F/P, 10.4713%, 6) = (1.104713)⁶ = 1.8175

FW = 50,000 × 16.302 × 1.8175 = **Rs 1,481,529**

**Answer: FW at the end of 15 years = about Rs 14.8 lakh.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Effective rate for 10% compounded monthly?
   A. (1 + 0.10/12)^12 - 1 = 10.4713%
   B. 10%
   C. 0.8333%
   D. 10.25%
   Answer: A. Compounding monthly lifts 10% nominal to 10.47% effective. (Key point: Effective annual rate)

2. Payments at the beginning of years 1-10: where does (F/A, i, 10) place their value?
   A. At t = 10
   B. At t = 9, so it must be moved 6 more years to t = 15
   C. At t = 15
   D. At t = 0
   Answer: B. First payment at t=0 means last at t=9. (Key point: Annuity due)

3. Which expression gives FW at 15?
   A. 50,000 (F/A, 10.4713%, 15)
   B. 50,000 (P/A, 10.4713%, 10)(F/P, 10.4713%, 15)
   C. 50,000 (F/A, 10.4713%, 10)(F/P, 10.4713%, 6)
   D. 50,000 (F/A, 10%, 10)(F/P, 10%, 5)
   Answer: C. Annuity to t=9 then 6 years of growth. (Key point: Setup)

## Close variants set in other exams

- [Nominal vs effective; FW with continuous compounding](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Afw-continuous-compounding-500) — Engineering Economics, chapter 2, asked 2×

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