---
title: "Modified B/C ratio for the required-receipts problem"
subject: "Engineering Economics"
chapter: 3
key: "semester_6/engineering_economics:modified-bcr-for-5a"
source: https://www.bctengineer.com/q/semester_6/engineering_economics/modified-bcr-for-5a
site: BCT Engineering
---

# Modified B/C ratio for the required-receipts problem

Engineering Economics · Chapter 3: Basic Methodologies of Engineering Economic Analysis

- Asked in: 2065 Kartik, 8 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/engineering_economics/modified-bcr-for-5a
- Whole chapter: https://www.bctengineer.com/md/semester_6/engineering_economics/chapter-3

## Question

Find the modified B/C ratio for the investment proposal below (problem 5(a): initial investment Rs. 10,00,000, salvage value Rs. 1,00,000, O & M expenses Rs. 50,000 per year, benefits of A+70,000, A+80,000, A+90,000, A+100,000, A+110,000 in years 1 to 5, using the value of A found there).

## Short answer

Modified B/C = 1.00 at A ≈ Rs 223,923 (MARR 12%). A chosen so PW benefits equals PW costs, making ratio exactly 1 (break-even). Net benefits and net investment both equal Rs 943,257.

## Answer

Assumption: the MARR is not printed with the question; take **MARR = 12%**. First find A (the value that makes the proposal just acceptable), then compute the modified B/C ratio.

#### Cash-flow diagram (Rs.)

```text
Benefits  A+70k  A+80k  A+90k  A+100k  A+110k
          |      |      |      |       |
  0 ------1------2------3------4-------5---> year
  |       O&M -50,000 every year (1-5)  ^ salvage +100,000
  v 1,000,000 (investment)
```

#### Step 1: find A
The extra amount over A is 70,000, 80,000, ..., 110,000. This is a uniform series of 70,000 plus a gradient of G = 10,000 (0, 10k, 20k, 30k, 40k).

Factors at 12%, N = 5:
- (P/A, 12%, 5) = 3.6048
- (P/G, 12%, 5) = 6.3970
- (P/F, 12%, 5) = 0.5674

```text
PW(benefits) = A(P/A) + 70,000(P/A) + 10,000(P/G)
             = 3.6048 A + 252,334 + 63,970
             = 3.6048 A + 316,304
PW(costs)    = 1,000,000 + 50,000(P/A) - 100,000(P/F)
             = 1,000,000 + 180,239 - 56,743
             = 1,123,496
```
Set PW(benefits) = PW(costs):
3.6048 A = 1,123,496 - 316,304 = 807,192

**A = Rs. 223,923 per year** (required annual receipts).

#### Step 2: modified B/C ratio
Modified B/C = [PW(benefits) - PW(O&M)] / [Investment - PW(salvage)]

- PW(benefits) = 3.6048 × 223,923 + 316,304 = 1,123,496
- PW(O&M) = 50,000 × 3.6048 = 180,239
- Net benefit = 1,123,496 - 180,239 = 943,257
- Net investment = 1,000,000 - 100,000 × 0.5674 = 943,257

Modified B/C = 943,257 / 943,257 = **1.00**

**Answer: Modified B/C = 1.00 (at A ≈ Rs. 223,923).** Because A was chosen so that PW of benefits equals PW of costs, the ratio is exactly 1, the break-even point. Any receipts larger than this A give a ratio above 1 and make the proposal acceptable.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is the first step before computing the modified B/C?
   A. Find A so that PW of benefits equals PW of costs
   B. Ignore A
   C. Compute IRR
   D. Compute payback
   Answer: A. The answer first finds A (required receipts), then computes the modified ratio. (Key point: Step order)

2. Which is the modified B/C formula used?
   A. [PW(B) + PW(O&M)] / I
   B. PW(B) / [I + PW(O&M) - PW(S)]
   C. [PW(B) - PW(O&M)] / [I - PW(S)]
   D. PW(B) / PW(O&M)
   Answer: C. O&M is netted from benefits; salvage is netted from investment. (Key point: Modified B/C formula)

3. What is the modified B/C ratio at the A found?
   A. 0.76
   B. 1.00
   C. 1.48
   D. 1.19
   Answer: B. Net benefit and net investment are both 943,257, so the ratio is exactly 1. (Key point: Final value)

4. Why does the ratio come out exactly 1?
   A. O&M is zero
   B. MARR is 1%
   C. Salvage is zero
   D. A was chosen so PW benefits equal PW costs (break-even)
   Answer: D. Setting PW(benefits) = PW(costs) to find A is the break-even point, giving ratio 1. (Key point: Why exactly 1)

## Related in Engineering Economics

- [Find required annual receipts A](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Arequired-annual-receipts-a-1000000) — Engineering Economics, chapter 3
- [Modified B/C ratio for 100,000 project](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Amodified-bcr-100000-25000) — Engineering Economics, chapter 3
- [Sensitivity on investment, revenue and life; interpret](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Asensitivity-30-initial-100000-useful-10) — Engineering Economics, chapter 6
- [Define ESL; find ESL of 50,000 asset](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Aesl-define-50000-15-percent-growth) — Engineering Economics, chapter 5
- [Best of three mutually exclusive projects, 10-year study](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Amutually-exclusive-abc-study-10-years) — Engineering Economics, chapter 4
- [Sensitivity to investment, revenue and life](https://www.bctengineer.com/question.md?key=semester_6%2Fengineering_economics%3Asensitivity-30-investment-revenue-life-500000) — Engineering Economics, chapter 6

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