---
title: "Hall 16 × 12 m LED lighting"
subject: "Industrial Power Distribution and Illumination"
chapter: 7
key: "semester_6/industrial_power_distribution_and_illumination:hall-16x12-led"
source: https://www.bctengineer.com/q/semester_6/industrial_power_distribution_and_illumination/hall-16x12-led
site: BCT Engineering
---

# Hall 16 × 12 m LED lighting

Industrial Power Distribution and Illumination · Chapter 7: Illumination Design Principles

- Asked in: 2075 Bhadra, 8 marks
- Video: [ILLUMINATION ENGINEERING - PART - 11 - LUMEN OR FLUX METHOD OF  CALCULATION AND THREE PROBLEMS](https://www.youtube.com/watch?v=mB573i9S39A) — zenmurali Sachithanandam
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/industrial_power_distribution_and_illumination/hall-16x12-led
- Whole chapter: https://www.bctengineer.com/md/semester_6/industrial_power_distribution_and_illumination/chapter-7

## Question

A hall of size 16 m× 12 m is to be illuminated by 55 watt LED lamp. Inside the hall, an average illumination of 300 lumen/m² is to be provided on the working plane. The walls and ceiling are brightly painted. Calculate the no. of luminaries required to be fitted in the hall. Draw lay-out diagram showing arrangement of luminaries, switches and distribution board. Decide the light sub-circuits if the supply is 400 V, 3-phase 4 wire system. Assume value for utilization and maintenance factor are 0.8 and 0.8 respectively, the lamp efficiency is 90 lumen/watt.

## Short answer

Mounting height 3 m. N = (300 ×192) / (4950 ×0.64) =20 luminaires in a5 ×4 grid. Distribution board: 6 A TPN MCB incomer, 25 A RCCB, three 6 A SP lighting circuits.

## Answer

**Given:** hall 16 m × 12 m, E = 300 lm/m², 55 W LED at 90 lm/W, UF = 0.8, MF = 0.8, supply 400 V, 3-phase, 4-wire.
**Assumptions:** mounting height 3 m above working plane, SHR ≤ 1.5, pf 0.9.

#### Number of luminaires

Lumen method: N = (E × A) / (φ × UF × MF), where φ is the output of one luminaire.

```text
Area A        = 16 × 12 = 192 m²
φ per luminaire = 55 W × 90 lm/W = 4950 lm
Total lumens  = E × A / (UF × MF)
              = 300 × 192 / (0.8 × 0.8)
              = 90000 lm
N             = 90000 / 4950 = 18.18
```

Rounding up and fitting a regular grid: **5 × 4 = 20 luminaires** (5 along the 16 m side, 4 along the 12 m side).

#### Arrangement and spacing

```text
Spacing along length = 16/5 = 3.2 m
Spacing along width  = 12/4 = 3 m
End spacing (to wall) = half of these
Max spacing = SHR × Hm = 1.5 × 3 = 4.5 m
3.2 m and 3 m ≤ 4.5 m  → OK
Actual E = 20 × 4950 × 0.8 × 0.8 / 192
         = 330 lux (≥ 300 lux required)
```

#### Layout diagram

```text
Plan 16 m × 12 m (letter = phase of lamp circuit)
+-----------+
| R R R R R |
| Y Y Y R R |
| Y Y Y Y B |
| B B B B B |
+-----------+
[DB]  [SB]  <- entrance: DB and switch board
       S S S S ... one switch per sub-circuit
```

Each light sub-circuit is controlled by one 6 A one-way switch; all switches are grouped on a switch board (SB) next to the entrance, and the DB is mounted beside it.

#### Sub-circuits

Rule (IS 732 / NEA practice): a light sub-circuit carries at most 10 points and 800 W. Here one luminaire is 55 W, so up to 10 luminaires per sub-circuit. Number of circuits is made a multiple of 3 for phase balance.

| Circuit | Luminaires | Load (W) | Current (A) | Phase | MCB |
|---|---|---|---|---|---|
| L1 | 7 | 385 | 1.86 | R | 6 A |
| L2 | 7 | 385 | 1.86 | Y | 6 A |
| L3 | 6 | 330 | 1.59 | B | 6 A |

#### Distribution board design

| Phase | Circuits | Load (W) | Current (A) |
|---|---|---|---|
| R | L1 | 385 | 1.86 |
| Y | L2 | 385 | 1.86 |
| B | L3 | 330 | 1.59 |

```text
Total connected load = 1100 W (lighting)
Most loaded phase    = 385 W
Iph = 385 / (230 × 0.9) = 1.86 A
Main MCB ≥ 1.25 × 1.86 = 2.32 A → 6 A TPN MCB
```

**DB specification:** 4-way-per-phase TPN DB (12 ways in all, spares included) with 6 A TPN MCB as incomer, 25 A 4-pole RCCB (100 mA) for earth-leakage protection, 6 A SP MCBs (B-curve) for light circuits. Incoming cable: 4-core 1.5 mm² Cu PVC (rating 21 A ≥ 6 A), plus earth continuity conductor.

```text
3-phase, 400/230 V, 4-wire supply
        |
   [Energy meter]
        |
   [6 A TPN MCB]
        |
   [25 A 4P RCCB]
        |
==R====Y====B====N== busbars
  |    |    |    |    |
  L1   L2   L3  ...
```

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is the light output of one 55 W LED at 90 lm/W?
   A. 55 lm
   B. 990 lm
   C. 4950 lm
   D. 49500 lm
   Answer: C. phi = 55 x 90 = 4950 lm. (Key point: Luminaire output)

2. Total lumens 90000 and 4950 lm per luminaire give 18.18. What is fitted?
   A. 18 luminaires, rounded down
   B. 20 luminaires in a 5 x 4 grid (rounded up)
   C. 100 luminaires
   D. 12 luminaires
   Answer: B. Rounding up to a regular grid gives 5 x 4 = 20, and actual E is 330 lux, above 300 lux required. (Key point: Number of luminaires)

3. How are the 20 luminaires split between sub-circuits?
   A. All on one circuit of 20
   B. 7, 7 and 6 on phases R, Y and B
   C. 10 on R only and 10 on Y only
   D. One per circuit
   Answer: B. One circuit allows at most 10 points, and three circuits balance the phases: 7, 7 and 6 luminaires. (Key point: Sub-circuits and phases)

## Close variants set in other exams

- [Factory hall 15 × 12 m metal halide lighting](https://www.bctengineer.com/question.md?key=semester_6%2Findustrial_power_distribution_and_illumination%3Afactory-hall-metal-halide) — Industrial Power Distribution and Illumination, chapter 7, asked 4×
- [Factory hall 55.75 m × 40.25 m LED lighting](https://www.bctengineer.com/question.md?key=semester_6%2Findustrial_power_distribution_and_illumination%3Afactory-hall-led-55x40) — Industrial Power Distribution and Illumination, chapter 7, asked 4×
- [Production room 27 × 45 m twin 36 W tubes](https://www.bctengineer.com/question.md?key=semester_6%2Findustrial_power_distribution_and_illumination%3Aproduction-room-27x45) — Industrial Power Distribution and Illumination, chapter 7, asked 4×

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