---
title: "CB ratings: 2500 A, 1500 MVA, 33 kV"
subject: "Switchgear and Protection"
chapter: 6
key: "semester_6/switchgear_and_protection:cb-ratings-2500a-1500mva"
source: https://www.bctengineer.com/q/semester_6/switchgear_and_protection/cb-ratings-2500a-1500mva
site: BCT Engineering
---

# CB ratings: 2500 A, 1500 MVA, 33 kV

Switchgear and Protection · Chapter 6: Circuit Breakers

- Asked in: 2070 Bhadra, 2+2+2+2 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/switchgear_and_protection/cb-ratings-2500a-1500mva
- Whole chapter: https://www.bctengineer.com/md/semester_6/switchgear_and_protection/chapter-6

## Question

A circuit breaker is rated as 2500 A, 1500 MVA, 33 KV, 3 sec, 3 phase OCB. Determine (i) the rated symmetrical breaking current (ii) rated making current (iii) short time rating and (iv) rated service voltage.

## Short answer

Rated symmetrical breaking current = 1500/(√3×33) = 26.24 kA rms. Making current = 2.55×26.24 = 66.92 kA peak. Short time rating = 26.24 kA for 3 s. Rated service voltage = 33 kV.

## Answer

The ratings of a CB follow from its breaking MVA and rated voltage.

#### Definitions and formulas used
- **Rated symmetrical breaking current** *I_b* = rated breaking MVA / (√3 × rated line kV), rms.
- **Rated making current** = 1.8 × √2 × *I_b* = **2.55 × *I_b*** (peak), since the first major peak of an asymmetrical current can be 1.8 times the peak of the symmetrical current.
- **Short time rating** = the current the CB can carry while closed for the stated time without damage; it equals *I_b* for the given duration.

#### Given
2500 A, 1500 MVA, 33 kV, 3 s, 3-phase oil CB.

#### (i) Rated symmetrical breaking current
```text
I_b = MVA / (√3 × kV)
    = 1500 / (√3 × 33)
    = 26.24 kA (rms)
```
#### (ii) Rated making current
```text
I_m = 2.55 × I_b
    = 2.55 × 26.24
    = 66.92 kA (peak)
```
#### (iii) Short time rating
```text
= 26.24 kA (rms) for 3 seconds
```
#### (iv) Rated service voltage
```text
= 33 kV (rms, line to line)
```
**Answer: (i) 26.24 kA rms; (ii) 66.92 kA peak; (iii) 26.24 kA for 3 s; (iv) 33 kV rms (line). Rated normal current is 2500 A.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Which formula gives the rated symmetrical breaking current of a 3-phase CB from its MVA rating?
   A. I_b = MVA / kV
   B. I_b = MVA x kV / sqrt(3)
   C. I_b = MVA / (sqrt(3) x line kV)
   D. I_b = MVA x sqrt(3) / kV
   Answer: C. Breaking MVA = sqrt(3) x line kV x I_b, so I_b = MVA / (sqrt(3) x kV). (Key point: Breaking current formula)

2. For 1500 MVA at 33 kV, what is the rated symmetrical breaking current?
   A. 45.5 kA
   B. 26.24 kA
   C. 75.8 kA
   D. 2.5 kA
   Answer: B. 1500 / (1.732 x 33) = 26.24 kA rms. The 2500 A is only the normal rated current. (Key point: Breaking current value)

3. Why is the rated making current taken as 2.55 x I_b?
   A. Because the breaker must carry 2.55 times its normal current
   B. Because the first major peak of an asymmetrical current can be 1.8 times the symmetrical peak, i.e. 1.8 x sqrt(2) x I_b
   C. Because the voltage rises 2.55 times at closing
   D. Because of the 3 s time rating
   Answer: B. Including the DC offset, the first peak is 1.8 x sqrt(2) x I_b = 2.55 I_b (peak). (Key point: Making current)

4. What is the short time rating of this breaker?
   A. 2500 A for 3 s
   B. 66.92 kA for 3 s
   C. 33 kA for 3 s
   D. 26.24 kA rms for 3 s
   Answer: D. The short time rating equals the symmetrical breaking current for the stated duration: 26.24 kA for 3 s. (Key point: Short time rating)

## Related in Switchgear and Protection

- [CB ratings: 33 kV, 1500 A, 3000 MVA](https://www.bctengineer.com/question.md?key=semester_6%2Fswitchgear_and_protection%3Acb-ratings-1500a-3000mva) — Switchgear and Protection, chapter 6
- [Breaking, making, short-time ratings (500 MVA)](https://www.bctengineer.com/question.md?key=semester_6%2Fswitchgear_and_protection%3Acb-ratings-500a-500mva) — Switchgear and Protection, chapter 6
- [Breaking MVA and making kA (800 A, 33 kV)](https://www.bctengineer.com/question.md?key=semester_6%2Fswitchgear_and_protection%3Acb-breaking-making-800a) — Switchgear and Protection, chapter 6
- [CB terms: making, breaking, operating duty](https://www.bctengineer.com/question.md?key=semester_6%2Fswitchgear_and_protection%3Acb-terms-making-breaking-duty) — Switchgear and Protection, chapter 6
- [Selecting CB for 6.6 kV, 650 MVA](https://www.bctengineer.com/question.md?key=semester_6%2Fswitchgear_and_protection%3Aselect-cb-6-6kv-650mva) — Switchgear and Protection, chapter 6

## Related in other subjects

- [Short circuit MVA of feeder circuit breaker](https://www.bctengineer.com/question.md?key=semester_5%2Fpower_system_analysis_ii%3Afeeder-cb-short-circuit-mva) — Power System Analysis II, chapter 3, asked 2×
- [Initial symmetrical current, load short circuit](https://www.bctengineer.com/question.md?key=semester_5%2Fpower_system_analysis_ii%3Ainitial-current-load-short-circuit) — Power System Analysis II, chapter 3
