---
title: "Hair pin bend elements"
subject: "Transportation Engineering I"
chapter: 5
key: "semester_6/transportation_engineering_i:hairpin-elements-derive"
source: https://www.bctengineer.com/q/semester_6/transportation_engineering_i/hairpin-elements-derive
site: BCT Engineering
---

# Hair pin bend elements

Transportation Engineering I · Chapter 5: Hill Roads

- Asked in: 2070 Magh, 8 marks
- Video: [Hairpin Bend Design: Derivation and Road Safety Insights || Transportation Engineering](https://www.youtube.com/watch?v=YOaFKHJcwbM) — OPengineer
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_6/transportation_engineering_i/hairpin-elements-derive
- Whole chapter: https://www.bctengineer.com/md/semester_6/transportation_engineering_i/chapter-5

## Question

What is a hair pin bend? Derive the expression for the elements of symmetrical hair pin bends.

## Short answer

A hairpin bend is a sharp 180-degree turn to gain height. For a symmetrical hairpin with transitions, the tangent length is T_s = (R+s) tan(Δ/2) + L_s/2, central angle Δ_c = Δ - 2θ_s, shift s = L_s²/(24R), and total curve length L = RΔ + L_s with design checks like max superelevation 10%, minimum radius 14 m.

## Answer

#### Hairpin bend
A **hairpin bend** is a sharp bend of about 180 degrees on a hill road that is used to gain height when the road has to turn back along a spur. It consists of a central circular curve (radius $R$, minimum about 14 m as per IRC:SP:48) with a transition curve of length $L_s$ at each end.

#### Symmetrical hairpin with transitions: elements
Let the two straight approaches meet at the apex (intersection point) $I$ with an interior angle $\alpha$. The deflection angle is

$$
\Delta = 180^\circ - \alpha
$$

For a hairpin $\Delta$ is large (about 120 to 180 degrees).

**1. Angle turned through by each transition**

On a spiral the curvature grows linearly with length $l$: $\dfrac{1}{r}=\dfrac{l}{RL_s}$. Since $\dfrac{d\phi}{dl}=\dfrac{1}{r}$, integrating gives $\phi=\dfrac{l^2}{2RL_s}$. At the end of the spiral ($l=L_s$), the spiral angle is

$$
\theta_s = \frac{L_s}{2R} \ \text{(radian)}
$$

**2. Central circular arc angle**

The two transitions together turn through $2\theta_s$, so the circular arc turns through the rest:

$$
\Delta_c = \Delta - 2\theta_s
$$

**3. Shift of the circular curve**

The spiral offset at its end is $y_s \approx \dfrac{L_s^2}{6R}$. The circle, produced back, is at $R(1-\cos\theta_s)\approx \dfrac{R\theta_s^2}{2}=\dfrac{L_s^2}{8R}$ from the tangent. The shift is the difference:

$$
s = \frac{L_s^2}{6R}-\frac{L_s^2}{8R}=\frac{L_s^2}{24R}
$$

**4. Tangent length (from apex $I$ to the start of the transition, $T_s$)**

The shifted circle (radius $R$, centre at $R+s$ from each straight) has a tangent length of $(R+s)\tan\frac{\Delta}{2}$ from $I$. Its point of tangency lies $x_s - R\sin\theta_s \approx L_s - \dfrac{L_s}{2}=\dfrac{L_s}{2}$ ahead of the start of the spiral, so

$$
T_s = (R+s)\tan\frac{\Delta}{2} + \frac{L_s}{2}
$$

**5. Length of the circular arc and total curve length**

$$
L_c = R\,\Delta_c = R\,(\Delta - 2\theta_s)
$$

$$
L = L_c + 2L_s = R\Delta - L_s + 2L_s = R\Delta + L_s
$$

(with $\Delta$ in radians).

**6. External distance (apex distance)**

$$
E = (R+s)\sec\frac{\Delta}{2} - R
$$

**7. Chainages**

$$
\text{Start of curve} = \text{Ch}(I) - T_s,\qquad \text{End of curve} = \text{Start} + L
$$

```text
   straight          apex I
 -----------\       /------
             \  __/
   TS ~~~~~~~ SC  CS ~~~~ ST
              ( R )
```

Note: as $\Delta$ approaches 180°, $\tan\frac{\Delta}{2}$ and $\sec\frac{\Delta}{2}$ become very large, so the apex lies far away. For such bends the curve is set out from its centre or from the tangent points rather than from the apex.

#### Design checks (IRC:SP:48)
Superelevation up to 10% (1 in 10), developed over $L_s$; widening provided on the inner side; gradient on the curve not more than 1 in 40; minimum radius of the inner curve 14 m (IRC); and at least 60 m between consecutive hairpins.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is a hairpin bend?
   A. A gentle 20-degree bend on a plain road
   B. A sharp bend of about 180 degrees used to gain height when the road turns back along a spur
   C. A straight stretch between two valleys
   D. A bend with no circular curve
   Answer: B. A hairpin is a sharp turn of about 180 degrees on hill roads with a central circular curve and transitions at each end, used to gain height. (Key point: Hairpin bend definition)

2. In a symmetrical hairpin with transitions, the central circular arc angle is
   A. Delta + 2 theta_s
   B. Delta - 2 theta_s
   C. Delta / 2
   D. Delta - theta_s
   Answer: B. Each transition turns through theta_s = Ls/(2R), so the circular arc turns through Delta - 2 theta_s. (Key point: Central arc angle)

3. What is the shift of the circular curve for a spiral of length Ls and radius R?
   A. s = Ls^2/(24R)
   B. s = Ls/(2R)
   C. s = Ls^2/(6R)
   D. s = R^2/(24 Ls)
   Answer: A. The shift is s = Ls^2/(24R); Ls/(2R) is the spiral angle, not the shift. (Key point: Shift of curve)

4. The tangent length from the apex I to the start of the transition is
   A. R tan(Delta/2)
   B. (R + s) tan(Delta/2) + Ls/2
   C. (R - s) tan(Delta/2) - Ls/2
   D. (R + s) sec(Delta/2) - R
   Answer: B. The tangent to the shifted circle is (R+s)tan(Delta/2), and the spiral offset Ls/2 is added; the last option is the external distance E. (Key point: Tangent length)

## Related in Transportation Engineering I

- [Short note: hairpin bends](https://www.bctengineer.com/question.md?key=semester_6%2Ftransportation_engineering_i%3Ahairpin-bend) — Transportation Engineering I, chapter 5, asked 4×
- [Derivation of superelevation expression](https://www.bctengineer.com/question.md?key=semester_6%2Ftransportation_engineering_i%3Asuper-derive) — Transportation Engineering I, chapter 3, asked 7×

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