---
title: "Biaxial column 500x600, 1300 kN"
subject: "Design of RCC Structure"
chapter: 10
key: "semester_7/design_of_rcc_structure:biaxial-column-500x600-1300-kn"
source: https://www.bctengineer.com/q/semester_7/design_of_rcc_structure/biaxial-column-500x600-1300-kn
site: BCT Engineering
---

# Biaxial column 500x600, 1300 kN

Design of RCC Structure · Chapter 10: Design of compression members: Columns

- Asked in: 2075 Asoj, 15 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/design_of_rcc_structure/biaxial-column-500x600-1300-kn
- Whole chapter: https://www.bctengineer.com/md/semester_7/design_of_rcc_structure/chapter-10

## Question

Determine the longitudinal and transverse reinforcement in bi-axially loaded column having the following parameters: Unsupported length of column = 3.10 m; Size of column = 500 mm x 600 mm; Factored moment, $M_{ux}$ = 125 kN.m; Factored load, $P_u$ = 1300 kN; Factored moment, $M_{uy}$ = 200 kN.m. Use M25 concrete and Fe 500 steel. Take reinforcement in four side. Sketch the details.

## Short answer

Short column; no slenderness effect. Use 12-16 mm bars (p=0.80%) and 8 mm ties @250 mm c/c; biaxial interaction ratio is 0.796, so safe.

## Answer

#### Data and assumptions
- Column 500 mm (width $b$) × 600 mm (depth $D$); $P_u = 1300$ kN; $f_{ck} = 25$ MPa, $f_y = 500$ MPa. Clear cover 40 mm (IS 456 cl. 26.4.2.1), 8 mm ties.
- Moments: about major axis (x-x) $M_{ux}$ = 125 kN·m; about minor axis (y-y) $M_{uy}$ = 200 kN·m.
- Sizes are given as $b \times D$ with $D \ge b$; moments $M_{ux}$ act about the major axis (depth $D$) and $M_{uy}$ about the minor axis (depth $b$).

#### Slenderness

| Axis | $l_e$ (mm) | Dimension (mm) | $l_e/$dim | Type |
|---|---|---|---|---|
| x-x (about major) | 3100 | 600 | 5.17 | short |
| y-y (about minor) | 3100 | 500 | 6.20 | short |

Both ratios are below 12, so the column is **short**; no additional moment is required.

#### Minimum eccentricity (cl. 25.4)
$$
e_{min} = \max\left(\frac{L}{500} + \frac{D}{30},\ 20\right)
$$
- About x-x: $e_x = 3100/500 + 600/30 = 26.2$ mm (min. 20 mm); adopt 26.2 mm; $M_{ux,min} = P_u e = 34.1$ kN·m
- About y-y: $e_y = 3100/500 + 500/30 = 22.9$ mm (min. 20 mm); adopt 22.9 mm; $M_{uy,min} = 29.7$ kN·m

#### Design moments
- Design moments: $M_{ux} = 125.0$ kN·m, $M_{uy} = 200.0$ kN·m (not less than the minimum-eccentricity values).

#### Longitudinal reinforcement
$\dfrac{P_u}{f_{ck} b D} = \dfrac{1300000}{25 \times 500 \times 600} = 0.173$
Bars are chosen so that $p$ lies between 0.8% (minimum) and 4% (practical maximum; IS 456 cl. 26.5.3.1 allows 6%). The uniaxial capacities $M_{ux1}$, $M_{uy1}$ at $P_u$ are read from the SP-16 interaction charts for rectangular sections; here they are computed by strain compatibility with the IS 456 stress block and the design stress-strain curve of steel (same basis as the charts), with effective cover $d' = 40 + 8 + \phi/2$.

| Trial | $p$ (%) | $d'/D$ | $M_{ux1}$ | $M_{uy1}$ | $P_u/P_{uz}$ | $\alpha_n$ | $(M_{ux}/M_{ux1})^{\alpha_n}+(M_{uy}/M_{uy1})^{\alpha_n}$ |
|---|---|---|---|---|---|---|---|
| 12-16 φ | 0.80 | 0.093 | 409.9 | 333.0 | 0.306 | 1.18 | 0.796 ✓ |

#### Check
$P_{uz} = 0.45 f_{ck} A_c + 0.75 f_y A_{sc} = 0.45 \times 25 \times 297587 + 0.75 \times 500 \times 2413 = 4253$ kN
$\dfrac{P_u}{P_{uz}} = \dfrac{1300}{4253} = 0.306$, so $\alpha_n = 1.18$ (IS 456 cl. 39.6; linear between 1.0 at 0.2 and 2.0 at 0.8).
$$
\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} = \left(\frac{125.0}{409.9}\right)^{1.18} + \left(\frac{200.0}{333.0}\right)^{1.18} = 0.796 \le 1.0
$$
The interaction condition is satisfied; the section is **safe**.

Provide **12-16 mm** bars ($A_{sc} = 2413$ mm², $p = 0.80\%$), within 0.8% to 4%.

#### Lateral ties
- Diameter $\ge \max(\phi_{max}/4,\ 6) = \max(16/4, 6) = 6$ mm → provide 8 mm.
- Pitch $\le \min$(least lateral dimension, $16\phi_{min}$, 300 mm) $= \min(500, 256, 300) = 256$ mm → provide 8 mm ties @ 250 mm c/c.

#### Detailing
```text
CROSS-SECTION 500 x 600
    +-------------------------+
    |  o      o     o      o  |
    |                         |
    |                         |
    |  o                   o  |
    |                         |
    |                         |
    |                         |
    |  o                   o  |
    |                         |
    |                         |
    |  o      o     o      o  |
    +-------------------------+
   o = 16 mm bars, ties 8 mm @ 250 c/c
```

**Answer:** 500 × 600 mm column with 12-16 mm longitudinal bars ($p = 0.80\%$) and 8 mm ties @ 250 mm c/c.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Which moment acts about the major axis in this column?
   A. Muy = 200 kN·m
   B. Mux = 125 kN·m, about the axis with depth 600 mm
   C. Both act about the minor axis
   D. Mux = 200 kN·m
   Answer: B. Mux = 125 kN·m acts about the major axis (depth 600 mm) and Muy = 200 kN·m about the minor axis (depth 500 mm). (Key point: Moment axes)

2. Which steel percentage limit governs the choice of 12-16φ (p = 0.80%)?
   A. Maximum 6%
   B. Minimum 0.8% of gross area
   C. Minimum 2%
   D. Maximum 0.8%
   Answer: B. IS 456 requires at least 0.8% longitudinal steel in columns, and 12-16φ just meets it. (Key point: Minimum steel)

3. What is Pu/Puz and what does it decide?
   A. 1300/4253 = 0.306, giving αn = 1.18
   B. 4253/1300 = 3.27, giving αn = 3.27
   C. 0.173, giving αn = 1.0
   D. 0.806, giving αn = 2.0
   Answer: A. Pu/Puz = 1300/4253 = 0.306; interpolating between 0.2 and 0.8 gives αn about 1.18. (Key point: Pu/Puz ratio)

4. Why is the tie pitch 250 mm for this column?
   A. Least lateral dimension 500 mm governs
   B. 16 x 16 = 256 mm is the smallest limit, so 250 mm is used
   C. 300 mm is the smallest limit
   D. It is 8 x bar diameter
   Answer: B. Pitch must not exceed the least of 500, 16 x 16 = 256 and 300 mm, so 250 mm is adopted. (Key point: Tie pitch)

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