---
title: "Materials for brickwork 1:4 (230×110×55)"
subject: "Estimating and Costing"
chapter: 4
key: "semester_7/estimating_and_costing:materials-brick-1-4-sizes"
source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-1-4-sizes
site: BCT Engineering
---

# Materials for brickwork 1:4 (230×110×55)

Estimating and Costing · Chapter 4: Analysis of Rates

- Asked in: 2071 Chaitra, 6 marks
- Video: [How to calculate Quantity of Cement, Sand & Bricks in Brick work | Brick Quantity calculation](https://www.youtube.com/watch?v=YEvkOcPFjfA) — SOLITUDE EDUCATION 
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-1-4-sizes
- Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-4

## Question

Prepare materials required for an item of brickwork in cement mortar (1:4). Size of brick is 230 mm × 110 mm × 55 mm, with mortar joint 10 mm.

## Short answer

Brick 230x110x55 mm, mortar 10 mm gives 534 bricks per m³ with mortar. Per m³: 535 bricks, 1.88 bags cement, 0.261 m³ sand. Per 10 m³: 5,342 bricks, 18.8 bags cement, 2.61 m³ sand.

## Answer

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags of 50 kg; no wastage is added. The volume of brickwork is not stated, so quantities are found per 1 m³ and per 10 m³.

**Per 1 m³ brickwork**
- Brick with mortar $= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6}$ m³; bricks per m³ $= 1/1872.0\times10^6 = 534.19$
- Bricks for 1.00 m³ $= 534.19 \times 1.00 = 534$ nos (say 535)
- Volume of bricks only $= 0.230\times0.110\times0.055 = 1391.5\times10^{-6}$ m³ each; wet mortar per m³ $= 1 - 534.19\times1391.5\times10^{-6} = 0.2567$ m³
- Wet mortar for 1.00 m³ $= 0.257$ m³; dry $= 1.27\times0.257 = 0.326$ m³
- Cement $= 1/5\times0.326 = 0.065$ m³ $= 1.9$ bags
- Sand $= 4/5\times0.326 = 0.261$ m³

**Per 10 m³ brickwork**
- Brick with mortar $= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6}$ m³; bricks per m³ $= 1/1872.0\times10^6 = 534.19$
- Bricks for 10.00 m³ $= 534.19 \times 10.00 = 5,342$ nos (say 5,342)
- Volume of bricks only $= 0.230\times0.110\times0.055 = 1391.5\times10^{-6}$ m³ each; wet mortar per m³ $= 1 - 534.19\times1391.5\times10^{-6} = 0.2567$ m³
- Wet mortar for 10.00 m³ $= 2.567$ m³; dry $= 1.27\times2.567 = 3.260$ m³
- Cement $= 1/5\times3.260 = 0.652$ m³ $= 18.8$ bags
- Sand $= 4/5\times3.260 = 2.608$ m³

**Answer: per m³ about 535 bricks, 1.88 bags cement, 0.261 m³ sand; per 10 m³: 5,342 bricks, 18.8 bags cement, 2.61 m³ sand.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Cement fraction for 1:4?
   A. 1/4
   B. 1/3
   C. 1/5
   D. 4/5
   Answer: C. 1+4 = 5. (Key point: Ratio sum)

2. Bricks per m^3?
   A. About 678
   B. About 535
   C. About 1,000
   D. About 400
   Answer: B. 1/1872e-6. (Key point: Bricks)

3. Cement per m^3?
   A. About 1.88 bags
   B. About 2.4
   C. About 13
   D. About 0.9
   Answer: A. 0.326/5 x 28.8. (Key point: Cement bags per m^3)

4. Why 1 and 10 m^3?
   A. Size not stated
   B. Ratio not stated
   C. Rates not given
   D. Brickwork volume not stated
   Answer: D. Scaling. (Key point: Volume)

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