---
title: "Materials: 10 m³ brick 1:4, 100 m³ PCC 1:3:6"
subject: "Estimating and Costing"
chapter: 4
key: "semester_7/estimating_and_costing:materials-brick-pcc-v"
source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-pcc-v
site: BCT Engineering
---

# Materials: 10 m³ brick 1:4, 100 m³ PCC 1:3:6

Estimating and Costing · Chapter 4: Analysis of Rates

- Asked in: 2065 Shrawan (old course), 5×2 marks
- Video: [Calculation of Cement, Sand and Aggregate for 1 Cubic Meter PCC | Concrete Ratio M10 (1:3:6) | Ci...](https://www.youtube.com/watch?v=Kn5sSMeyOg4) — CIVIL ENGINEER MUNTAZIR
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-pcc-v
- Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-4

## Question

Calculate the quantities of materials required for i) 10 m³ brick masonry in 1:4 cement mortar ii) 100 m³ PCC 1:3:6 in foundation.

## Short answer

For 10 m3 brickwork in 1:4, using 230x110x55 mm bricks with joints: bricks 5,342, cement 18.8 bags, sand 2.61 m3. For 100 m3 PCC 1:3:6, dry volume 154 m3: cement 443.5 bags, sand 46.2 m3, coarse aggregate 92.4 m3.

## Answer

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags. The brick size is not given, so 230 × 110 × 55 mm bricks with 10 mm joints are assumed.

#### (i) 10 m³ brickwork in 1:4 cement mortar

- Volume of one brick with mortar $= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6}$ m³; bricks per m³ $= 1/(1872.0\times10^{-6}) = 534.19$
- Bricks for 10.00 m³ $= 534.19 \times 10.00 = 5,342$ nos
- Volume of one brick alone $= 0.230\times0.110\times0.055 = 1391.5\times10^{-6}$ m³; wet mortar per m³ $= 1 - 534.19\times1391.5\times10^{-6} = 0.2567$ m³
- Wet mortar for 10.00 m³ $= 2.567$ m³; dry volume $= 1.27\times2.567 = 3.260$ m³
- Cement $= 1/5\times3.260 = 0.652$ m³ $= 0.652 \times 28.8 = 18.8$ bags
- Sand $= 4/5\times3.260 = 2.608$ m³

#### (ii) 100 m³ PCC (1:3:6) in foundation

- Wet volume $= 100.000$ m³; dry volume $= 1.54 \times 100.000 = 154.000$ m³ (sum of ratio $= 1 + 3 + 6 = 10$)
- Cement $= 1/10 \times 154.000 = 15.400$ m³ $= 15.400 \times 28.8 = 443.5$ bags (50 kg)
- Sand $= 3/10 \times 154.000 = 46.200$ m³
- Coarse aggregate $= 6/10 \times 154.000 = 92.400$ m³

**Answer: (i) bricks 5,342 nos, cement 18.8 bags, sand 2.61 m³. (ii) cement 443.5 bags, sand 46.20 m³, coarse aggregate 92.40 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. For 10 m3 brickwork in 1:4 mortar, what fraction of the dry mortar is cement?
   A. 1/4, giving 0.815 m3
   B. 1/3, giving 1.087 m3
   C. 1/4 of the wet mortar volume
   D. 1/5, since the sum of ratio is 5; cement = 0.652 m3 = 18.8 bags
   Answer: D. Cement fraction is 1/(1+4); dry mortar is 3.26 m3. (Key point: Cement in 1:4 mortar)

2. How many bricks are needed for 10 m3 of brickwork here?
   A. About 5,342 (534.19 per m3 from the brick with mortar size)
   B. About 4,000
   C. About 6,800
   D. About 3,260
   Answer: A. 1 m3 divided by 0.24 x 0.12 x 0.065 m3 = 534.19 per m3. (Key point: Bricks)

3. What are the cement, sand and aggregate for 100 m3 of PCC 1:3:6?
   A. Cement 44.4 bags, sand 46.2 m3, aggregate 92.4 m3
   B. Cement 443.5 bags, sand 46.2 m3, aggregate 92.4 m3
   C. Cement 443.5 bags, sand 92.4 m3, aggregate 46.2 m3
   D. Cement 633.6 bags, sand 44 m3, aggregate 88 m3
   Answer: B. Dry 154 m3: cement 15.4 m3 x 28.8 = 443.5 bags; sand 3/10 and aggregate 6/10. (Key point: PCC 1:3:6 for 100 m3)

## Close variants set in other exams

- [Materials: 10 m³ brick 1:6, 10 m³ PCC 1:3:6](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-pcc-10m3-s) — Estimating and Costing, chapter 4, asked 2×

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