---
title: "Materials for brick wall 10 m (1:5)"
subject: "Estimating and Costing"
chapter: 4
key: "semester_7/estimating_and_costing:materials-brick-wall-10m-1-5"
source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-wall-10m-1-5
site: BCT Engineering
---

# Materials for brick wall 10 m (1:5)

Estimating and Costing · Chapter 4: Analysis of Rates

- Asked in: 2081 Bhadra, 5 marks
- Video: [Brick Quantity calculation for house | How to calculate sand & Cement for Brick work By CivilGuruji](https://www.youtube.com/watch?v=bFY5ZaOrY7U) — The Institute of Construction Managment 
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-wall-10m-1-5
- Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-4

## Question

Calculate quantities of material required for brick wall of a building L × B × H = 10 m × 0.23 m × 3 m with 10 mm thick in (1:5) cement sand mortar. The wall contains two windows of size 1.2 m × 1.2 m. Take standard size of brick.

## Short answer

Net masonry volume is 6.238 m3 after deducting openings. Using nominal brick size 240x120x65 mm and a 1:5 mortar, materials required: bricks 3332 nos., cement 9.99 bags (0.347 m3), sand 1.734 m3.

## Answer

#### Net volume of masonry
- Gross volume = 10 x 0.23 x 3 = 6.900 m³
- Openings = 2 x 1.2 x 1.2 x 0.23 = 0.6624 m³
- Net volume = 6.900 - 0.6624 = 6.2376 m³

#### Bricks
Using the standard brick 230 x 110 x 55 mm with 10 mm mortar joints, the nominal size is 240 x 120 x 65 mm.
$$
\text{Bricks per m}^3 = \frac{1}{0.240 \times 0.120 \times 0.065} = 534.19
$$
Number of bricks = 534.19 x 6.2376 = **3332 nos.** (about 3499 nos. with 5% wastage).

#### Mortar (1:5)
- Volume of bricks without mortar = 3332 x 0.23 x 0.11 x 0.055 = 4.6365 m³
- Wet mortar = 6.2376 - 4.6365 = 1.6011 m³
- Dry mortar = 1.6011 x 1.30 = 2.0814 m³
- Cement = 2.0814/6 = 0.3469 m³ = 499.5 kg = **9.99 bags** (50 kg)
- Sand = 2.0814 x 5/6 = **1.734 m³**

**Answer: Bricks = 3332 nos.; cement = 9.99 bags (0.347 m³); sand = 1.734 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. How is net masonry volume found?
   A. Gross volume plus openings
   B. Gross volume only
   C. Gross volume minus volume of openings
   D. Openings only
   Answer: C. Windows are deducted. (Key point: Net volume)

2. How is number of bricks found?
   A. Gross volume x 534
   B. Net volume / 534
   C. Mortar x 534
   D. Bricks per m³ x net volume
   Answer: D. Bricks per m³ times net volume. (Key point: Bricks count)

3. How is wet mortar found?
   A. Net masonry volume minus volume of bricks alone
   B. Dry mortar x 1.3
   C. Net volume x 0.5
   D. Bricks x 1.3
   Answer: A. Remaining volume is mortar. (Key point: Wet mortar)

4. How to split dry mortar for 1:5?
   A. Cement = dry/5
   B. Cement = dry/6, sand = dry x 5/6
   C. Cement = dry/4
   D. Cement = dry x 5/6
   Answer: B. Ratio sum is 6. (Key point: Cement and sand)

## Close variants set in other exams

- [Materials for brick wall 20 m (1:5)](https://www.bctengineer.com/question.md?key=semester_7%2Festimating_and_costing%3Amaterials-brick-wall-20m) — Estimating and Costing, chapter 4, asked 2×

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