---
title: "Materials for brick wall, two windows 1.5 m"
subject: "Estimating and Costing"
chapter: 4
key: "semester_7/estimating_and_costing:materials-brick-wall-windows-1-5"
source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-wall-windows-1-5
site: BCT Engineering
---

# Materials for brick wall, two windows 1.5 m

Estimating and Costing · Chapter 4: Analysis of Rates

- Asked in: 2080 Bhadra, 5 marks
- Video: [1) Brickwork Calculation & Cost Estimation with Deduction. Brick, Cement, Sand Calculation with E...](https://www.youtube.com/watch?v=H_vfETZm9Kc) — Civil with Sujit
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-brick-wall-windows-1-5
- Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-4

## Question

Find out quantities of materials required for brick wall of size (10 m × 3 m × 0.23 m) which has two windows of size (1.5 m × 1.5 m). Take average size of brick (230 mm × 115 mm × 55 mm), mortar thickness of 12 mm and mortar of (1:5) cement sand ratio.

## Short answer

Net volume after openings is 5.865 m3. Using average brick nominal size 242x127x67 mm with 12 mm mortar, quantities: bricks 2848 nos., cement 10.74 bags (0.373 m3), sand 1.865 m3.

## Answer

#### Net volume of masonry
- Gross volume = 10 x 0.23 x 3 = 6.900 m³
- Openings = 2 x 1.5 x 1.5 x 0.23 = 1.0350 m³
- Net volume = 6.900 - 1.0350 = 5.8650 m³

#### Bricks
Using the average brick 230 x 115 x 55 mm with 12 mm mortar joints, the nominal size is 242 x 127 x 67 mm.
$$
\text{Bricks per m}^3 = \frac{1}{0.242 \times 0.127 \times 0.067} = 485.63
$$
Number of bricks = 485.63 x 5.8650 = **2848 nos.** (about 2991 nos. with 5% wastage).

#### Mortar (1:5)
- Volume of bricks without mortar = 2848 x 0.23 x 0.115 x 0.055 = 4.1431 m³
- Wet mortar = 5.8650 - 4.1431 = 1.7219 m³
- Dry mortar = 1.7219 x 1.30 = 2.2384 m³
- Cement = 2.2384/6 = 0.3731 m³ = 537.2 kg = **10.74 bags** (50 kg)
- Sand = 2.2384 x 5/6 = **1.865 m³**

**Answer: Bricks = 2848 nos.; cement = 10.74 bags (0.373 m³); sand = 1.865 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. Net masonry volume?
   A. 6.9 m³
   B. 5.865 m²
   C. 6.9 - 1.035 = 5.865 m³
   D. 1.035 m³
   Answer: C. Two 1.5x1.5x0.23 openings deducted. (Key point: Net volume)

2. Nominal size with 12 mm joints?
   A. 230 x 115 x 55
   B. 240 x 120 x 65
   C. 242 x 115 x 55
   D. 242 x 127 x 67 mm
   Answer: D. Add 12 mm to each dimension. (Key point: Brick with mortar)

3. Bricks per m³?
   A. 485.63
   B. 534.19
   C. 718
   D. 400
   Answer: A. 1/(0.242x0.127x0.067). (Key point: Brick count)

4. Cement for 1:5 from dry mortar 2.238 m³?
   A. 2.238/5
   B. 2.238/6 = 0.373 m³ = 10.74 bags
   C. 2.238 x 5/6
   D. 2.238/7
   Answer: B. Ratio sum 6. (Key point: Cement)

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