---
title: "Materials for 5 m³ stone masonry 1:6"
subject: "Estimating and Costing"
chapter: 4
key: "semester_7/estimating_and_costing:materials-stone-masonry-5m3"
source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-stone-masonry-5m3
site: BCT Engineering
---

# Materials for 5 m³ stone masonry 1:6

Estimating and Costing · Chapter 4: Analysis of Rates

- Asked in: 2081 Baisakh, 5 marks
- Video: [how to calculate cement sand and stone in wall  /quantity of cement sand and stone in stone masonary](https://www.youtube.com/watch?v=yNWz1YBDHSU) — Aim 2 Civil Class
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/materials-stone-masonry-5m3
- Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-4

## Question

Calculate quantity of materials required for 5 m³ of stone masonry in 1:6 cement sand mortar ratios.

## Short answer

Stone required is 1.2 times masonry volume, and wet mortar is 30% of masonry, dry factor 1.30. For 5 m3, stone = 6.0 m3, cement = 8.0 bags (0.279 m3), sand = 1.67 m3.

## Answer

#### Assumptions
For rubble stone masonry in cement mortar: stone required = 1.2 m³ per m³ of masonry (stone is measured as stacked volume, which includes voids, plus an allowance for wastage); wet mortar = 30% of the masonry volume; and dry volume of mortar = 1.30 x wet volume.

#### Calculation for 5 m³
- Stone = 1.2 x 5 = **6.00 m³**
- Wet mortar = 0.30 x 5 = 1.50 m³
- Dry mortar = 1.50 x 1.30 = 1.950 m³
- Mortar ratio 1:6 (sum 7):
  - Cement = 1.950/7 = 0.2786 m³ x 1,440 kg/m³ = 401.1 kg = **8.02 bags** (50 kg)
  - Sand = 1.950 x 6/7 = **1.671 m³**

**Answer: Stone = 6.0 m³; cement = 8.0 bags (0.279 m³); sand = 1.67 m³.**

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. How much stone is taken for 5 m^3 of rubble masonry?
   A. 5.00 m^3, equal to the masonry volume
   B. 1.50 m^3, equal to the wet mortar
   C. 6.00 m^3, at 1.2 m^3 per m^3 of masonry
   D. 7.80 m^3, using the dry factor 1.30
   Answer: C. Stone required is taken as 1.2 m^3 per m^3 of masonry, so 1.2 x 5 = 6.00 m^3. (Key point: Stone quantity)

2. How is the dry mortar volume obtained?
   A. 30% x 5 x 1.54 = 2.31 m^3
   B. Wet mortar (30% of masonry = 1.50 m^3) x 1.30 = 1.950 m^3
   C. 5 x 1.2 x 1.30 = 7.8 m^3
   D. Wet mortar 1.50 m^3 divided by 1.30 = 1.154 m^3
   Answer: B. Wet mortar is 30% of 5 m^3 = 1.5 m^3, and the dry volume is 1.30 times this = 1.950 m^3. (Key point: Dry mortar volume)

3. For mortar 1:6 and dry volume 1.950 m^3, what are cement and sand volumes?
   A. Cement 1.950/7 = 0.2786 m^3; sand 1.950 x 6/7 = 1.671 m^3
   B. Cement 1.950/6 = 0.325 m^3; sand 1.625 m^3
   C. Cement 1.950/7 = 0.2786 m^3; sand 1.950 x 7/6 = 2.275 m^3
   D. Cement 1.950 x 1/6 = 0.325 m^3; sand 1.950 x 5/6 = 1.625 m^3
   Answer: A. The parts sum to 1+6 = 7, so cement is 1/7 and sand 6/7 of the dry mortar. (Key point: Cement and sand split)

4. Cement is 0.2786 m^3 at 1,440 kg/m^3. How many 50 kg bags?
   A. About 0.28 bags
   B. About 80.2 bags
   C. About 5.6 bags
   D. About 8.02 bags (401.1 kg / 50)
   Answer: D. Mass = 0.2786 x 1,440 = 401.1 kg, and dividing by 50 kg gives 8.02 bags. (Key point: Cement bags)

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