--- title: "Quantity sheet and abstract for residential building" subject: "Estimating and Costing" chapter: 2 key: "semester_7/estimating_and_costing:quantity-sheet-abstract-residential" source: https://www.bctengineer.com/q/semester_7/estimating_and_costing/quantity-sheet-abstract-residential site: BCT Engineering --- # Quantity sheet and abstract for residential building Estimating and Costing · Chapter 2: Method of Estimating - Asked in: 2071 Chaitra, 3 marks - Video: [Basic Concept Of Estimation And Costing How To Make Measurement Sheet In Excel #estimationandcosting](https://www.youtube.com/watch?v=3_7-mrmf6YA) — Kayi Engineers - Civil Engineering Concepts - Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14 - Page: https://www.bctengineer.com/q/semester_7/estimating_and_costing/quantity-sheet-abstract-residential - Whole chapter: https://www.bctengineer.com/md/semester_7/estimating_and_costing/chapter-2 ## Question Prepare tables of quantity sheet and abstract of cost for a residential building. ## Short answer Based on centre line length 14.92 m, quantities: excavation 13.43 m³, PCC 2.01 m³, foundation brickwork 3.92 m³, net superstructure brickwork 9.48 m³, plaster 85.98 m², flooring 12 m². Abstract cost: Rs 287,293 (illustrative rates). ## Answer Assumed: a single-room residential building, clear size 4 m x 3 m, 230 mm brick walls, 3.0 m high, one door 1.0 x 2.1 m and one window 1.2 x 1.2 m; trench 0.9 m wide x 1.0 m deep; centre line length $L = 2(4.23 + 3.23) = 14.92$ m. #### Quantity sheet (detailed measurement) | Item | No. | L (m) | B (m) | H (m) | Quantity | |---|---|---|---|---|---| | Excavation | 1 | 14.92 | 0.90 | 1.00 | 13.43 m³ | | PCC 1:3:6 | 1 | 14.92 | 0.90 | 0.15 | 2.01 m³ | | Brickwork in foundation and plinth | 1 | 14.92 | 0.35 | 0.75 | 3.92 m³ | | DPC | 1 | 14.92 | 0.23 | - | 3.43 m² | | Brickwork in superstructure | 1 | 14.92 | 0.23 | 3.00 | 10.29 m³ | | Deduct door | -1 | 1.00 | 0.23 | 2.10 | -0.48 m³ | | Deduct window | -1 | 1.20 | 0.23 | 1.20 | -0.33 m³ | | Net superstructure brickwork | | | | | 9.48 m³ | | Plaster inside 2(4+3) x 3 (no deduction, see note) | | | | | 42.00 m² | | Plaster outside 2(4.46+3.46) x 3 less openings 3.54 | | | | | 43.98 m² | | Flooring | 1 | 4.0 | 3.0 | - | 12.00 m² | Note: both openings (2.10 m² and 1.44 m²) are between 0.5 and 3 m², so as per IS 1200 they are deducted from one face only (here the outside), and the reveals are not added. Total plaster = 42.00 + 43.98 = 85.98 m². #### Abstract of cost (rates illustrative) | SN | Item | Qty | Unit | Rate (Rs) | Amount (Rs) | |---|---|---|---|---|---| | 1 | Excavation | 13.43 | m³ | 600 | 8,058 | | 2 | PCC 1:3:6 | 2.01 | m³ | 11,500 | 23,115 | | 3 | Brickwork 1:6 in foundation | 3.92 | m³ | 14,000 | 54,880 | | 4 | DPC | 3.43 | m² | 650 | 2,230 | | 5 | Brickwork 1:6 in superstructure | 9.48 | m³ | 15,500 | 146,940 | | 6 | Plaster 12.5 mm, both faces | 85.98 | m² | 480 | 41,270 | | 7 | Flooring | 12.00 | m² | 900 | 10,800 | | | **Total** | | | | **287,293** | Contingency, VAT and the other items (RCC slab, roofing, doors, painting) would be added in the same way. ## Check yourself The answer's key points as multiple-choice questions, with the correct option and why. 1. In the example, the centre-line length is 2(4.23 + 3.23). Why is 4.23 used for the 4 m clear side? A. Clear size plus wall thickness (4 + 0.23) gives the centre-to-centre length B. Clear size minus wall thickness C. Clear size alone D. Clear size plus twice the wall thickness Answer: A. The centre line runs along the middle of the wall, so each side is the clear size plus one wall thickness. (Key point: Centre-line length) 2. Why are the door and window volumes deducted from the superstructure brickwork? A. Doors and windows are paid at a higher rate B. The openings have no brickwork, so the quantity is measured net C. To account for mortar wastage D. Because they are plastered separately Answer: B. Quantities are measured net, so 10.29 - 0.48 - 0.33 = 9.48 m3. (Key point: Deductions) 3. How is the DPC quantity (3.43 m2) found? A. Length x width x height of wall B. Floor area 4 x 3 C. Centre-line length x wall width (14.92 x 0.23) D. Wall height x wall width Answer: C. DPC is a layer measured in area: length x width, with no height. (Key point: DPC quantity) 4. How is the amount for PCC 1:3:6 (Rs 23,115) obtained in the abstract? A. Quantity + rate B. Quantity x 600 C. Quantity / rate D. Quantity x rate = 2.01 x 11,500 Answer: D. Amount in an abstract is quantity multiplied by the unit rate. 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