---
title: "Forebay design procedure"
subject: "Hydropower Engineering"
chapter: 6
key: "semester_7/hydropower_engineering:forebay-design-procedure"
source: https://www.bctengineer.com/q/semester_7/hydropower_engineering/forebay-design-procedure
site: BCT Engineering
---

# Forebay design procedure

Hydropower Engineering · Chapter 6: Water Conveyance Structures

- Asked in: 2081 Baishakh, 4 marks; 2073 Shrawan, 3 marks (asked 2 times)
- Video: [Design of Forebay || Hydropower Engineering Numerical](https://www.youtube.com/watch?v=wBR0XxeCHEw) — OPengineer
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/hydropower_engineering/forebay-design-procedure
- Whole chapter: https://www.bctengineer.com/md/semester_7/hydropower_engineering/chapter-6

## Question

Describe the design procedure of a forebay (write the procedure to compute the dimensions of the forebay and the equations used for such purpose) with a neat sketch.

## Short answer

Volume V = Q·t (t≈2–3 min). Area A = Q/v with v ≤ 0.3 m/s. Depth H = S + D + clearance; submergence S = C·Vp·√D (C=0.5434 symmetrical, 0.7245 asymmetrical). Width B = A/H, length L = V/A (L/B~2–4). Spillway Q = C·L·h^(3/2) with C≈1.7 for full turbine flow. Freeboard and flushing gate.

## Answer

A **forebay** is a small reservoir at the end of the headrace (canal or tunnel) from which the penstock takes off. It stores water to meet sudden load demand, provides the transition from open-channel flow to pressure flow, and provides a place for the trash rack, the spillway and sediment flushing.

#### Design procedure
1. **Decide the discharge and retention time**: $Q$ = turbine discharge; the retention time $t$ is usually 2-3 minutes at full load.
2. **Volume of storage**: $V=Q\,t$
3. **Cross-section**: limit the velocity in the forebay to $v\le0.2-0.3$ m/s, so that sediment settles and the flow is calm: $A=Q/v$
4. **Water depth** from the submergence of the penstock intake:
   - velocity in the penstock, $V_p=\dfrac{Q}{n\,\frac{\pi}{4}D^2}$ ($n$ = number of penstocks)
   - Gordon's formula $S=C\,V_p\sqrt D$ ($C=0.5434$ for a symmetrical approach and 0.7245 for an asymmetrical approach)
   - depth $H=S+D+$ bottom clearance (0.3-0.5 m)
5. **Width and length**: $B=\dfrac{A}{H}$ and $L=\dfrac{V}{A}$ (check that $L/B$ is large enough, around 2-4, with a gradual expansion from the headrace).
6. **Spillway**: to pass the full design discharge when the turbines trip, $Q=C\,L_s\,h^{3/2}$ with $C\approx1.7$ for a broad crest and $h=0.3-0.5$ m.
7. **Free board** (0.5 m), a bottom slope towards a **flushing gate**, a trash rack at the intake and an air vent behind the penstock gate.
8. **Check** the entrance loss, and set the top of the forebay wall at full supply level + surge + free board.

#### Sketch
```text
PLAN
 headrace ====> \  forebay  /|==> penstock
        transition| rack     |
 ====>           /           |==> penstock
              spillway  |  flush gate
                        v to river

SECTION
 FSL ~~~~~~~~~~~~~~~~~~~~~~~~~~
      |      S      |rack|gate
      |             |####|  ___ penstock crown
 bed  |_____________|####|_/ D
        0.5 m clearance
```

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. How is the forebay storage volume determined?
   A. V = Q t with retention time of 2-3 minutes at full load
   B. V = Q/v
   C. V = H B L from the penstock diameter
   D. V = Q h^(3/2)
   Answer: A. The forebay must hold enough water to meet sudden load demand, so V = Q x t with t about 2-3 min. (Key point: Forebay storage volume)

2. Why is the forebay velocity limited to 0.2-0.3 m/s?
   A. To maximise head loss
   B. So flow is calm and sediment can settle; A = Q/v
   C. To keep the penstock full
   D. To prevent water hammer
   Answer: B. Low velocity gives calm flow, lets sediment settle, and A = Q/v sets the cross-sectional area. (Key point: Cross-section from velocity)

3. How is the forebay water depth fixed?
   A. H = S + D + bottom clearance, where S = C V_p sqrt(D) is the submergence of the penstock intake
   B. H = Q/(vB)
   C. H = S - D
   D. H = 3 D regardless
   Answer: A. Submergence S from Gordon's formula prevents vortex and air entry; adding the penstock diameter and 0.3-0.5 m clearance gives the depth. (Key point: Depth from Gordon's formula)

4. What is the forebay spillway designed to pass?
   A. 10% of the turbine discharge
   B. The full design discharge when the turbines trip, using Q = C L h^(3/2)
   C. Only the flood flow of the river
   D. Flushing discharge only
   Answer: B. If turbines trip, all incoming flow must be spilled safely at a small head h of 0.3-0.5 m. (Key point: Spillway sizing)

## Related in Hydropower Engineering

- [Forebay design considerations; design for 12 m³/s](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-design-considerations-12cumec) — Hydropower Engineering, chapter 6
- [Forebay design with spillway length (14 m³/s)](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-design-14cumec-spillway-length) — Hydropower Engineering, chapter 6
- [Forebay design (14.5 m³/s, two penstocks)](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-design-14-5cumec) — Hydropower Engineering, chapter 6
- [Forebay design (20 m³/s, 300 m penstock)](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-design-20cumec-300m) — Hydropower Engineering, chapter 6
- [Forebay design (15 m³/s, 4 minutes)](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-design-15cumec-4min) — Hydropower Engineering, chapter 6
- [Forebay dimension for 3 minutes storage](https://www.bctengineer.com/question.md?key=semester_7%2Fhydropower_engineering%3Aforebay-dimension-3min-storage-2-24m) — Hydropower Engineering, chapter 6

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