---
title: "Dynamic response of excitation system"
subject: "Power Plant Equipment"
chapter: 3
key: "semester_7/power_plant_equipment:excitation-dynamic-response"
source: https://www.bctengineer.com/q/semester_7/power_plant_equipment/excitation-dynamic-response
site: BCT Engineering
---

# Dynamic response of excitation system

Power Plant Equipment · Chapter 3: Var/Voltage Control in Hydrogenerating Systems

- Asked in: 2082 Baisakh, 6 marks; 2074 Chaitra, 8 marks; 2076 Chaitra, 8 marks (asked 3 times)
- Video: [11. Excitation System (7) Dynamic Performance Measures (1)](https://www.youtube.com/watch?v=0YBSbfxTMgs) — Saher Albatran
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/power_plant_equipment/excitation-dynamic-response
- Whole chapter: https://www.bctengineer.com/md/semester_7/power_plant_equipment/chapter-3

## Question

Explain the dynamic response of excitation system with suitable mathematical deduction.

## Short answer

Dynamic response is governed by loop gain and time constants. Closed loop is G/(1+G) with G=K/[(1+sTA)(1+sTE)(1+sTG)]. Steady-state error is 1/(1+K); high K improves accuracy but may cause instability, so stabilizing feedback adds damping.

## Answer

The **dynamic response of an excitation system** is how fast and how smoothly the generator terminal voltage follows a change in reference voltage (or recovers after a load change). It depends on the gains and time constants of the amplifier, exciter and generator field, and on stabilizing feedback.

#### Mathematical model
Basic AVR loop (sensor time constant neglected, unity feedback):

```text
 Vref +   Ve  +-------+   +-------+   +-------+
 --->(+)----->|  KA   |-->|  KE   |-->|  KG   |--+--> Vt
     ^ -      |1+sTA  |   |1+sTE  |   |1+sTG  |  |
     |        +-------+   +-------+   +-------+  |
     +-------------------------------------------+
```

Open-loop transfer function:
$$
G(s) = \frac{K}{(1 + sT_A)(1 + sT_E)(1 + sT_G)}, \qquad K = K_A K_E K_G
$$
Closed loop:
$$
\frac{\Delta V_t(s)}{\Delta V_{ref}(s)} = \frac{G(s)}{1 + G(s)}
$$

#### Steady-state response
For a step $\Delta V_{ref}$, using the final value theorem:
$$
\begin{aligned}
\Delta V_t(\infty) &= \frac{K}{1 + K}\,\Delta V_{ref} \\
e_{ss} &= \frac{1}{1 + K}\,\Delta V_{ref}
\end{aligned}
$$
To keep the voltage error small (e.g. below 1 %), $K$ must be large (about 100 or more).

#### Transient response and stability
Characteristic equation:
$$
(1 + sT_A)(1 + sT_E)(1 + sT_G) + K = 0
$$
$$
T_A T_E T_G\, s^3 + (T_A T_E + T_E T_G + T_A T_G)\, s^2 + (T_A + T_E + T_G)\, s + (1 + K) = 0
$$
By the Routh criterion, the system is stable only if
$$
(T_A T_E + T_E T_G + T_A T_G)(T_A + T_E + T_G) > T_A T_E T_G\,(1 + K)
$$
So a large $K$ (good accuracy) makes the response more oscillatory and can make it unstable. This is the basic conflict in AVR design.

```text
 Vt
      high K: fast but oscillatory
    |    .-.
    |   /   '-.__.-------------
    |  /    ___.-------------- low K
    | / _.-'   (slower, larger error)
    |/.'
    +---------------------------> t
```

#### Improving the dynamic response
- **Stabilizing (rate) feedback** from exciter output to amplifier input, $\dfrac{sK_F}{1 + sT_F}$: adds damping only during transients, leaving steady-state gain unchanged. Closed loop becomes
$$
\frac{\Delta V_t}{\Delta V_{ref}} = \frac{G_A G_E G_G}{1 + G_A G_E H_F + G_A G_E G_G}
$$
- **Fast exciters** (static thyristor or brushless) with small $T_E$, and high **ceiling voltage** and **response ratio**, so the field current can be forced quickly.
- Lead-lag compensation or a power system stabilizer (PSS) for damping rotor oscillations.

A good excitation system gives a fast rise, small overshoot, short settling time and a small steady-state voltage error.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. For the basic AVR loop with loop gain K, the steady-state error for a step in Vref is:
   A. K/(1+K)
   B. 1/(1+K)
   C. 1/K^2
   D. K
   Answer: B. Vt(inf) = K/(1+K) dVref, so the error is 1/(1+K) of dVref. (Key point: Steady-state error)

2. What happens when the loop gain K is increased?
   A. Error falls but response becomes more oscillatory and may become unstable
   B. Error rises and stability improves
   C. Both error and oscillation fall
   D. Nothing changes
   Answer: A. Routh stability requires the time-constant product to exceed T_A T_E T_G (1+K), so large K risks instability. (Key point: Gain vs stability)

3. The characteristic equation of the basic AVR loop is:
   A. (1+sTA)(1+sTE)(1+sTG) + K = 0
   B. (1+sTA)(1+sTE)(1+sTG) - K = 0
   C. s + K = 0
   D. (sTA)(sTE)(sTG) = K
   Answer: A. 1 + G(s) = 0 with G = K/[(1+sTA)(1+sTE)(1+sTG)]. (Key point: Characteristic equation)

4. Which measure adds damping only during transients without changing steady-state gain?
   A. Increasing K_A
   B. Rate feedback sK_F/(1+sT_F) from exciter output
   C. Raising the exciter time constant
   D. Removing the amplifier
   Answer: B. Rate feedback is zero at steady state, so it only affects transients. (Key point: Improving response)

## Related in Power Plant Equipment

- [Need for excitation and improving dynamic response](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Aexcitation-dynamic-improvement) — Power Plant Equipment, chapter 3
- [Excitation system with stabilizing transformer: transfer function](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Aexcitation-stabilizing-transformer-model) — Power Plant Equipment, chapter 3, asked 13×
- [Function of excitation system and its transfer function](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Aexcitation-function-tf) — Power Plant Equipment, chapter 3, asked 2×
- [Brush excitation system](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Abrush-excitation-system) — Power Plant Equipment, chapter 3
- [Static excitation system](https://www.bctengineer.com/question.md?key=semester_7%2Fpower_plant_equipment%3Astatic-excitation-system) — Power Plant Equipment, chapter 3

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