---
title: "S-matrix of an amplitude modulator"
subject: "RF and Microwave Engineering"
chapter: 3
key: "semester_7/rf_and_microwave_engineering:s-matrix-amplitude-modulator"
source: https://www.bctengineer.com/q/semester_7/rf_and_microwave_engineering/s-matrix-amplitude-modulator
site: BCT Engineering
---

# S-matrix of an amplitude modulator

RF and Microwave Engineering · Chapter 3: RF and Microwave Network Theory and Analysis

- Asked in: 2078 Chaitra, 3+7 marks
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/rf_and_microwave_engineering/s-matrix-amplitude-modulator
- Whole chapter: https://www.bctengineer.com/md/semester_7/rf_and_microwave_engineering/chapter-3

## Question

Elaborate the importance of S-parameters for microwave frequencies. Evaluate the S-matrix of an Amplitude Modulator.

## Short answer

S-parameters use matched terminations for stable microwave measurements and directly give reflection/gain. For an amplitude modulator using a shunt PIN diode with normalized admittance y=Z0/R, the S-matrix is [S]=1/(2+y) [[-y,2],[2,-y]]; S21 varies with bias, producing AM.

## Answer

#### Importance of S-parameters at microwave frequencies
- Voltage and current cannot be measured directly at microwave frequencies (and are not unique in waveguides); **incident and reflected power waves** can.
- Z, Y and h parameters need **open or short** terminations, which are hard to build at high frequency and may make active devices oscillate. S-parameters are measured with **matched loads**.
- S-parameters give reflection (S11, S22), gain/loss (S21) and isolation (S12) directly, and are measured with a vector network analyzer.
- Network properties are simple to test: reciprocal → [S] = [S]ᵀ, lossless → [S] unitary.

#### S-matrix of an amplitude modulator
A microwave amplitude modulator is a **two-port device whose transmission coefficient changes with a low-frequency modulating signal**. A common form is a **PIN diode** mounted in **shunt** across a matched line (or waveguide). The diode's RF resistance *R* is controlled by its bias current, so the bias carries the modulating signal.

```text
  a1 ->                       -> b2
  o-------------+-------------o
  port 1 (Z0)   |        port 2 (Z0)
               [R]  PIN diode, R(t)
                |   (bias = modulating signal)
  o-------------+-------------o
```

**Assumption:** the diode acts as a pure resistance with normalized shunt admittance y = Z0/R; ports are matched lines of Z0.

**Step 1 – S11.** With port 2 matched, port 1 sees Z0 in parallel with R, i.e. normalized admittance 1 + y:
```text
 S11 = (1 - (1 + y))/(1 + (1 + y)) = -y/(2 + y)
```
**Step 2 – S21.** For a shunt element, the voltage across both ports is the same, so V2 = V1 = V1+(1 + S11):
```text
 S21 = 1 + S11 = 2/(2 + y)
```
**Step 3 – symmetry.** The element is symmetric and reciprocal, so S22 = S11 and S12 = S21:
```text
          1     | -y   2 |
 [S] = ------- · |       |
        2 + y   |  2  -y |
```

**Step 4 – modulation.** If the bias makes y vary with the modulating signal, the output is
b2 = S21(t)·a1 = [2/(2 + y(t))]·a1. Choosing the bias so that |S21(t)| = k[1 + m·cos ωₘt] gives an AM wave:
```text
 a1 = A cos ωc t
 b2 = kA [1 + m cos ωm t] cos ωc t
```
with modulation index *m*.

**Limiting cases:**
- y → 0 (R very high, diode reverse biased): S11 = 0, S21 = 1, full transmission (carrier peak).
- y → ∞ (R very low, diode forward biased): S11 = −1, S21 = 0, full reflection (carrier off).

**Properties of the matrix:**
- Reciprocal: S12 = S21.
- Not lossless: |S11|² + |S21|² = (y² + 4)/(2 + y)² < 1 for 0 < y < ∞; the missing power is absorbed in the diode resistance.
- Not matched: S11 ≠ 0 except at y = 0, so an isolator is often placed before the modulator to protect the source from the reflected power.

An ideal (matched) modulator is therefore often modeled simply as [S] = [[0, S21(t)], [S21(t), 0]] with S21(t) = k[1 + m cos ωₘt]·e^(−jθ).

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. How does the PIN diode shunt modulator produce amplitude modulation?
   A. The bias signal varies the diode resistance, which varies the transmission coefficient S21
   B. The diode changes the carrier frequency
   C. The diode is turned fully off all the time
   D. The diode amplifies the carrier
   Answer: A. The modulating signal controls the bias, so R and y change, making S21(t) vary and the output b2 = S21(t) a1 amplitude modulated. (Key point: Modulator principle)

2. For a shunt element with normalized admittance y, the S-parameters are
   A. S11 = y/(2+y), S21 = 2/(2+y)
   B. S11 = -y/(2+y), S21 = 2/(2+y)
   C. S11 = -y/(2+y), S21 = y/(2+y)
   D. S11 = 2/(2+y), S21 = -y/(2+y)
   Answer: B. S11 = -y/(2+y) and, since both ports have the same voltage, S21 = 1 + S11 = 2/(2+y). (Key point: Shunt S11 and S21)

3. When the diode is forward biased (R very low, y tends to infinity), what happens?
   A. S11 = 0, S21 = 1, full transmission
   B. S11 = -1, S21 = 0, full reflection
   C. S11 = 1, S21 = 1
   D. S11 = 0, S21 = 0
   Answer: B. A low-resistance shunt shorts the line, reflecting everything with a sign change, so the carrier is off. (Key point: Limiting cases)

4. Why is the shunt-resistor modulator not lossless?
   A. Because S12 is not equal to S21
   B. Because |S11|^2 + |S21|^2 = (y^2+4)/(2+y)^2 < 1, the rest being absorbed in the diode resistance
   C. Because it is matched
   D. Because it has three ports
   Answer: B. The sum of squared magnitudes is below 1 for 0 < y < infinity, so power is dissipated in the diode. (Key point: Lossless check)

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