---
title: "Turbojet cycle, thrust and propulsive efficiency"
subject: "Turbo Machines"
chapter: 6
key: "semester_7/turbo_machines:turbojet-cycle-thrust-propulsive-efficiency"
source: https://www.bctengineer.com/q/semester_7/turbo_machines/turbojet-cycle-thrust-propulsive-efficiency
site: BCT Engineering
---

# Turbojet cycle, thrust and propulsive efficiency

Turbo Machines · Chapter 6: Gas Turbine Cycles of Aircraft Propulsion

- Asked in: year not given, 6 marks
- Video: [Turbojets: Thermodynamics for Mechanical Engineers](https://www.youtube.com/watch?v=Ir4zlj45vRY) — Mike Schertzer
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_7/turbo_machines/turbojet-cycle-thrust-propulsive-efficiency
- Whole chapter: https://www.bctengineer.com/md/semester_7/turbo_machines/chapter-6

## Question

Draw the schematic and T-s diagram of the ideal turbojet engine cycle. Derive the expressions for the thrust, the propulsive efficiency and the overall efficiency of a turbojet in terms of flight and jet velocities.

## Short answer

Thrust is F = mdot_a[(1 + f)C_j - V] plus the pressure term, approximately mdot_a(C_j - V). Propulsive efficiency is eta_p = 2V/(C_j + V) = 2/(1 + C_j/V). Overall efficiency is eta_o = eta_p eta_th = FV/(mdot_f LHV), with ideal thermal efficiency depending on overall pressure ratio.

## Answer

#### Cycle
Station numbers: 0 ambient, 1 inlet, 2 compressor inlet, 3 compressor exit, 4 turbine inlet, 5 turbine exit, 6 nozzle exit.

```text
 flight->  [diffuser][C][ Comb ][T][nozzle]--> jet
            0-2      2-3  3-4   4-5   5-6

 T-s: 0-2 ram rise (isentropic, up), 2-3 compression (up),
      3-4 heat addition (right and up along the p3 line),
      4-5 turbine expansion (down; drop = 2-3 rise),
      5-6 nozzle expansion (down to p0), 6-0 exhaust cooling.

 T
 |              4
 |             /|
 |            / |
 |           /  5
 |          3   |
 |          |   |
 |          |   6
 |          2  /
 |          | /
 |          0
 +-------------------- s
```

#### Thrust
From the momentum equation on the engine, with fuel-air ratio $f$ and air mass flow $\dot m_a$:

$$
F = \dot m_a\left[(1 + f)C_j - V\right] + (p_j - p_0)A_j
$$

For a fully expanded nozzle ($p_j = p_0$) and small $f$, $F \approx \dot m_a (C_j - V)$. The specific thrust is $F/\dot m_a = C_j - V$.

#### Propulsive efficiency
Useful thrust power $= FV = \dot m_a V (C_j - V)$. Rate of increase of kinetic energy of the stream $= \tfrac12\dot m_a (C_j^2 - V^2)$.

$$
\eta_p = \frac{\dot m_a V(C_j - V)}{\tfrac12\dot m_a (C_j^2 - V^2)} = \frac{2V}{C_j + V} = \frac{2}{1 + C_j/V}
$$

It approaches 1 as $C_j \to V$, but then the thrust goes to zero. This is why the turbofan uses a large mass flow at a lower jet velocity.

#### Thermal and overall efficiency
$$
\eta_{th} = \frac{\tfrac12\dot m_a (C_j^2 - V^2)}{\dot m_f \, LHV}, \qquad
\eta_o = \eta_p \eta_{th} = \frac{F V}{\dot m_f \, LHV}
$$

For the ideal Brayton-type engine, $\eta_{th} = 1 - T_0/T_{03}$, i.e. it depends on the overall pressure ratio (ram plus compressor). The **thrust specific fuel consumption** is $TSFC = \dot m_f/F = f/(C_j - V)$.

A higher turbine inlet temperature increases the specific thrust (higher $C_j$); a higher pressure ratio improves $\eta_{th}$ and so lowers the TSFC.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. For a fully expanded nozzle and small f, specific thrust is approximately
   A. C_j + V
   B. C_j V
   C. C_j - V
   D. C_j / V
   Answer: C. F = m_a[(1+f)C_j - V] reduces to m_a(C_j - V), so F/m_a = C_j - V. (Key point: Thrust for fully expanded nozzle)

2. Propulsive efficiency of the turbojet in terms of velocities is
   A. 2V/(C_j + V)
   B. (C_j - V)/V
   C. V/C_j
   D. (C_j + V)/2V
   Answer: A. Thrust power m_a V (C_j - V) divided by KE rate 1/2 m_a (C_j^2 - V^2) gives 2V/(C_j + V). (Key point: Propulsive efficiency)

3. Why not make C_j equal to V to get eta_p = 1?
   A. Thermal efficiency becomes infinite
   B. The nozzle would choke
   C. Fuel flow becomes zero
   D. Thrust becomes zero
   Answer: D. F = m_a(C_j - V) goes to zero, hence turbofans use large mass flow with lower jet velocity. (Key point: Trade-off)

4. Overall efficiency of a turbojet is
   A. eta_p / eta_th
   B. eta_p x eta_th = F V/(m_f LHV)
   C. eta_p + eta_th
   D. F/(m_f LHV)
   Answer: B. Overall efficiency is thrust power over fuel energy rate, which is the product of propulsive and thermal efficiencies. (Key point: Overall efficiency)

5. Higher pressure ratio and higher turbine inlet temperature respectively
   A. lower eta_th; lower specific thrust
   B. raise eta_th (lower TSFC); raise specific thrust through higher C_j
   C. raise specific thrust; lower eta_th
   D. have no effect on either
   Answer: B. Ideal eta_th = 1 - T0/T03 grows with pressure ratio, while higher T04 gives more expansion energy and jet velocity. (Key point: Effect of pressure ratio and TIT)

## Related in Turbo Machines

- [Ideal turbojet at altitude: thrust and TSFC](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Aideal-turbojet-flight-numerical) — Turbo Machines, chapter 6
- [Turbojet thrust, efficiencies and fuel consumption](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Aturbojet-thrust-efficiencies-numerical) — Turbo Machines, chapter 5
- [Ideal Brayton cycle work and efficiency](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Aideal-brayton-numerical) — Turbo Machines, chapter 3
- [Rocket engine thrust and specific impulse calculation](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Arocket-thrust-specific-impulse-numerical) — Turbo Machines, chapter 5
- [Turbojet, turbofan and turboprop comparison](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Aturbojet-turbofan-turboprop-comparison) — Turbo Machines, chapter 6
- [Brayton cycle efficiency and optimum pressure ratio](https://www.bctengineer.com/question.md?key=semester_7%2Fturbo_machines%3Abrayton-cycle-efficiency-optimum-pressure-ratio) — Turbo Machines, chapter 3

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- [Ideal diesel engine CR 20: efficiency and MEP](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Adiesel-cr20-max-2200k) — Fundamental of Thermodynamics & Heat Transfer, chapter 6
- [Ideal Brayton cycle: diagrams and efficiency](https://www.bctengineer.com/question.md?key=semester_2%2Ffundamental_of_thermodynamics_and_heat_transfer%3Abrayton-cycle-efficiency-derivation) — Fundamental of Thermodynamics & Heat Transfer, chapter 6, asked 2×
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