--- title: "BoQ for IOE ICT building six labs" subject: "Internet and Intranet" chapter: 5 key: "semester_8/internet_and_intranet:boq-ioe-ict-six-labs" source: https://www.bctengineer.com/q/semester_8/internet_and_intranet/boq-ioe-ict-six-labs site: BCT Engineering --- # BoQ for IOE ICT building six labs Internet and Intranet · Chapter 5: Designing Internet Systems and Servers - Asked in: 2071 Bhadra, 12 marks - Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14 - Page: https://www.bctengineer.com/q/semester_8/internet_and_intranet/boq-ioe-ict-six-labs - Whole chapter: https://www.bctengineer.com/md/semester_8/internet_and_intranet/chapter-5 ## Question IOE ICT building has six computer labs each having 30 computers. Two labs are located at 2nd floor and four labs are located at 3rd floor. Each computer has redundant network connection via dual ports CAT6 information outlet connected directly from Network Control Room (NCR) located at ground floor. Prepare the Bill of Quantity (BoQ) with necessary network resources required in quantity for the complete networking. Your BoQ should include estimation of information outlet (faceplate), wireless AP, CAT6 cables, Patch Cords, 24 ports Patch Panels and 48-ports Switches. ## Short answer Assume 360 cable runs (180 dual-port PCs) plus 6 APs, with average lengths of 45 m (2nd floor) and 55 m (3rd floor) and 10% wastage. Key quantities: 69 boxes of CAT6 cable, 180 dual-port faceplates plus 6 single-port, 366 RJ45 jacks, 16 patch panels, 8 48-port access switches plus 1 PoE switch, 2 core L3 switches, and 732 patch cords. ## Answer #### Assumptions - 6 labs x 30 computers = 180 computers. Dual-port outlets, so 2 cables per computer = 360 cables. - Labs 1-2 on the 2nd floor, labs 3-6 on the 3rd floor. NCR on the ground floor. - One wireless AP per lab = 6 APs, single CAT6 drop each (PoE). - Average run (horizontal plus vertical riser and slack): 2nd-floor labs 45 m, 3rd-floor labs 55 m. All are under 90 m. - Wastage and slack 10%. Cable box 305 m. A computer's two ports go to two different switches (dual-homing). #### Layout ```text 3rd floor: Lab3 Lab4 Lab5 Lab6 (30 PC each, dual outlet) 2nd floor: Lab1 Lab2 (30 PC each, dual outlet) | CAT6 riser (55 m / 45 m) Ground : [Patch panels x16] [Switch x8 (48p) + 1 PoE] | [Core L3 x2] -- Router/FW -- Internet ``` #### Quantity estimation 1. Dual-port faceplates: 180. Single-port faceplates for APs: 6. Total faceplates = **186**. RJ45 jacks = 360 + 6 = **366**. 2. Cable length: - Labs 1-2: 2 labs x 61 runs (60 + 1 AP) x 45 m = 5,490 m. - Labs 3-6: 4 labs x 61 runs x 55 m = 13,420 m. - Total = 18,910 m. With 10%: 20,801 m. Boxes = 20,801 / 305 = 68.2, so **69 boxes**. 3. Patch panels: 366 / 24 = 15.25, so **16 panels**. 4. Switches (48-port): PC ports 360 / 48 = 7.5, so 8 switches for PCs; plus 1 PoE 48-port switch for 6 APs = **9 switches**. Two core L3 switches (24-port, SFP+) are added for redundant uplinks, routing and server links = **2**. 5. Patch cords: user side 2 m = 360 + 6 = 366; panel to switch 1 m = 366; access to core uplinks (fibre or CAT6) = 18. Total CAT6 cords = **732** plus **18** uplink cords. 6. Rack space: 16 panels (16U) + 11 switches (11U) + managers (8U) + router/FW (2U) + UPS (4U) = 41U. Use **2 racks** of 42U. #### Bill of Quantity | S.N. | Item | Specification | Qty | |---|---|---|---| | 1 | CAT6 UTP cable | 305 m box | 69 boxes | | 2 | Dual-port faceplate | With back box | 180 | | 3 | Single-port faceplate | For APs | 6 | | 4 | RJ45 CAT6 jack | Keystone | 366 | | 5 | Patch panel | 24-port CAT6 | 16 | | 6 | Patch cord 2 m | CAT6 | 366 | | 7 | Patch cord 1 m | CAT6 | 366 | | 8 | Access switch | 48-port GE, 4 SFP+ | 8 | | 9 | PoE switch | 48-port PoE+ | 1 | | 10 | Core L3 switch | 24-port, 4 SFP+ | 2 | | 11 | Wireless AP | Dual-band, PoE | 6 | | 12 | Router / firewall | | 1 | | 13 | Rack | 42U | 2 | | 14 | UPS | 5 kVA online | 1 | | 15 | Conduit, trunking, cable trays | | lot | | 16 | Labels, ties, tester | | lot | #### IP plan (10.20.0.0/16) A lab has 30 PCs plus a gateway, so a /27 (30 hosts) is too small. A /26 (62 hosts) is used. | Network | Subnet | Usable | Gateway | |---|---|---|---| | Lab 1 | 10.20.1.0/26 | 62 | .1 | | Lab 2 | 10.20.1.64/26 | 62 | .65 | | Lab 3 | 10.20.1.128/26 | 62 | .129 | | Lab 4 | 10.20.1.192/26 | 62 | .193 | | Lab 5 | 10.20.2.0/26 | 62 | .1 | | Lab 6 | 10.20.2.64/26 | 62 | .65 | | Wi-Fi (6 APs) | 10.20.3.0/27 | 30 | .1 | | Management | 10.20.4.0/27 | 30 | .1 | | Servers | 10.20.5.0/27 | 30 | .1 | The two NICs of a PC are teamed (active-backup) so the PC keeps one address. DHCP is served by the core switch or a server using relay. ## Check yourself The answer's key points as multiple-choice questions, with the correct option and why. 1. How many CAT6 cables serve the 180 computers' dual-port outlets? A. 180 B. 360 C. 186 D. 540 Answer: B. Each computer has two ports, so 2 x 180 = 360 cables, plus 6 single drops for APs. (Key point: Cable count with dual ports) 2. How is the total cable length of about 18,910 m found? A. All 6 labs x 61 runs x 50 m B. Labs 1-2 at 45 m and labs 3-6 at 55 m, each with 61 runs (60 + 1 AP) C. 360 runs x 90 m D. 180 x 55 m only Answer: B. 2 x 61 x 45 = 5,490 m and 4 x 61 x 55 = 13,420 m, a total of 18,910 m before 10% wastage. (Key point: Cable length estimate) 3. After adding 10% wastage (20,801 m), how many 305 m boxes are ordered? A. 68 B. 69 C. 62 D. 75 Answer: B. 20,801 / 305 = 68.2, which is rounded up to 69 boxes. (Key point: Box rounding) 4. Which pair of quantities is correct for patch panels and 48-port switches? A. 16 patch panels; 8 PC switches plus 1 PoE switch B. 8 patch panels; 4 switches C. 15 patch panels; 7 switches D. 24 patch panels; 12 switches Answer: A. 366 jacks / 24 = 15.25, so 16 panels. 360 PC ports / 48 = 7.5, so 8 switches, plus 1 PoE switch for the 6 APs. (Key point: Patch panels and switches) 5. What does dual-homing of a PC mean here? A. Both ports go to the same switch B. The two ports go to two different switches for redundancy C. Two PCs share one port D. The PC uses Wi-Fi as its second link Answer: B. Connecting a computer's two ports to different switches keeps it online if one switch fails. (Key point: Dual-homing) ## Related in Internet and Intranet - [BOQ for DOECE four computer labs](https://www.bctengineer.com/question.md?key=semester_8%2Finternet_and_intranet%3Aboq-doece-four-labs) — Internet and Intranet, chapter 5 - [BoQ for NITC four research labs](https://www.bctengineer.com/question.md?key=semester_8%2Finternet_and_intranet%3Aboq-nitc-research-labs) — Internet and Intranet, chapter 5 - [Redundant network for IOE Pulchowk campus](https://www.bctengineer.com/question.md?key=semester_8%2Finternet_and_intranet%3Aredundant-network-ioe-pulchowk) — Internet and Intranet, chapter 5 - [Design network for two buildings with fiber](https://www.bctengineer.com/question.md?key=semester_8%2Finternet_and_intranet%3Anetwork-design-guidelines-two-buildings) — Internet and Intranet, chapter 5