---
title: "Multistage advantage and TST switching"
subject: "Telecommunications"
chapter: 4
key: "semester_8/telecommunications:multistage-advantage-tst"
source: https://www.bctengineer.com/q/semester_8/telecommunications/multistage-advantage-tst
site: BCT Engineering
---

# Multistage advantage and TST switching

Telecommunications · Chapter 4: Digital Switching

- Asked in: 2079 Bhadra, 3+4 marks; 2073 Shrawan, 2+6 marks (asked 2 times)
- Video: [T 4.5  TDM Switching & Space -Time switching](https://www.youtube.com/watch?v=PEzhUtAsX0g) — Ramanikumar animations -Telecom and Wireless
- Answer checked by Claude Opus 5.5 (high effort) on 2026-10-14
- Page: https://www.bctengineer.com/q/semester_8/telecommunications/multistage-advantage-tst
- Whole chapter: https://www.bctengineer.com/md/semester_8/telecommunications/chapter-4

## Question

What is the advantage of multi-stage switching system over single stage switching system? Explain TST Switching with neat diagram and its blocking probability.

## Short answer

Multi-stage switches use far fewer crosspoints, better utilization, alternative paths, modular growth, and built-in concentration/expansion. In TST, incoming slot i is moved by first TSI to free internal slot j, switched by space matrix in slot j, then moved by second TSI to outgoing slot m. Blocking probability: P_B = [1 - (1 - p/alpha)^2]^l with alpha = l/c, extremely low.

## Answer

#### Advantages of multi-stage over single-stage switching
- **Far fewer crosspoints:** a single-stage $N \times N$ switch needs $N^2$ crosspoints (e.g. $10^6$ for 1000 lines); a three-stage switch needs only a small fraction, so cost and size fall.
- **Better crosspoint utilisation:** in a single stage at most $N$ of the $N^2$ crosspoints can be in use at once (each input and output takes part in only one connection), so utilisation is at most $1/N$; in multi-stage each crosspoint is shared by many possible connections.
- **Alternative paths:** a call can go through any of several middle-stage arrays, so failure of one crosspoint does not isolate a subscriber (better reliability).
- **Modular growth:** capacity can be expanded by adding arrays.
- **Concentration and expansion** can be built into the stages to suit traffic.
- Drawbacks: some blocking may occur, and path search (control) is more complex.

#### TST switching
A **Time–Space–Time (TST)** switch is a three-stage digital switching network: an incoming **time stage**, a **space stage** in the middle, and an outgoing **time stage**. It is the most common structure in large digital exchanges.
```text
 incoming     T stage      S stage       T stage   outgoing
 highways   (time slot   (crosspoint   (time slot  highways
            interchange)   matrix)    interchange)
 PCM 1 --->[ TSI ]--->+-------------+--->[ TSI ]---> PCM 1
 PCM 2 --->[ TSI ]--->|  N x N      |--->[ TSI ]---> PCM 2
  ...                 |  space sw.  |
 PCM N --->[ TSI ]--->+-------------+--->[ TSI ]---> PCM N
 slot i  -> slot j (internal) -> slot j -> slot m
```
**Operation (connect slot $i$ of PCM 1 to slot $m$ of PCM N):**
1. **First time stage:** the time slot interchanger (TSI) on PCM 1 writes incoming samples into its speech memory in order and reads the sample of slot $i$ out in a free **internal slot $j$** (chosen by the control).
2. **Space stage:** in internal slot $j$ the crosspoint connecting row 1 to column N is closed (set by the space-switch control memory), passing the sample to the outgoing side. The same crosspoint is reused by other connections in other slots.
3. **Second time stage:** the TSI on output highway N stores the sample and reads it out in the required outgoing slot $m$.
4. The reverse direction uses a related internal slot (often half a frame away, $j + l/2$, where $l$ is the number of internal slots) so both directions are set up together.

Because the space stage only needs to find **one free internal slot common to both links**, the many internal time slots act like many middle-stage arrays, giving very low blocking at low cost. The time stages can also expand ($l > c$ internal slots) to reduce blocking further.

#### Blocking probability of TST (Lee graph)
```text
           slot 1
       +--- ... ---+
  A ---+--- slot j-+--- B     l parallel paths
       +--- ... ---+          (internal slots)
           slot l
```
Let $p$ = occupancy of an incoming channel, $c$ = channels per highway, $l$ = internal slots, time expansion $\alpha = l/c$. Each internal link is busy with probability $p' = p/\alpha$. A path is blocked if either of its two links is busy: $1-(1-p')^2$. The call is blocked only if all $l$ paths are blocked:
$$
\begin{aligned}
p' &= \frac{p}{\alpha},\quad \alpha = \frac{l}{c} \\
P_B(\text{TST}) &= \left[1 - (1-p')^2\right]^{l}
\end{aligned}
$$

Example: $p = 0.2$, $l = c = 32$: $P_B = (1 - 0.8^2)^{32} = 0.36^{32} \approx 6.3 \times 10^{-15}$, practically non-blocking.

## Check yourself

The answer's key points as multiple-choice questions, with the correct option and why.

1. What is the main advantage of multi-stage over single-stage switching?
   A. No blocking at all
   B. Simpler path search
   C. Far fewer crosspoints than N^2
   D. Fewer alternative paths
   Answer: C. A single stage needs N^2 crosspoints; three stages need only a fraction, cutting cost and size. (Key point: Crosspoint saving)

2. Why does multi-stage switching improve reliability?
   A. A call can use any of several middle-stage arrays
   B. It uses fewer subscribers
   C. It has only one path
   D. It removes the control unit
   Answer: A. Multiple middle arrays give alternative paths, so one failed crosspoint does not isolate a subscriber. (Key point: Reliability from alternative paths)

3. In a TST switch, what does the space stage do?
   A. Changes the slot from i to m
   B. Connects the sample on the incoming highway to the outgoing highway in the internal slot j
   C. Writes samples into the speech memory
   D. Generates the tones
   Answer: B. The first TSI moves slot i to internal slot j, the space stage crosses highways in slot j, the last TSI moves it to slot m. (Key point: TST operation)

4. What is the TST blocking probability, with p' = p/alpha and l internal slots?
   A. p'^l
   B. 1 - (1-p')^l
   C. [1 - (1-p')^2]^l
   D. (1-p')^2
   Answer: C. A path is free only if both links are free; blocked = 1-(1-p')^2, and the call blocks only if all l paths are blocked. (Key point: TST blocking formula)

## Related in Telecommunications

- [Multistage switching and TST blocking](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Amultistage-tst-blocking) — Telecommunications, chapter 4
- [Multistage switching; TST vs STS](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Amultistage-tst-sts-compare) — Telecommunications, chapter 4
- [Multistage switching and STS blocking](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Amultistage-sts-blocking) — Telecommunications, chapter 4
- [TST time slots for non-blocking operation](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Atst-time-slots-numerical) — Telecommunications, chapter 4
- [GOS and blocking probability in a loss system](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Agos-blocking-loss-system) — Telecommunications, chapter 6
- [Clos network and STS/TST blocking](https://www.bctengineer.com/question.md?key=semester_8%2Ftelecommunications%3Aclos-network-sts-tst-blocking) — Telecommunications, chapter 4

## Related in other subjects

- [Pipelining and multi-stage pipeline](https://www.bctengineer.com/question.md?key=semester_6%2Fembedded_system%3Apipelining-stages) — Embedded System, chapter 2, asked 3×
