- 2068 Shrawan
Motion when acceleration is function of time
Short answer
Integrate acceleration with respect to time to get velocity: v = v₀ + ∫ a dt. Then integrate velocity to get position: x = x₀ + ∫ v dt. Use initial conditions v₀, x₀.
How is the motion of a particle found when the acceleration is a given function of time?
Motion when a is a given function of time
If a = f(t), velocity and position are found by successive integration, using the initial conditions.
- Velocity: a = dv/dt, so dv = f(t) dt, and v = v₀ + ∫₀ᵗ f(t) dt
- Position: v = dx/dt, so x = x₀ + ∫₀ᵗ v dt
- The constants v₀ and x₀ are the velocity and position at t = 0 (or any known instant).
Example: a = 6t m/s² with v₀ = 2 m/s and x₀ = 0:
- v = 2 + ∫6t dt = 2 + 3t²
- x = ∫(2 + 3t²) dt = 2t + t³
At t = 2 s: v = 14 m/s and x = 12 m.
If the particle changes direction (v passes through zero), the total distance travelled is found by adding the distances in each interval separately.
✓ Answer checked by Claude Opus 5.5 (high effort)
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