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Motion when acceleration is function of time

Short answer

Integrate acceleration with respect to time to get velocity: v = v₀ + ∫ a dt. Then integrate velocity to get position: x = x₀ + ∫ v dt. Use initial conditions v₀, x₀.

How is the motion of a particle found when the acceleration is a given function of time?

Motion when a is a given function of time

If a = f(t), velocity and position are found by successive integration, using the initial conditions.

  1. Velocity: a = dv/dt, so dv = f(t) dt, and v = v₀ + ∫₀ᵗ f(t) dt
  2. Position: v = dx/dt, so x = x₀ + ∫₀ᵗ v dt
  3. The constants v₀ and x₀ are the velocity and position at t = 0 (or any known instant).

Example: a = 6t m/s² with v₀ = 2 m/s and x₀ = 0:

  • v = 2 + ∫6t dt = 2 + 3t²
  • x = ∫(2 + 3t²) dt = 2t + t³

At t = 2 s: v = 14 m/s and x = 12 m.

If the particle changes direction (v passes through zero), the total distance travelled is found by adding the distances in each interval separately.

✓ Answer checked by Claude Opus 5.5 (high effort)

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