- 2069 Chaitra · 6 marks
Generation of sinusoidal emf
Short answer
When a coil rotates at constant angular velocity ω in a uniform magnetic field, the induced emf is e = Em sin ωt, with Em = NBAω. Angular velocity is the rate of angular displacement: ω = 2πf rad/s.
Explain generation of sinusoidal emf with diagram and define angular velocity.
Principle: When a coil rotates in a uniform magnetic field, its conductors cut the flux and an emf is induced (Faraday's law). The emf varies sinusoidally with the angle turned.
Generation
Take a rectangular coil of N turns, area A, rotating at constant angular velocity ω in a uniform field B between N and S poles.
N S
┌───────────────────────┐
│ ┌───────────┐ │
│ │ coil │ ──►ω │
│ └───────────┘ │
└───────────────────────┘
Slip rings + brushes → load
At t = 0 the coil plane is perpendicular to the field (flux maximum, emf zero). After time t the coil has turned through θ = ωt.
- Flux linked: φ = B A cos ωt
- Induced emf: e = −N dφ/dt = N B A ω sin ωt
So e = Em sin ωt, with Em = N B A ω.
- At θ = 0° and 180°: coil sides move parallel to the field, e = 0.
- At 90° (emf +max) and 270° (−max): sides cut the field at right angles.
Plotting e against ωt gives a sine wave. One revolution of a two-pole machine gives one cycle. Slip rings carry the emf to the external circuit.
Angular velocity
Angular velocity is the rate of change of angular displacement of the rotating coil:
ω = θ/t = 2π f rad/s
where f is the frequency in Hz. For f = 50 Hz, ω = 314 rad/s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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