- 2073 Chaitra · 4 marks
Thevenin theorem with example
Short answer
Thevenin's theorem states any linear two-terminal network can be replaced by a voltage source V_th in series with a resistance R_th, where V_th is open-circuit voltage and R_th is equivalent resistance with sources zeroed. It simplifies analysis when load varies, e.g., a network of 24V, 6Ω, 3Ω yields V_th=8V, R_th=2Ω, and load current is V_th/(R_th+RL).
State and explain thevenin's theorem with suitable example.
Statement
Thevenin's theorem: any linear two-terminal network containing sources and resistors can be replaced, as seen from its two terminals, by a single voltage source V_th in series with a resistance R_th.
- V_th = open-circuit voltage between the terminals (load removed).
- R_th = resistance between the terminals with all independent sources set to zero (voltage sources shorted, current sources opened).
Linear network Thevenin equivalent
o-------+------o a o--[R_th]--+------o a
| (V_th) | load
(sources| |
and R) | |
o-------+------o b o----------+------o b
Steps
- Remove the load resistor and mark the two terminals.
- Find V_th (open-circuit voltage) by any method.
- Set all independent sources to zero and find R_th.
- Connect the load to the equivalent: I_L = V_th/(R_th + R_L).
Example
A 24 V source feeds R₁ = 6 Ω in series, with R₂ = 3 Ω across the output terminals, and a load R_L = 4 Ω.
- V_th = 24 × 3/(6 + 3) = 8 V
- R_th = 6 ∥ 3 = 2 Ω
- I_L = 8/(2 + 4) = 1.333 A, V_L = 5.33 V
Check on the original circuit: R_total = 6 + (3 ∥ 4) = 7.714 Ω, I = 3.111 A, and the load receives 3.111 × 3/7 = 1.333 A. The results are the same.
It is useful when one branch (the load) changes while the rest of the network stays the same.
✓ Answer checked by Claude Opus 5.5 (high effort)
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