Sort employee structures by salary

Method. A structure employee with name, age and salary is declared and an array of 10 such structures is read in main(). The array is passed to sortBySalary(), which sorts it in ascending order of salary using bubble sort; whole structures are swapped with a temporary structure variable. The sorted data is displayed from main().

(For the variant with only name and salary, remove age; the same function works unchanged.)

#include <stdio.h>
#define N 10

struct employee {
    char name[30];
    int age;
    float salary;
};

void sortBySalary(struct employee e[], int n)
{
    struct employee t;
    for (int i = 0; i < n - 1; i++)
        for (int j = 0; j < n - 1 - i; j++)
            if (e[j].salary > e[j + 1].salary) {
                t = e[j];
                e[j] = e[j + 1];
                e[j + 1] = t;
            }
}

int main(void)
{
    struct employee e[N];
    for (int i = 0; i < N; i++) {
        printf("Employee %d (name age salary): ", i + 1);
        scanf("%29s %d %f", e[i].name, &e[i].age, &e[i].salary);
    }
    sortBySalary(e, N);
    printf("\n%-12s %-5s %s\n", "Name", "Age", "Salary");
    for (int i = 0; i < N; i++)
        printf("%-12s %-5d %.2f\n", e[i].name, e[i].age, e[i].salary);
    return 0;
}

Sample run

Input (entered one after another): Ram 30 45000 Sita 25 52000 Hari 41 38000 Gita 29 61000 Bibek 35 47500 Maya 33 39500 Kiran 27 43000 Anita 38 70000 Suman 45 55000 Rita 31 41000

Name         Age   Salary
Hari         41    38000.00
Maya         33    39500.00
Rita         31    41000.00
Kiran        27    43000.00
Ram          30    45000.00
Bibek        35    47500.00
Sita         25    52000.00
Suman        45    55000.00
Gita         29    61000.00
Anita        38    70000.00