- 2074 Chaitra · 6 marks
Student records with two functions
Short answer
Use struct student with name, roll, marks. readInfo() reads data with scanf, displayInfo() prints a formatted table. In main, declare struct student s[10], pass to both functions.
Create a structure named student that has name, roll and marks as members. Assume appropriate types and size of members. Use this structure to read and display records of 10 students. Create two functions: One is to read information of students and other to display the information.
Design. The structure student has name (char array of 30), roll (int) and marks (float). An array of 10 students is created in main() and passed to two functions: readInfo() reads the details and displayInfo() prints them in a table. As arrays are passed by address, readInfo() fills the original array.
#include <stdio.h>
#define N 10
struct student {
char name[30];
int roll;
float marks;
};
void readInfo(struct student s[], int n)
{
for (int i = 0; i < n; i++) {
printf("Student %d (name roll marks): ", i + 1);
scanf("%29s %d %f", s[i].name, &s[i].roll, &s[i].marks);
}
}
void displayInfo(struct student s[], int n)
{
printf("\n%-12s %-6s %s\n", "Name", "Roll", "Marks");
for (int i = 0; i < n; i++)
printf("%-12s %-6d %.1f\n", s[i].name, s[i].roll, s[i].marks);
}
int main(void)
{
struct student s[N];
readInfo(s, N);
displayInfo(s, N);
return 0;
}
Sample run
Input (entered one after another): Ram 1 78 Sita 2 85.5 Hari 3 62 Gita 4 91 Bibek 5 55.5 Maya 6 70 Kiran 7 66 Anita 8 88 Suman 9 49 Rita 10 73
Name Roll Marks
Ram 1 78.0
Sita 2 85.5
Hari 3 62.0
Gita 4 91.0
Bibek 5 55.5
Maya 6 70.0
Kiran 7 66.0
Anita 8 88.0
Suman 9 49.0
Rita 10 73.0
✓ Answer checked by Claude Opus 5.5 (high effort)
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