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Damped LCR oscillation, damped frequency

Short answer

Electromagnetic oscillation is energy exchange between L and C. Damped LCR circuit: L d²q/dt² + R dq/dt + q/C = 0 gives d²q/dt² + 2γ dq/dt + ω0² q = 0 with γ = R/(2L). For weak damping, q = q0 e^(−γ t) cos(ω′t), where damped frequency ω′ = √(1/LC − R²/(4L²)) is lower than ω0 due to energy dissipation in R.

What is electromagnetic oscillation? Derive the differential equation of damped LCR oscillation, solve it to find the damped frequency of the oscillation and explain its significance.

Electromagnetic oscillation is the periodic exchange of energy between the electric field of a capacitor and the magnetic field of an inductor, with charge and current varying sinusoidally in time.

Differential equation

A charged capacitor C is discharged through L and R in series.

  +q |----|-q
     C    L ~~~ R
     |_________|

Kirchhoff's voltage law: L di/dt + Ri + q/C = 0 with i = dq/dt:

L d²q/dt² + R dq/dt + q/C = 0
d²q/dt² + 2γ dq/dt + ω0² q = 0 ,   γ = R/2L ,  ω0² = 1/LC

Solution

  1. Try q = q0 e^(αt). Auxiliary equation: α² + 2γα + ω0² = 0, α = −γ ± √(γ² − ω0²).
  2. For weak damping (γ < ω0, i.e. R² < 4L/C), write √(γ² − ω0²) = ± iω′ with
ω′ = √(ω0² − γ²) = √(1/LC − R²/4L²)
  1. Solution: q = q0 e^(−Rt/2L) cos(ω′t + φ).

Frequency and significance

f′ = ω′/2π = (1/2π) √(1/LC − R²/4L²)
  • The charge oscillates with the lower frequency ω′ < ω0 and with exponentially decaying amplitude q0 e^(−Rt/2L).
  • Energy is dissipated as heat in R, so oscillations die out; time constant for amplitude = 2L/R.
  • If R² = 4L/C (critical damping), ω′ = 0: no oscillation, charge decays fastest without overshoot.
  • If R² > 4L/C (overdamped), no oscillation and slow decay.
  • ω′ tells how a real LC circuit (e.g. a tuned circuit) differs from the ideal one; for small R, ω′ ≈ ω0.

✓ Answer checked by Claude Opus 5.5 (high effort)

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