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Energy stored in an inductor

Short answer

Energy stored in an inductor: U = ½ L I². Magnetic energy density u_B = B²/(2μ₀), proportional to B², analogous to electric energy density u_E = ½ ε₀ E².

Determine the energy stored in an inductor (derive the expression). Hence show that the magnetic energy density is directly proportional to the square of the magnetic field (flux density), and compare it with the electric energy density.

Energy stored in an inductor

When current i flows in an inductor of inductance L, the induced emf opposes the rise: ε = −L di/dt. The source must do work against it.

  1. Power supplied against the back emf: P = ε_back · i = L i (di/dt)
  2. Work in time dt: dW = L i di
  3. Total work to raise current from 0 to I:

U = ∫₀ᴵ L i di = ½ L I²

U = ½ L I², stored in the magnetic field.

Magnetic energy density

Take a long solenoid of length l, area A, n turns per unit length. B = μ0 n I and L = μ0 n² A l.

  1. U = ½ (μ0 n² A l) I² = (1/2μ0)(μ0 n I)² A l = B²/(2μ0) · (A l)
  2. Volume = A l, so energy per unit volume:

u_B = B²/(2μ0)

Thus u_B ∝ B², the square of the flux density. This holds for any magnetic field in vacuum.

Comparison with electric energy density

PropertyMagneticElectric
Energy densityu_B = B²/(2μ0)u_E = ½ ε0 E²
Depends onsquare of Bsquare of E
Stored in deviceinductor, U = ½LI²capacitor, U = ½CV²
Constantμ0 (in denominator)ε0 (in numerator)

Both are proportional to the square of the field and exist throughout space where the field is present.

✓ Answer checked by Claude Opus 5.5 (high effort)

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