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Production of plane, circular, elliptical light
Short answer
Polarization restricts vibrations to a fixed pattern. Double refraction splits light into mutually perpendicular plane-polarized ordinary and extraordinary rays. With phase difference δ = (2π/λ)(μ_o−μ_e)t, δ=0,π gives linear; δ=π/2 and a≠b gives elliptical; δ=π/2 and a=b gives circular.
What is the principle of double refraction? Establish the relations for the production of linearly, elliptically and circularly polarized light (what is polarization?).
Polarization is the property of transverse waves by which the vibrations are restricted to a particular direction or pattern. In plane (linear) polarized light the electric vector vibrates in one plane; in circular and elliptical light its tip traces a circle or ellipse.
Principle of double refraction
When unpolarized light enters a doubly refracting (anisotropic) crystal like calcite or quartz, it splits into two rays:
- Ordinary (o) ray: obeys Snell's law, has speed v_o in all directions, vibrates perpendicular to the principal section.
- Extraordinary (e) ray: does not obey Snell's law, speed varies with direction, vibrates in the principal section.
Both are plane polarized with mutually perpendicular vibrations. Along the optic axis both travel with the same speed. (Huygens: o gives spherical, e gives ellipsoidal wavefront.)
Production of polarized light
plane-polarized optic axis (OA)
light, amplitude A |
-------->[ crystal plate, thickness t ]--> E and O rays
angle θ between vibration and OA
- Plane polarized light of amplitude A falls normally on a plate cut parallel to the optic axis, vibrating at angle θ to it.
- It splits into e-component (along axis) a = A cos θ and o-component (perpendicular) b = A sin θ; they travel with different speeds.
- On emerging, path difference = (μ_o − μ_e) t, so phase difference δ = (2π/λ)(μ_o − μ_e) t.
- Take x = a cos ωt, y = b cos(ωt + δ). Eliminating t:
x²/a² + y²/b² − (2xy/ab) cos δ = sin²δ
- Special cases:
| Condition | Result |
|---|---|
| δ = 0 or π (path diff 0, λ/2) | y = ±(b/a)x : linear |
| δ = π/2 (quarter-wave plate), a ≠ b | x²/a² + y²/b² = 1 : elliptical |
| δ = π/2 and a = b (θ = 45°) | x² + y² = a² : circular |
| other δ | tilted ellipse (elliptical) |
Thus a quarter-wave plate with θ = 45° gives circular light, with the thickness t = λ/[4(μ_o − μ_e)].
✓ Answer checked by Claude Opus 5.5 (high effort)
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