- Asked 4/16
- 2073 Shrawan · 5 marks
- 2072 Chaitra · 5 marks
- 2071 Chaitra · 5 marks
- 2067 Asar · 5 marks
Poynting vector, S = E×B/μ0
Short answer
The Poynting vector S = (E×B)/μ₀ is the electromagnetic energy flux (W/m²). Using Maxwell's equations, one obtains ∇·S = −∂u/∂t − E·J, which is the energy conservation law.
Define Poynting vector. Prove that S = (E × B)/μ0, where the symbols have their usual meanings.
Definition
The Poynting vector S is the rate of flow of electromagnetic energy per unit area, in the direction of propagation of the wave. Its unit is W/m². It is given by S = E × H = (E × B)/μ₀.
Proof
We use energy conservation with Maxwell's equations (in vacuum, in a region with current density J):
∇×E = −∂B/∂t and ∇×B = μ₀J + μ₀ε₀ ∂E/∂t.
-
Use the vector identity ∇·(E×B) = B·(∇×E) − E·(∇×B).
-
Substitute: ∇·(E×B) = −B·∂B/∂t − E·[μ₀J + μ₀ε₀ ∂E/∂t].
-
Divide by μ₀:
∇·(E×B)/μ₀ = −(1/μ₀) B·∂B/∂t − ε₀ E·∂E/∂t − E·J
-
Note B·∂B/∂t = ½ ∂(B²)/∂t and E·∂E/∂t = ½ ∂(E²)/∂t. So
∇·[(E×B)/μ₀] = −∂/∂t [ε₀E²/2 + B²/(2μ₀)] − E·J
-
The bracket is the energy density u = u_E + u_B. E·J is the power given to the charges per unit volume. Define S = (E × B)/μ₀:
∇·S = −∂u/∂t − E·J
-
Integrate over a volume and use the divergence theorem: ∮S·dA = −d/dt ∫u dV − ∫E·J dV.
The left side is the energy flowing out through the surface per second. The right side is the decrease in stored field energy minus the work done on the charges per second. So S·dA is the power crossing dA, and S = (E×B)/μ₀ is the energy flux, pointing along E × B (the direction of travel).
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Derive numerical aperture of optical fiber · Engineering Physics, chapter 6 · asked 4×
- Atomic view of resistivity, ρ = m/ne²τ · Engineering Physics, chapter 8
- State and prove Poynting's theorem · Electromagnetism, chapter 4 · asked 2×
- Prove shear stirrup spacing or Ld formula · Design of RCC Structure, chapter 6
- Condition for constant direction of vector · Mathematics, chapter 5 · asked 6×
- Condition for constant magnitude of vector · Mathematics, chapter 5 · asked 5×