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J = σE, resistivity and superconductors

Short answer

From drift velocity v_d=eτE/m, current density J=ne v_d gives J=(ne²τ/m)E=σE. Resistivity ρ=1/σ rises with temperature because stronger lattice vibrations reduce relaxation time τ. Superconductors have zero resistance below T_c and exhibit the Meissner effect (perfect diamagnetism), unlike a perfect conductor that retains flux. Key characteristics: zero resistance, Meissner effect, critical field and current.

Derive an equation J = σE. Explain why resistivity of a conductor increases with increasing temperature; plot a graph between Rθ (resistance at any temperature θ) and temperature. Based on the graph, explain what are superconductors? How do they differ from perfect conductor? Describe the characteristics of superconductors.

Derivation of J = σE

Let n be the free-electron density and τ the average time between collisions.

  1. Acceleration: a = eE/m.
  2. Drift velocity: v_d = aτ = eτE/m.
  3. J = n e v_d = (ne²τ/m) E.
  4. Writing σ = ne²τ/m (conductivity), J = σE. The resistivity is ρ = 1/σ = m/(ne²τ).

Why resistivity rises with temperature

When temperature increases, the lattice ions vibrate more strongly. Electrons collide more often, so τ decreases. Since ρ = m/(ne²τ), ρ increases. For a metal, n stays almost constant. Near room temperature:

ρ = ρ₀[1 + α(θ − θ₀)], and R_θ = R₀(1 + αθ).

Graph of R_θ against temperature

 R
 |                              /  normal metal
 |                           /
 |                        /
 |                    _ /
 |   ____________ --          <- residual resistance at 0 K
 |
 |                        /  superconductor
 |                     /
 |            |------/
 |            |
 +------------+------------------> T
 0            Tc

For a normal metal, R falls steadily as T is lowered and levels off at a small residual value at 0 K. For a superconductor, R drops abruptly to zero at the critical temperature T_c and stays zero below it.

Superconductors

A superconductor is a material whose resistance falls to exactly zero below T_c (e.g. Hg 4.2 K, Nb 9.3 K, YBCO ~92 K).

Difference from a perfect conductor: a perfect conductor (ρ = 0) only keeps the magnetic flux it already has, so its state depends on history. A superconductor also shows the Meissner effect: it expels magnetic flux (B = 0 inside) whatever the order of cooling and field application. It is a perfect diamagnet (χ = −1).

Characteristics

  1. Zero electrical resistance below T_c, so a persistent current flows without loss.
  2. Meissner effect: perfect diamagnetism.
  3. Critical field H_c(T) = H₀[1 − (T/T_c)²]; above it superconductivity is destroyed.
  4. Critical current density: a large enough current also destroys it.
  5. Type I (sharp transition) and Type II (mixed state between H_c1 and H_c2).
  6. Uses: MRI magnets, maglev, SQUIDs, power cables.

✓ Answer checked by Claude Opus 5.5 (high effort)

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