- 2068 Chaitra · 5 marks
Time independent Schrödinger equation; barrier
Short answer
Starting from d²ψ/dx² + k²ψ=0 with k=p/ħ and p²=2m(E−V) yields the time-independent equation d²ψ/dx² + (2m/ħ²)(E−V)ψ=0. A potential barrier is a region where V₀ > E; classically the particle is reflected, but quantum mechanically it can tunnel through with probability T ≈ e^{-2κa}.
Derive the Schrödinger time independent wave equation. Also what do you mean by a potential barrier?
Derivation of the time-independent Schrödinger equation
- A matter wave travelling along x with wave function ψ(x) satisfies a wave equation of the form d²ψ/dx² + k²ψ = 0, where k = 2π/λ.
- de Broglie: λ = h/p, so k = p/ħ and k² = p²/ħ².
- For a particle of total energy E in potential V(x), the kinetic energy is p²/2m = E − V, so p² = 2m(E − V).
- Substitute:
d²ψ/dx² + (2m/ħ²)(E − V)ψ = 0
or −(ħ²/2m) d²ψ/dx² + Vψ = Eψ. 5. In three dimensions: ∇²ψ + (2m/ħ²)(E − V)ψ = 0, that is, Ĥψ = Eψ.
(The same equation follows from the time-dependent equation iħ∂Ψ/∂t = −(ħ²/2m)∂²Ψ/∂x² + VΨ by writing Ψ = ψ(x)e^{−iEt/ħ}.)
Here |ψ|² is the probability density, and ψ must be finite, single-valued and continuous.
Potential barrier
A potential barrier is a region of space where the potential energy V₀ is greater than the total energy E of the particle.
V
V0 | ______
| | |
E |-----| |----- incident particle
| | |
+-----0------a-----> x
I II III
- Classically, the particle cannot enter or cross the barrier (it is reflected).
- Quantum mechanically, inside the barrier the solution is exponential, ψ ∝ e^{−κx} with κ = √(2m(V₀ − E))/ħ, so the particle has a non-zero chance to get through to region III. This is tunnelling, with transmission probability T ≈ e^{−2κa}.
Tunnelling explains alpha decay, the tunnel diode and the scanning tunnelling microscope.
✓ Answer checked by Claude Opus 5.5 (high effort)
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