- 2074 Asoj · 5 marks
Energy of SHM, total energy constant
Short answer
SHM is periodic motion with restoring force proportional to displacement (F=-kx). Kinetic energy = ½mω²a²cos²(ωt+φ), potential energy = ½mω²a²sin²(ωt+φ). Sum is constant total energy E = ½mω²a² = ½k a². KE and PE oscillate out of phase, each varying between 0 and maximum, but total remains invariant.
Define SHM. Derive the expression for energy of SHM. Show that the KE and PE of a simple harmonically oscillating object change with time however the total energy is invariant.
Simple harmonic motion (SHM) is periodic motion of a particle in which the restoring force (or acceleration) is proportional to the displacement from the equilibrium position and is directed towards it: F = −kx.
Equation and solution
m d²x/dt² = −kx gives x = a sin(ωt + φ), with ω = √(k/m), a = amplitude. Then v = dx/dt = aω cos(ωt + φ).
Potential energy
Work done against the restoring force to displace by x:
PE = ∫₀ˣ kx dx = ½ k x² = ½ m ω² a² sin²(ωt + φ)
Kinetic energy
KE = ½ m v² = ½ m ω² a² cos²(ωt + φ) = ½ m ω² (a² − x²)
Total energy
E = KE + PE = ½ m ω² a² [cos²(ωt + φ) + sin²(ωt + φ)]
E = ½ m ω² a² = ½ k a²
This does not depend on time t.
Variation with time
- KE and PE both vary with time between 0 and ½mω²a², with frequency 2ω (twice that of the motion).
- At the mean position (x = 0): PE = 0, KE = ½mω²a² (maximum).
- At extreme positions (x = ±a): KE = 0, PE = ½mω²a² (maximum).
- When KE falls, PE rises by exactly the same amount.
E |------------------------- total E
| \ /\ /\
| \ / \ / KE and PE are
| \/ \/ out of phase
|__________________ t
So KE and PE change with time, but their sum ½ka² stays constant; no energy is lost in ideal SHM.
✓ Answer checked by Claude Opus 5.5 (high effort)
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