- 2081 Chaitra (new course) · 4 marks
Summing amplifier using op-amp
Short answer
The inverting summing amplifier uses virtual ground at the op‑amp input. Input currents sum, flowing through Rf: Vo = –Rf (V1/R1 + V2/R2 + V3/R3). Equal resistors give Vo = –(V1+V2+V3).
Derive the expression of summing amplifier using OP amp.
A summing amplifier (adder) is an op-amp circuit whose output is proportional to the (weighted) sum of several input voltages. The common form is the inverting summing amplifier.
Circuit
V1 o--[R1]--+
| Rf
V2 o--[R2]--+-----/\/\/\-----+
| |
V3 o--[R3]--+ |\ |
+---|-\ |
V− | >---------+--o Vo
GND --|+/
|/
Assumptions (ideal op-amp)
- V+ = 0 (grounded), and because of the virtual short V− = V+ = 0 (virtual ground).
- No current enters the op-amp input.
Derivation
Input currents:
I1 = (V1 − 0)/R1 = V1/R1
I2 = V2/R2
I3 = V3/R3
No current enters the (−) terminal, so by KCL all these currents flow through Rf:
If = I1 + I2 + I3
The output voltage, with the inverting node at 0 V:
0 − Vo = If × Rf
Vo = −Rf (V1/R1 + V2/R2 + V3/R3)
Special cases
- Equal resistors R1 = R2 = R3 = Rf = R: Vo = −(V1 + V2 + V3) (inverting adder).
- R1 = R2 = R3 = R, Rf = R/3: Vo = −(V1 + V2 + V3)/3 (averaging amplifier).
- Unequal resistors give a scaling (weighted) summer, Vo = −(a1V1 + a2V2 + a3V3) with ai = Rf/Ri.
Example: V1 = 1 V, V2 = 2 V, V3 = −0.5 V with all resistors 10 kΩ: Vo = −(1 + 2 − 0.5) = −2.5 V.
Because the inverting node is a virtual ground, the inputs do not interact with each other. Uses: audio mixers, digital-to-analog converters (weighted resistors), and adding a DC offset to a signal. A second inverting amplifier of gain −1 can be added to get a non-inverted sum.
✓ Answer checked by Claude Opus 5.5 (high effort)
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