- 2069 Asar
Volume of ellipsoid by revolving an ellipse
Short answer
Revolve about x-axis: V = 4πab²/3 cubic units. Revolve about y-axis: V = 4πa²b/3 cubic units, using V = π∫ y² dx or π∫ x² dy respectively.
Find the volume of the ellipsoid formed by the revolution of an ellipse x²/a² + y²/b² = 1.
Ellipse: x²/a² + y²/b² = 1. Revolving it about an axis gives an ellipsoid of revolution (a spheroid).
About the x-axis (prolate spheroid when a > b)
The solid is symmetrical about the y-axis, so V = π ∫_(−a)^a y² dx = 2π ∫₀^a y² dx, with y² = b²(1 − x²/a²):
V = 2π b² ∫₀^a (1 − x²/a²) dx
= 2π b² [x − x³/(3a²)]₀^a
= 2π b² (a − a/3)
V = 4πab²/3.
About the y-axis (oblate spheroid when a > b)
Similarly V = 2π a² ∫₀^b (1 − y²/b²) dy = 2πa² (b − b/3), so
V = 4πa²b/3.
For a sphere (a = b = r) both give 4πr³/3, as expected.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Volume by revolving ellipse about x=2a · Mathematics I, chapter 2
- Volume of cardioid r=a(1+cosθ) about initial line · Mathematics I, chapter 2 · asked 6×
- Volume of ellipsoid by triple integration · Mathematics, chapter 2